Tính giá trị biểu thức
1)A=1-3+5-7+.....+2019-2021+2023
2)B=1-2-3+4+5-6-7+8+....+1993-1994
A=1-3+5-7+...+2019-2021+2023
B=1-2-3+4+5-6-7+8+...+1993-1994
A=1-3+5-7+...+2019-2021+2023
A = 1 + 5 + .. .+ 2019 + 2023 - 3 - 7 - ... - 2017 - 2021
A = ( 1 + 5 + ... + 2023 ) - ( 3 + 7 + ... + 2021 )
A = 512578
tính giá trị biểu thức
1/2x3/4:6/5 2/3+1/6:7/12 8x3/5:12/5 4/9+3/4-1/3
a: \(=\dfrac{1}{2}\cdot\dfrac{3}{4}\cdot\dfrac{5}{6}=\dfrac{15}{48}=\dfrac{5}{16}\)
b: \(=\dfrac{2}{3}+\dfrac{12}{42}=\dfrac{2}{3}+\dfrac{2}{7}=\dfrac{20}{21}\)
c: \(=\dfrac{24}{5}\cdot\dfrac{5}{12}=2\)
d: \(=\dfrac{1}{9}+\dfrac{3}{4}=\dfrac{4+27}{36}=\dfrac{31}{36}\)
Tính các tổng sau
a) A = 1 – 3 + 5 – 7 + … + 2001 – 2003 + 2005. b) B = 1 – 2 – 3 + 4 + 5 – 6 - 7 + 8 + …+ 1993 – 1994.
Lời giải:
a.
$A=(1-3)+(5-7)+(9-11)+...+(2001-2003)+2005$
$=(-2)+(-2)+(-2)+...+(-2)+2005$
$=(-2).501+2005=-1002+2005=1003$
b.
$B=(1-2-3+4)+(5-6-7+8)+...+(1989-1990-1991+1992)+(1993-1994)$
$=0+0+....+0+(1993-1994)=0+(-1)=-1$
Tính:
a) 1-3+5-7+...+2001-2003+2005
b) 1-2-3+4+5-6-7+8+...+1993-1994
Câu 30. Giá trị của tổng
S =1+ 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 +10 -... + 2018 - 2019 - 2020 + 2021 là
A. 2020 . B. 2021. C. 1. D. -1.
tính giá trị biểu thức
1/2x3/4:6/5 2/3+1/6:7/12 8x3/5:12/5 4/9+3/4-1/3
2 bn lm xong trước mk tick
1: \(=\dfrac{3}{8}\cdot\dfrac{5}{6}=\dfrac{15}{24}=\dfrac{5}{8}\)
2: \(=\dfrac{2}{3}+\dfrac{12}{42}=\dfrac{2}{3}+\dfrac{2}{7}=\dfrac{14+6}{21}=\dfrac{20}{21}\)
3: \(=\dfrac{24}{5}\cdot\dfrac{5}{12}=2\)
4: \(=\dfrac{1}{3}+\dfrac{3}{4}=\dfrac{4+9}{12}=\dfrac{13}{12}\)
`1/2xx3/4:6/5= 1/2 xx 3/4 xx 5/6 = 3/8 xx 5/6 =5/16`
`2/3+1/6:7/12 = 2/3 + 1/6 xx 12/7 = 2/3 + 2/7 = 14/21 + 6/21 = 20/21`
`8xx3/5:12/5= 8xx 3/5 xx 5/12 = 24/5 xx 5/12 = 2`
`4/9+3/4-1/3= (16/36 + 27/36 ) - 1/3 = 43/36 - 1/3 = 31/36`
`1/2xx3/4:6/5`
`=1/2xx3/4xx5/6`
`=3/8xx5/6`
`=15/48`
`=5/16`
__
`2/3+1/6:7/12`
`=2/3+1/6xx12/7`
`=2/3+2/7`
`=14/21+6/21`
`=20/21`
__
`8xx3/5:12/5`
`=8xx3/5xx5/12`
`=8xx1/4`
`=8/4`
`=2`
__
`4/9+3/4-1/3`
`=(4/9-1/3)+3/4`
`=(4/9-3/9)+3/4`
`=1/9+3/4`
`=4/36+27/36`
`=31/36`
Các bn giúp mk nha
Tính giá trị biểu thức sau
a) A=2*5^22-9*5^51/25^10 : 5*(3*7^15-19*7^14)/7^16+3/7^15
b) 8^5*16^3/4^13 - 3^33*4^15/6^32
c) C= 1994^(256-1^2)^(256-2^2)^....^(256-50^2)
So sánh các lũy thừa sau
A=(-2017)^2019 và B = ( - 2018)^2020
A=1-3+5-7+...+2001-2003+2005
B=1-2-3+4+5-6-7+8+...+1993-1994
C=1+2-3-4+5+6-7-8+9+...+2002-2003-2004+2005+2006
A=1-3+5-7+....+2001-2003+2005
A=[(1-3)+(5-7)+.....+(2001-2003)]+2005
A=[(-2)+(-2)+....+(-2)]+2005
Vì từ 1 đến 2003 có: 1002 số hạng => có 501 cặp => có 501 số -2
A=(-2) x 501 +2005
A=-1002+2005
A=1003
A=1-3+5-7+...+2001-2003+2005
A=(1-3)+(5-7)+....+(2001-2003)+2005
A=(-2)+(-2)+...+(-2)+2005
A=(-2).501+2005
A=(-1002)+2005
A=1003
B=1-2-3+4+5-6-7+8+...+1993-1994
B=(1-2-3+4)+(5-6-7+8)+....+(1989-1990-1991+1992)+(1993-1994)
B=0+0+...+0+(-1)
B=(-1)
C=1+2-3-4+5+6-7-8+9+...+2002-2003-2004+2005+2006
C=(1+2-3-4)+(5+6-7-8)+....+(2001+2002-2003-2004)+(2005+2006)
C=(-4)+(-4)+....+(-4)+4011
C=(-4).501+4011
C=(-2004)+4011
C=2007
A=1-3+5-7+...+2001-2003+2005
A= (-2) + (-2) +....+(-2) +2005
A= -2. 501 +2005
A= -1002 +2005
A= 1003
B=1-2-3+4+5-6-7+8+...+1993-1994
B= (1-2-3+4) + (5-6-7 +8) +.......+ (1989 - 1990 -1991 +1992)+1993-1994
B= 0 + 0+....+0+ 1993-1994
B= -1
C=1+2-3-4+5+6-7-8+9+...+2002-2003-2004+2005+2006
C= (1+2-3-4) + (5+6-7-8) +.....+(2001+2002 -2003 -2004) +2005+2006
C= -4. 501 + 2005 +2006
C= -2004+2005+2006
C= 2007
tính tổng B=1-2-3+4+5-6-7+8+...+1993-1994
C=1+2-3-4+5+6-7-8+9+...+2002-2003-2004+2005+2006