Ta có:

67 - [ 8 + 7 . 3² - 24 : 6 + ( 9 - 7 )³ ] : 15 

= 67 - (8 + 7.9 - 4 + 8) : 15

= 67 - 75 : 15

= 67 - 5

= 62

\(67-\left[8+7.3^2-24:6+\left(9-7\right)^3\right]:15\\ =67-\left[8+7.9-4+2^3\right]:15\\ =67-\left[8+63-4+8\right]:15\\ =67-75:15\\ =67-5=62\)

cảm ơn bạn Nguyễn Hòang tùng nhé

`a,`

`31/23-(7/32+8/23)`

`=31/23-7/32-8/23`

`=(31/23-8/23)-7/32`

`=1-7/32=25/32`

`b,`

`38/45-(8/45-17/51-3/11)`

`=38/45-8/45+17/51+3/11`

`= (38/45-8/45)+17/51+3/11`

`=2/3+17/51+3/11`

`=1+3/11=14/11`

`c,`

`(1/3+12/67+13/41)-(79/67-28/41)`

`= 1/3+12/67+13/41-79/67+28/41`

`= 1/3+(12/67-79/67)+(13/41+28/41)`

`= 1/3+(-1)+1=1/3+(-1+1)=1/3+0=1/3`

`d,`

`1/5+(-1/6)+1/7+(-1/8)+1/9+1/8+(-1/7)+1/6+(-1/5)`

`= (1/5+ -1/5)+(-1/6+1/6)+(1/7+ -1/7)+(-1/8 +1/8)+1/9`

`= 0+0+0+0+1/9=1/9 .`

67-[8+7.\(3^2\)-24:6+\(\left(9-7\right)^3\)]:15

=67-[8+63-4+8]:15

=67-75:15

=67-5

=62

67 -[ 8 + 7 x 3² - 24: 6 + (9 - 7 )³] :15

= 67 -[ 8 + 7 . 3² - 24 : 6 + 2³ ] : 15

= 67 - [ 8 + 7 . 9 - 24 : 6 + 8 ] : 15

= 67 - [ 71 - 12 ] : 15

= 67 - 59 : 15

= 8 : 15

=> ko thực hiện đc .

67-[8+7.3²-24:6+(9-7)³]:15

=67-[8+7.9-24:6+8]:15

=67-[8+63-4+8]:15

=67-75:15

=67-5

=62

a, 1+2+3+4+5+6+7+8+9+...+100

Tổng dãy số trên là :

\(\frac{100.\left(100+1\right)}{2}=5050\)

b, 23+54+32+67+100x0

= 23 + 54 + 32 + 67

= ( 23 + 67 ) + ( 54 + 32 )

= 90 + 86

= 176

Study well 

a, ko ghi đề

=(100+1)+(99+2)+...+(50+51) ( có 50 cặp )

=(101) x 50

=5050

b,ko ghi đề nốt

=(23+54+32+67)+0

=176

Nhớ k đúng mk nha ^^

a) 1 + 2 + 3 + 4 +...+ 100 có: ( 100 - 1 ) : 1 + 1 = 100 ( số hạng )

=> 1 + 2 + 3 + 4 +...+ 100 = ( 100 + 1 ) x 100 : 2 = 5050.

b) 23 + 54 + 32 + 67 + 100 x 0

= 23 + 54 + 32 + 67 

= ( 23 + 67 ) + 54 + 32

= 90 + 54 + 32

= 144 + 32

= 176

=???

ok chị

cái nịt

= 83,00000108