a: UCLN(48;72)=24

UC(48;72)={1;2;3;4;6;8;12;24}

b: UCLN(132;156)=12

UC(132;156)={1;2;3;4;6;12}

c: UCLN(225;270;360)=45

UC(225;270;360)={1;3;5;9;15;45}

d: UCLN(540;756;1512)=108

UC(540;756;1512)={1;2;3;4;6;9;12;18;27;36;54;108}

Phân tích thành tích các thừa số nguyên tố: \(225=3^2.5^2,60=2^2.3.5\)

\(ƯCLN\left(225,60\right)=3.5=15\)

\(ƯC\left(225,60\right)=Ư\left(15\right)=\left\{-15,-5,-3,-1,1,3,5,15\right\}\)

\(BCNN\left(225,60\right)=2^2.3^2.5^2=900\)

\(BC\left(225,60\right)=B\left(900\right)\)

Ta có:864=2⁵.3³

          504=2³.3².7

\(\RightarrowƯCLN\left(864,504\right)=2^3.3^2=72\)

\(\Rightarrow\)ƯC(864,504)=Ư(72)={1;2;3;4;6;12;18;24;36;72}

864=2⁵x3³

504=2³x3²x7

ƯCLN(864,504)=2³x3² =72

=> ƯC (864,504)= Ư(72)={1;2;3;4;6;;...}

k cho mình nhé

Ta co: 8 = 2³         

         10 = 2 .5

         12 = 3 . 2²

UCLN ( 8 ; 10 ;12 ) = 2

UC ( 8 ;10 ;12 ) = U ( 2 ) = { 1, 2 } 

8=2³

10=2.5

12=2².3

ƯCLN(8;10;12)=2

ƯC(8;10;12)=Ư(2)={1;2}

\(a,ƯC\left(30,45\right)=Ư\left(15\right)=\left\{1;3;5;15\right\}\\ b,ƯC\left(42,77\right)=Ư\left(7\right)=\left\{1;7\right\}\)

a) Ư(30) = {1; 2; 3; 5; 6; 10; 15; 30}

    Ư(45) = {1; 3; 5; 9; 15; 45}

Vậy ƯC(30, 45) = {1; 3; 5; 15}

b) Ư(42) = {1; 2; 3; 6; 7; 14; 21; 42}

    Ư(70) = {1; 2; 5; 7; 10; 14; 35; 70}

Vậy ƯC(42, 70) = {1; 2; 7; 14}.

Bài này dễ mà

a ) 48 và 72

48 = 2⁴.3

72 = 2³.3²

ƯCLN ( 48,72 ) = 2³.3 = 12

b ) 132 và 156

132 = 2².3.11

156 = 2².3.13

ƯCLN = 2².3 = 12

a, 48 = 2\(^4\) . 3

72 = 2\(^3\) . 3\(^2\)

ƯCLN(48;72) = 2\(^3\).3= 24

ƯC(48;72)=Ư(24)\(\in\)\(\left\{1;2;3;4;6;8;12;24\right\}\)

=> ƯC(48;72)\(\in\)\(\left\{1;2;3;4;6;8;12;24\right\}\)

b,132=2\(^2\).3.11

156=2\(^2\).3.13

ƯCLN(132;156)=2\(^2\).3=12

ƯC(132;156)=Ư(12)\(\in\)\(\left\{1;2;3;4;6;12\right\}\)

=>ƯC132;156)\(\in\)\(\left\{1;2;3;4;6;12\right\}\)

Ta có: 90 = 2.32.5

126 = 2.32.7

ƯCLN(90;126) = 2.32= 18

ƯC(90;126) ={1;2;3;6;9;18}