Bài làm

a) \(\frac{x}{7}-\frac{3}{7}+\frac{1}{2}=\frac{31}{140}\)

                        \(\frac{x}{7}=\frac{31}{140}-\frac{1}{2}+\frac{3}{7}\)

                        \(\frac{x}{7}=\frac{31}{140}-\frac{70}{140}+\frac{60}{140}\)

                         \(\frac{x}{7}=\frac{21}{140}\)

                          \(\frac{x}{7}=\frac{3}{20}\)

=> \(x.20=3.7\)

=> \(x=\frac{3.7}{20}\)

=> \(x=\frac{21}{20}\)

Vậy \(x=\frac{21}{20}\)

b) \(\frac{5}{12}+\frac{5}{x}-\frac{1}{8}=\frac{1}{2}\)

                             \(\frac{5}{x}=\frac{1}{2}+\frac{1}{8}-\frac{5}{12}\)

                             \(\frac{5}{x}=\frac{12}{24}+\frac{3}{24}-\frac{10}{24}\)

                             \(\frac{5}{x}=\frac{5}{24}\)

=> \(5.24=5.x\)

=> \(x=\frac{5.24}{5}\)

=> \(x=24\)

 Vậy \(x=24\)

# Học tốt #

\(x=\dfrac{7}{25}+\dfrac{-1}{5}=\dfrac{7}{25}-\dfrac{1}{5}=\dfrac{2}{25}.\\ x=\dfrac{5}{11}+\dfrac{4}{-9}=\dfrac{5}{11}-\dfrac{4}{9}=\dfrac{1}{99}.\\ \dfrac{5}{9}-\dfrac{x}{-1}=\dfrac{-1}{3}\Leftrightarrow\dfrac{5}{9}+x=-\dfrac{1}{3}.\Leftrightarrow x=-\dfrac{8}{9}.\)

\(x=\dfrac{7}{25}+-\dfrac{1}{5}=>\dfrac{7}{25}+-\dfrac{5}{25}=>x=\dfrac{2}{25}\)

\(x=\dfrac{5}{11}+\dfrac{4}{-9}=>\dfrac{-45}{-99}+\dfrac{44}{-99}=>x=\dfrac{-1}{-99}=\dfrac{1}{99}\)

\(\dfrac{5}{9}-\dfrac{x}{-1}=-\dfrac{1}{3}=>-\dfrac{1}{3}-\dfrac{5}{9}=>\dfrac{x}{-1}=-\dfrac{8}{9}=>x=-\dfrac{8}{9}\)

\(x=\dfrac{7}{25}+\dfrac{-1}{5}\\ \Rightarrow x=\dfrac{7}{25}+\dfrac{-5}{25}\\ \Rightarrow x=\dfrac{2}{25}\\ x=\dfrac{5}{11}+\dfrac{4}{-9}\\ \Rightarrow x=\dfrac{-45}{-99}+\dfrac{44}{-99}\\ \Rightarrow x=\dfrac{45}{99}+\dfrac{44}{99}\\ \Rightarrow x=\dfrac{95}{99}\\ \dfrac{5}{9}-\dfrac{x}{-1}=\dfrac{-1}{3}\\ \Rightarrow\dfrac{x}{-1}=\dfrac{5}{9}-\dfrac{-1}{3}\\ \Rightarrow\dfrac{x}{-1}=\dfrac{5}{9}-\dfrac{-3}{9}\\ \Rightarrow\dfrac{x}{-1}=\dfrac{8}{9}\Rightarrow x\cdot9=-1\cdot8=-8\\ \Rightarrow x\cdot9=-8\\ \Rightarrow x=\dfrac{-8}{9}\)

a, x + 1/9 - 3/5 = 3/6

    x + 1/9        = 3/6 - 3/5

    x + 1/9        = -1/10

    x                = -1/10 - 1/9

    x                = -19/90

19/90 nha

 720 : ( x . 2 + x . 3 ) = 3.2
720 : ( x . 2 + x.3 ) = 6
( x .2 + x.3 )           = 720 : 6 
x.2+x.3 = 120
x . ( 2 + 3 ) = 120
x . 5 = 120
     x     = 120 : 5 
    x      = 24

\(\frac{x}{4}-\frac{3}{7}+\frac{2}{5}=\frac{31}{140}\)

\(\frac{x}{4}=\frac{31}{140}-\frac{2}{5}+\frac{3}{7}\)

\(\frac{x}{4}=\frac{1}{4}\)

\(\Rightarrow x=1\)

\(\frac{x}{4}-\frac{3}{7}+\frac{2}{5}=\frac{31}{140}\)

\(\frac{x}{4}-\frac{3}{7}=\frac{31}{140}-\frac{2}{5}\)

\(\frac{x}{4}-\frac{3}{7}=-\frac{5}{28}\)

\(\frac{x}{4}=-\frac{5}{28}+\frac{3}{7}\)

\(\frac{x}{4}=\frac{1}{4}\)

\(\Rightarrow x=1\)

\(\left(x-3\right)=\left(3-x\right)^2\)

\(\Leftrightarrow x-3=\left(x-3\right)^2\)

\(\Leftrightarrow\left(x-3\right)-\left(x-3\right)^2=0\)

\(\Leftrightarrow\left(x-3\right)\left[1-\left(x-3\right)\right]=0\)

\(\Leftrightarrow\left(x-3\right)\left(4-x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\4-x=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=4\end{matrix}\right.\)

___________

\(x^3+\dfrac{3}{2}x^2+\dfrac{3}{4}x+\dfrac{1}{8}=\dfrac{1}{64}\)

\(\Leftrightarrow x^3+3\cdot\dfrac{1}{2}\cdot x^2+3\cdot\left(\dfrac{1}{2}\right)^2\cdot x+\left(\dfrac{1}{2}\right)^3=\dfrac{1}{64}\)

\(\Leftrightarrow\left(x+\dfrac{1}{2}\right)^3=\left(\dfrac{1}{4}\right)^3\)

\(\Leftrightarrow x+\dfrac{1}{2}=\dfrac{1}{4}\)

\(\Leftrightarrow x=\dfrac{1}{4}-\dfrac{1}{2}\)

\(\Leftrightarrow x=-\dfrac{1}{4}\)

\(\Leftrightarrow\left(x+2\right)^3=343\)

=>x+2=7

hay x=5

(X-140)^3:7^2=4^5-3^2.4^3.

=>(x - 140)³:7² = 4⁵ - 3².4³

(x - 140)³ : 49 = 448

(x - 140)³ = 21952 = 28²

x - 140 = 28

x = 168

\(\dfrac{x}{3}=x+y=20\Rightarrow x=60\Rightarrow60+y=20\Rightarrow y=-40\)

Ta có:

\(\dfrac{x}{3}=20\)

\(\Rightarrow\)\(x=60\)

Lại có:

\(x+y=20\)

\(\Rightarrow\)\(y=20-60\)

\(\Rightarrow\)\(y=-40\)

Vây x = 60 và y = - 40

\(\dfrac{x}{3}=x+y\)

\(\Leftrightarrow x-\dfrac{1}{3}x=-y\)

\(\Leftrightarrow y=-\dfrac{2}{3}x\)

Ta có: x+y=20

\(\Leftrightarrow x\cdot\dfrac{1}{3}=20\)

hay x=60

=> y=40