\(\left|x\right|-\left|-5,25\right|=\left|10,75\right|\)

\(\left|x\right|-5,25=10,75\)

\(\left|x\right|=10,75+5,25\)

\(\left|x\right|=16\)

Vậy \(x=16\)

|x|-|-5,25|=|10,75|

 <=>|x|-5,25=10,75

<=>|x|        =10,75+5,25

<=>|x|        =16

x đc chia làm 2 trường hợp

x=16 và x=-16

Vậy x=16 hoặc x=-16

#Chúc bạn hok tốt

Cho mình sửa lại đoạn cuối: 

Vậy \(x=-16\)hoặc \(x=16\)

giúp j :v 

đou cj

?

              đây nha

Tra mạng thấy cx đẹp

  đc hong ?

ta có :

\(3^{x+1}-3^x=3^x.3-3^x=2.3^x=162\)

\(\Leftrightarrow3^x=81=3^4\Leftrightarrow x=4\)

304,548

56,901

1281,25

ra đáp án tri tiết giúp mik nhé

37,14 x 8,2 = 304,548

8,754 x 6,5 = 56,901

625 x 2,05 = 1281,25

a. 2904,02-152,36-547,64

= 2904,02- (152,36+547,64)

= 2904,02- 700

= 2204.02

b. 38,25- 18,25+ 21,64-11,64

= 20+ 10

=30

c. 513,76- 62,8+49,04

= (513,76+49,04) -62,8

=562,8-62,8

=500

Đây nè bài này dễ lắm ý=))

a,2204,02

b,30

c,500

\(\sqrt{20}-\sqrt{45}+\sqrt{6+2\sqrt{5}}=\sqrt{2^2.5}-\sqrt{3^2.5}+\sqrt{\left(\sqrt{5}+1\right)^2}=2\sqrt{5}-3\sqrt{5}+\sqrt{5}+1=1\)

\(\sqrt{20}-2-\sqrt{\left(\sqrt{5}-2\right)^2}=2\sqrt{5}-2-\left|\sqrt{5}-2\right|=2\sqrt{5}-2-\sqrt{5}+2=\sqrt{5}\)

\(\left(\sqrt{27}+3\sqrt{12}-2\sqrt{3}\right):\sqrt{3}=\left(3\sqrt{3}+6\sqrt{3}-2\sqrt{3}\right):\sqrt{3}=7\sqrt{3}:\sqrt{3}=7\)

\(\sqrt{50}-3\sqrt{8}+\sqrt{\left(\sqrt{2}+1\right)^2}=\sqrt{5^2.2}-3\sqrt{2^2.2}+\sqrt{\left(\sqrt{2}+1\right)^2}=5\sqrt{2}-6\sqrt{2}+\sqrt{2}+1=1\)

1) \(A=\sqrt{20}-\sqrt{45}+\sqrt{6+2\sqrt{5}}\)

\(=2\sqrt{5}-3\sqrt{5}+\sqrt{5}+1\)

=1

2) Ta có: \(B=\sqrt{20}-2-\sqrt{\left(\sqrt{5}-2\right)^2}\)

\(=2\sqrt{5}-2-\sqrt{5}+2\)

\(=\sqrt{5}\)

3) Ta có: \(\left(\sqrt{27}+3\sqrt{12}-2\sqrt{3}\right):\sqrt{3}\)

\(=\left(3\sqrt{3}+6\sqrt{3}-2\sqrt{3}\right):\sqrt{3}\)

=7

4) Ta có: \(\sqrt{50}-3\sqrt{8}+\sqrt{\left(\sqrt{2}+1\right)^2}\)

\(=5\sqrt{2}-6\sqrt{2}+\sqrt{2}+1\)

=1

a) \(\dfrac{2x}{3}\)+\(\dfrac{2x-1}{6}\)=4 - \(\dfrac{x}{3}\)

<=>\(\dfrac{2x}{3}\)+\(\dfrac{2x-1}{6}\) - 4+\(\dfrac{x}{3}\)=0

<=>\(\dfrac{2x.2+2x-1-4.6+x.2}{6}\)=0

=>4x-2x-24+2x=0

<=>4x-24=0

<=>4x=24

<=>x=6

Vậy x=6

b)\(\dfrac{x-1}{2}\)+\(\dfrac{x-1}{4}\)=1 - \(\dfrac{2\left(x-1\right)}{3}\)

<=>\(\dfrac{x-1}{2}\)+\(\dfrac{x-1}{4}\)-1+\(\dfrac{2\left(x-1\right)}{3}\)=0

<=>\(\dfrac{6.\left(x-1\right)+3\left(x-1\right)-1.12+4.2\left(x-1\right)}{12}\)=0

=>6x-6+3x-3-12+4x-4+2x-2=0

<=>15x-27=0

<=>15x=27

<=>x=\(\dfrac{9}{5}\)

Vậy x=\(\dfrac{9}{5}\)

d)\(\dfrac{7x}{8}\)-5(x-9)=20x+\(\dfrac{1,5}{6}\)

<=>\(\dfrac{7x}{8}\)-5(x-9)-20x-\(\dfrac{1,5}{6}\)=0

<=>\(\dfrac{3.7x-24.5\left(x-9\right)-20x.24-1,5.4}{24}\)=0

=>-478x+165=0

<=> - 478= - 165

<=> x=\(\dfrac{165}{487}\)

Vậy x =\(\dfrac{165}{487}\)