1-3-5+7+9-11-13+15+...+2017-2019-2021+2023=

=(1-3-5+7)+(9-11-13+15)+...+(2017-2019-2021+2023)=
=0+0+.....+0=0

=2019

= 0

a, \(\dfrac{90}{37}-\dfrac{38}{25}-\dfrac{8}{25}-\dfrac{4}{25}\)

= \(\dfrac{90}{37}\) - \(\dfrac{38+8+4}{25}\)

= \(\dfrac{90}{37}\) - 2

= \(\dfrac{16}{37}\)

\(\dfrac{24}{29}\) + \(\dfrac{32}{41}\) + \(\dfrac{34}{29}\) + \(\dfrac{50}{41}\)

=(\(\dfrac{24}{29}\) + \(\dfrac{34}{29}\)) + (\(\dfrac{32}{41}\) + \(\dfrac{50}{41}\))

= \(\dfrac{58}{29}\) + \(\dfrac{82}{41}\)

= 2 + 2

= 4

c, \(\dfrac{73}{24}\) - \(\dfrac{22}{29}\) - \(\dfrac{25}{24}\) + \(\dfrac{51}{29}\)

= ( \(\dfrac{73}{24}\) - \(\dfrac{25}{24}\)) +( \(\dfrac{51}{29}\) - \(\dfrac{22}{29}\))

= \(\dfrac{48}{24}\) + \(\dfrac{29}{29}\)

= 2 + 1

= 3

giải nhanh và đầy đủ giúp mình nha

       \(\frac{25}{26}\times\frac{26}{27}\times\frac{27}{28}\times\frac{28}{29}\times\frac{29}{30}\)

\(=\frac{25\times26\times27\times28\times29}{26\times27\times28\times29\times30}\)

\(=\frac{25}{30}\)

\(=\frac{5}{6}\)

BÀI NÀY TÍNH BẰNG CÁCH LOẠI BỎ NHỮNG SỐ GIỐNG NHAU Ở TRÊN TỬ VÀ DƯỚI MẪU 

\(\frac{25}{26}\times\frac{26}{27}\times\frac{27}{28}\times\frac{28}{29}\times\frac{29}{30}\)

\(=\frac{25}{30}\)

\(=\frac{5}{6}\)

96 x 24 + 192 x 25 + 288 x 9 - 96

= 96 × 24 + 96 × 2 × 25 + 96 × 3 × 9 - 96 × 1

= 96 × 24 + 96 × 50 + 96 × 27 - 96 ×1

= 96 × (24 + 50 + 27 -1)

= 96 × 100

= 9600

a: \(\dfrac{-11}{18}+\dfrac{12}{29}+\dfrac{-7}{18}+\dfrac{2020}{2021}+\dfrac{17}{29}\)

=(-11/18-7/18)+(12/29+17/29)+2020/2021

=2020/2021

b: \(\dfrac{-2}{3}\cdot\dfrac{4}{9}+\dfrac{5}{9}\cdot\dfrac{-2}{3}+\dfrac{4}{3}\)

=-2/3+4/3=2/3

a,\(\frac{1}{5}\times\frac{2}{9}\div\frac{1}{15}\)

\(=\frac{1}{5}\times\frac{2}{9}\times15\)

\(=\left(\frac{1}{5}\times15\right)\times\frac{2}{9}\)

\(=3\times\frac{2}{9}\)

\(=\frac{2}{3}\)

b\(\frac{4}{15}\times\frac{7}{15}\times\frac{5}{4}\)

\(=\left(\frac{4}{15}\times\frac{5}{4}\right)\times\frac{7}{15}\)

\(=\frac{1}{3}\times\frac{7}{15}\)

\(=\frac{7}{45}\)

c,\(\frac{21}{23}\times\frac{5}{11}\times\frac{44}{?}\)

d,\(26\times\frac{13}{42}\div13\)

\(=\left(26\div13\right)\times\frac{13}{42}\)

\(=2\times\frac{13}{42}\)

\(=\frac{13}{21}\)

ờ ờ .......................... hong bt

21/23 x 5/11x 44/35

Lời giải:

a. $=-(37+63)+[25+(-25)]+(-9)=-100+0+(-9)=-(100+9)=-109$

b. $=[1+(-3)]+[5+(-7)]+....+[21+(-23)]$

$=\underbrace{(-2)+(-2)+....+(-2)}_{6}=(-2).6=-12$

c. $=-(280+20)+[-(79+21)]=-300+(-100)=-(300+100)=-400$

d. $=[-(27+43)]+[-(208+102)]=-70+(-310)=-(70+310)=-380$

e. $=(38+120)-(12+46)=158-58=100$

f. $=9+15+11+24=(9+11)+(15+24)=20+39=59$

\(=\left(-\dfrac{1}{6}-\dfrac{5}{6}\right)+\left(\dfrac{25}{9}+\dfrac{2}{9}\right)=-1+3=2\)

Câu 6: Tính bằng cách hợp lí:

 25/9 - 1/6 + 4/18 -5/6 = (25/9+4/18)+(-1/6-5/6)

                                   =3-1

                                  =2

\(=\dfrac{25}{9}-\dfrac{1}{6}-\dfrac{2}{9}-\dfrac{5}{6}\\ =\left(\dfrac{25}{9}-\dfrac{2}{9}\right)+\left(\dfrac{5}{6}-\dfrac{1}{6}\right)\\ =\dfrac{23}{9}+\dfrac{2}{3}\\ =\dfrac{23+6}{9}=\dfrac{29}{9}\)

25/29 và 21/33

25/29=25X33/29x33=825/957

21/33=21x29/33x29=609/957

825/957>609/957

nên 25/29>21/33