\(C=48\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)=2\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)=2\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\left(5^{128}-1\right)=2.5^{128}-2\)

c: Ta có: \(C=48\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\cdot\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^2-1\right)\left(5^2+1\right)\cdot\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{16}-1\right)\cdot\left(5^{16}+1\right)\cdot\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{32}-1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{64}-1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{128}-1\right)\)

\(=2\cdot5^{128}-2\)

d: Ta có: \(E=\left(x-2\right)^3-\left(x+1\right)\left(x^2-x+1\right)+6\left(x-1\right)^2\)

\(=x^3-6x^2+12x-8-x^3-1+6x^2-12x+6\)

\(=-3\)

Ta có:

( 5 2 - 1).P = ( 5 2  – 1).12.( 5 2  + 1)( 5 4  + 1)( 5 8  + 1)( 5 16  + 1)

= 12.(  5 2  – 1).( 5 2  + 1)( 5 4 + 1)( 5 8  + 1)( 5 16 + 1)

= 12.(  5 4  - 1)(  5 4  + 1)(  5 8  + 1)( 5 16  + 1)

= 12.(  5 8  - 1)(  5 8  + 1)( 5 16  + 1)

= 12.(  5 16  - 1)( 5 16  + 1)

= 12.(  5 32  - 1)

a) 310 + 24 – 65 = 334 – 65 = 269

b) 275 + 58 x 2 = 275 + 116 = 391

c) 52 – 4 x 9 = 52 – 36 = 16

d) 63 : 7 x 8 = 9 x 8 = 72

a,D=1+2+4+8+16+32+64+128+256+512+1024

   D=(1+2)+4+8+16+32+64+128+256+512+1024

   D=(4+4)+8+16+32+64+128+256+512+1024

   D=(8+8)+16+32+64+128+256+512+1024

   D=(16+16)+32+64+128+256+512+1024

   D=(32+32)+64+128+256+512+1024

   D=(64+64)+128+256+512+1024

   D=(128+128)+256+512+1024

   D=(256+256)+512+1024

   D=(512+512)+1024

   D=1024+1024

   D=2048

b, 18.123+9.4567.2+3.5310.6

  =18.123+(9.2).4567+(3.6).5310

  =18.123+18.4567+18.5310

  =18.(123+4567+5310)

  =18.10000

  =180000

c, E= 1+4+7+10+...+49+52+55+58-490

    Dãy số trên có số số hạng là:(không tính số 490)

        (58-1):(4-1).1+1=20(số)

     E=(58+1).20:2-490=100

     vậy E=100

a) số số hạng của dãy số đó là : 

( 0,29 - 0,11 ) : 0,01 + 1 = 19 

Tổng của dãy số đó là :

( 0,11 + 0,29 ) x 19 : 2 = 3,8 

b) = ( 58 - 1 ) : 3 + 1 

= 20 x ( 1 + 58 ) : 2 

= 590 - 410 

= 180 

a)=3,8

b)=180

13 x 58 + 32 x 26 x 2 + 52 x 10

= 13 x 58 + 32 x 13 x 2 x 2 + 13 x 4 x 10

= 13 x 58 + 128 x 13 + 13 x 40

= 13 x (58 + 128 + 40)

= 13 x 226

= 2938

   13 x 58 + 32 x 26 x 2 + 52 x 10

= 13 x 58 + 32 x 13 x 2 x 2 + 13 x 4 x 10

= 13 x 58 + 128 + 13 x 40

= 13 x ( 58 +128 + 40 )

= 13 x 226

= 2938

  13 x 58 + 32 x 26 x 2 + 52 x 10

= 13 x 58 + 13 x 2 x 32 x 2 + 13 x 4 x 10

= 13 x 58 + 13 x 128 + 13 x 40

= 13 x ( 58 + 128 + 40 )

= 13 x 226

= 2938

Ta có: \(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(\Rightarrow P=\dfrac{24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{\left(5^{16}-1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{5^{32}-1}{2}\)

a) 103 + 20 + 5 = 123 + 5 = 128

Giá trị của biểu thức

103 + 20 + 5 là 128.

b) 241 – 41 + 29 = 200 + 29 = 229

Giá trị của biểu thức

241 – 41 + 29 là 229.

c) 516 – 10 + 30 = 506 + 30 = 536

Giá trị của biểu thức

516 – 10 + 30 là 536.

d) 635 – 3 – 50 = 650 – 50 = 600

Giá trị của biểu thức

635 – 3 – 50 là 600.

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