tính: \(\frac{\sqrt{3^2}-\sqrt{39^2}}{\sqrt{7^2}-\sqrt{91^2}}\)
TÍNH BÀI TOÁN SAU
\(\frac{\sqrt{3^2}-\sqrt{39^2}}{\sqrt{7^2}-\sqrt{91^2}}\)
Tính:
\(\frac{\sqrt{3^2}-\sqrt{39^2}}{\sqrt{7^2}-\sqrt{91^2}}\)
\(\frac{\sqrt{3^2}-\sqrt{39^2}}{\sqrt{7^2}-\sqrt{91^2}}=\frac{3-39}{7-91}=\frac{-36}{-84}=\frac{3}{7}\)
Happy memories -_- là \(\sqrt{7^2}-\sqrt{91^2}\)thành \(\sqrt{7^2-\sqrt{91^2}}\) chứ
tính giá trị biểu thức: \(\frac{\sqrt{3^2}+\sqrt{39^2}}{\sqrt{7^2}+91^2}=\)
\(\frac{\sqrt{3^2}+\sqrt{39^2}}{\sqrt{7^2}+\sqrt{91^2}}=\frac{3+39}{7+91}=\frac{42}{98}\)= \(\frac{3}{7}\)
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rút gọn \(\frac{\sqrt{3^2}+\sqrt{39^2}}{\sqrt{7^2}+\sqrt{91^2}}\)
tính
a) \(\sqrt{\dfrac{3^2}{7^2}}\) b) \(\dfrac{\sqrt{3}^2+\sqrt{39}^2}{\sqrt{7}^2+\sqrt{91}^2}\) c) \(\dfrac{\sqrt{3}^2-\sqrt{39}^2}{\sqrt{7}^2-\sqrt{91}^2}\) d) \(\sqrt{\dfrac{39^2}{91^2}}\)
a)\(\sqrt{\dfrac{3^2}{7^2}}=\sqrt{\dfrac{9}{49}}=\sqrt{\dfrac{3}{7}}\)
b)\(\dfrac{\sqrt{3^2}+\sqrt{39^2}}{\sqrt{7^2}+\sqrt{91^2}}=\dfrac{\sqrt{9}+\sqrt{1521}}{\sqrt{49}+\sqrt{8281}}=\dfrac{3+39}{7+91}=\dfrac{42}{98}\)
c)Tương tự câu b, ta đc:
\(\dfrac{\sqrt{3^2}-\sqrt{39^2}}{\sqrt{7^2}-\sqrt{91^2}}=\dfrac{3-39}{7-91}=\dfrac{-36}{86}=\dfrac{3}{7}\)
d)Tương tự câu a, ta đc:
\(\dfrac{\sqrt{39^2}}{\sqrt{91^2}}=\dfrac{39}{91}\)
Chúc Bạn Học Tốt!!!
a) \(\sqrt{\dfrac{3^2}{7^2}}=\sqrt{\left(\dfrac{3}{7}\right)^2}=\left|\dfrac{3}{7}\right|=\dfrac{3}{7}\)
b) \(\dfrac{\sqrt{3}^2+\sqrt{39}^2}{\sqrt{7}^2+\sqrt{91}^2}=\dfrac{\left|3\right|+\left|39\right|}{\left|7\right|+\left|91\right|}=\dfrac{3+39}{7+91}=\dfrac{42}{98}=\dfrac{3}{7}\)
c) \(\dfrac{\sqrt{3}^2-\sqrt{39}^2}{\sqrt{7}^2-\sqrt{91}^2}=\dfrac{\left|3\right|- \left|39\right|}{\left|7\right|-\left|91\right|}=\dfrac{3-39}{7-91}=\dfrac{-36}{-84}=\dfrac{3}{7}\)
d) \(\sqrt{\dfrac{39^2}{91^2}}=\sqrt{\left(\dfrac{39}{91}\right)^2}=\left|\dfrac{39}{91}\right|=\dfrac{39}{91}=\dfrac{3}{7}\)
\(\frac{\sqrt{3^2}-\sqrt{39^2}}{\sqrt{7^2}-\sqrt{91^2}}\)
\(=\frac{3-39}{7-91}=\frac{-36}{-84}=\frac{3}{7}\)
Inh gia tri cua bieu thuc sau
\(\frac{^{\sqrt{3^2}}-\sqrt{39^2}}{\sqrt{7^2}-\sqrt{91^2}}\)
\(\frac{\sqrt{3^2}-\sqrt{39^2}}{\sqrt{7^2}-\sqrt{91^2}}=\frac{3-39}{7-91}=\frac{-36}{-84}\)
\(=\frac{3}{7}\)
Trong các số sau, số nào bằng \(\dfrac{3}{7}\) ?
\(a=\dfrac{39}{91}\) \(b=\sqrt{\dfrac{3^2}{7^2}}\) \(c=\dfrac{\sqrt{3^2}+\sqrt{39^2}}{\sqrt{7^2}+\sqrt{91^2}}\) \(d=\dfrac{\sqrt{3^2}-\sqrt{39^2}}{\sqrt{7^2}-\sqrt{91^2}}\)
Các số bằng \(\dfrac{3}{7}\) là a ; b ; c ; d
tìm x biết
a, \(\sqrt{\left(2,5+0,7\right)^2}\)
b, \(\frac{\sqrt{3^2}+\sqrt{39^2}}{\sqrt{7^2}+\sqrt{91^2}}\)
mọi người giúp minh nha, cảm ơn
a) \(\sqrt{\left(2,5+0,7\right)^2}=\left(2,5+0,7\right)=3,2\)
b) \(\frac{\sqrt{3^2}+\sqrt{39^2}}{\sqrt{7^2}+\sqrt{91^2}}=\frac{3+39}{7+91}=\frac{42}{98}=\frac{3}{7}\)
Ko có x nha bạn