\(=\dfrac{-16}{5}\cdot\dfrac{-15}{64}+\left(\dfrac{4}{5}-2-\dfrac{4}{15}\right):\dfrac{47}{24}\)

\(=\dfrac{3}{4}-\dfrac{22}{15}\cdot\dfrac{24}{47}=\dfrac{1}{940}\)

\(\left(-3,2\right).\frac{-15}{64}+\left(0,8-2\frac{4}{15}\right):3\frac{2}{3}\)

\(=\frac{3}{4}+\frac{-22}{15}:\frac{11}{3}\)

\(=\frac{3}{4}+\frac{-2}{5}=\frac{7}{20}\)

( - 3,2 ) x  - 15 / 64 + ( 0,8 - 24 / 15 ) : 11 / 3

= -16 / 5 x  -15 / 64 + ( 4 / 5 - 24 / 25 ) : 11 /3

= 3 / 4 + -22 / 15 : 11 / 3

= 3 / 4 + -2 / 5

= 7 / 20

a; (15 - \(\dfrac{121}{18}\)) : \(\dfrac{297}{27}\) - \(\dfrac{17}{8}\) : \(\dfrac{51}{40}\)

     (\(\dfrac{270}{18}\) - \(\dfrac{121}{18}\)) : \(\dfrac{297}{27}\) - \(\dfrac{17}{8}\) x \(\dfrac{40}{51}\)

 =   \(\dfrac{149}{18}\) : \(\dfrac{297}{27}\) - \(\dfrac{5}{3}\)

= \(\dfrac{149}{18}\) x \(\dfrac{27}{297}\) - \(\dfrac{5}{3}\)

 = \(\dfrac{149}{198}\) - \(\dfrac{5}{3}\)

= \(\dfrac{149}{198}\) - \(\dfrac{330}{198}\)

= \(\dfrac{-181}{198}\)

b; (- 3,2) x (- \(\dfrac{15}{64}\)) + (0,8 - \(\dfrac{34}{15}\)): \(\dfrac{11}{3}\)

= (\(\dfrac{-16}{5}\)) x ( \(\dfrac{-15}{64}\)) + (\(\dfrac{4}{5}\) - \(\dfrac{34}{15}\)): \(\dfrac{11}{3}\)

= \(\dfrac{3}{4}\) + (\(\dfrac{4}{5}\) - \(\dfrac{34}{15}\)): \(\dfrac{11}{3}\)

= \(\dfrac{3}{4}\) + (\(\dfrac{12}{15}\) - \(\dfrac{34}{15}\)) : \(\dfrac{11}{3}\)

= \(\dfrac{3}{4}\) + \(\dfrac{-22}{15}\) : \(\dfrac{11}{3}\)

= \(\dfrac{3}{4}\) - \(\dfrac{22}{15}\) x \(\dfrac{3}{11}\)

= \(\dfrac{3}{4}\) - \(\dfrac{2}{5}\)

= \(\dfrac{15}{20}\) - \(\dfrac{8}{20}\)

= \(\dfrac{7}{20}\)

c;   \(\dfrac{6}{7}\) + \(\dfrac{5}{8}\): 5 - \(\dfrac{3}{16}\) x (- 2)²

=   \(\dfrac{6}{7}\) +  \(\dfrac{5}{8}\) x \(\dfrac{1}{5}\) - \(\dfrac{3}{16}\) x 4

=  \(\dfrac{6}{7}\) + \(\dfrac{1}{8}\) - \(\dfrac{3}{4}\)

=   \(\dfrac{48}{56}\) + \(\dfrac{7}{56}\) - \(\dfrac{42}{56}\)

= \(\dfrac{55}{56}\) - \(\dfrac{42}{56}\)

=  \(\dfrac{13}{56}\)

đọc mà phát choáng

\(\left(-3,2\right).\left(\frac{-15}{64}\right)+\left(0,8-2\frac{4}{15}\right):3\frac{1}{2}\)

đúng đề bài này ko

\(\left(-3,2\right).\left(\frac{-15}{64}\right)+\left(0,8-2\frac{4}{15}\right):3\frac{1}{2}\)

\(=\frac{-16}{5}.\left(\frac{-15}{64}\right)+\left(\frac{4}{5}-\frac{34}{15}\right):\frac{7}{2}\)

\(=\frac{3}{4}+\left(\frac{-22}{15}\right):\frac{7}{2}\)

\(=\frac{3}{4}-\frac{44}{105}\)

\(=\frac{139}{420}\)

( - 3,2 ) . \(\frac{-15}{64}\)+ ( 0,8 - \(2\frac{4}{15}\)) : \(3\frac{1}{2}\)

= \(\frac{3}{4}+\frac{-22}{15}:\frac{7}{2}\)

= \(\frac{3}{4}+\frac{-44}{105}\)

= \(\frac{139}{420}\)

Bạn viết lại đề bài được không mình chưa rõ ý bạn?

\(\frac{41}{11}\left(copy\right)\)

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