a)\(f\left(1\right)=2.1^2+5.1-3=2+5-3=4\)

\(f\left(0\right)=0+0-3=-3\)

\(f\left(1,5\right)=2.\left(1,5\right)^2-5.1,5-3=4,5-7,5-3=-6\)

b)\(f\left(3\right)=3a-3=9=>>3a=12=>a=4\)

\(f\left(5\right)=5a-3=11=>5a=14=>a=\dfrac{14}{5}\)

\(f\left(-1\right)=-a-3=6=>-a=9=>a=-9\)

`a)`

`@f(1)=2.1^2+5.1-3=2.1+5-3=2+5-3=4`

`@f(0)=2.0^2+5.0-3=-3`

`@f(1,5)=2.(1,5)^2+5.1,5-3=4,5+7,5-3=9`

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`b)`

`***f(3)=9`

`=>3a-3=9`

`=>3a=12=>a=4`

`***f(5)=11`

`=>5a-3=11`

`=>5a=14=>a=14/5`

`***f(-1)=6`

`=>-a-3=6`

`=>-a=9=>a=-9`

a: f(1)=2+5-3=4

f(0)=-3

f(1,5)=4,5+7,5-3=9

b: f(3)=9 nên 3a-3=9

hay a=4

f(5)=11 nên 5a-3=11

hay a=14/5

f(-1)=6 nên -a-3=6

=>-a=9

hay a=-9

a, Thay giá trị x = -1 và x = 3 vào hàm số ta thu đc kết quả lần lượt là: 

1/3 và -1.

b, x = 0 => y =0

   x = 3 => y = -1. 

Đồ thị thu đc là: 

a: f(-1)=4

f(2)=1

\(a,f\left(-1\right)=3-\left(-1\right)=4\\ f\left(2\right)=3-2=1\\ b,y=5\Rightarrow3-x=5\Rightarrow x=-2\\ y=2\Rightarrow3-x=2\Rightarrow x=1\\ y=-1\Rightarrow3-x=-1\Rightarrow x=4\)

a: f(-2)=3-(-2)=3+2=5

f(-1)=3-(-1)=4

b: y=5 thì 3-x=5

hay x=-2

a,f[-2]=3-[-2]=5

   f[-1]=3-[-1]=4

b,y=f[x]=3-x

  =>5=3-x

  =>x=3-5

  =>x=-2

Ta có: \(y=f\left(x\right)=3-x\)

a) \(f\left(-2\right)\Rightarrow3-\left(-2\right)=5\)

\(f\left(-1\right)\Rightarrow3-\left(-1\right)=4\)

b) \(y=5\Rightarrow3-x=5\Rightarrow x=-2\)

a: f(-2)=6

f(3)=-9

\(f\left(x\right)=2x^2+5x-3\)

f(1)=2+5-3=4

f(0)=-3

f(1,5)=2x2,25+5x1,5-3=9

\(f\left(x\right)=2x^2+5x-3\)

\(f\left(1\right)=2.1^2+5.1-3=2+5-3=4\)

\(f\left(0\right)=-3\)

\(f\left(1,5\right)-2.\left(1,5\right)^2+5.1,5-3=9\)

f(x) = 2x² + 5x -3

f(1) = 2.1² + 5.1 - 3 = 2.1 + 5.1 - 3 = 4

f(0) = 2.0² + 5.0 - 3 = -3

f(1,5) = 2 . 1,5² + 5 . 1,5 - 3 = 9