a)

204 - 84:12 = 204 - 7 = 197

b)

15.2³ + 4.3² - 5.7 = 15.8 + 4.9 – 5.7 = 120 + 36 - 35 = 121

c) Áp dụng:

a^m . aⁿ = a^m+n

a^m : aⁿ = a^m-n

5⁶:5³ + 2³.2² = 5³ + 2⁵ = 125 + 32 = 157

d)

164.53 + 47.164 = 164(53 + 47) = 164.100 = 16400

a) 204 - 84 : 12

= 204 - 7 = 197

b) 15.2³ + 4.3² - 5.7

= 15.8 + 4.9 - 35

= 120 + 36 - 35

= 156 - 35

= 121

c) 5⁶ : 5³ + 2³.2²

= 5^{6 - 3} + 2^{3 + 2}

= 5³ + 2⁵

= 125 + 32

= 157

d) 164.53 + 47.164

= 164.( 53 + 47 )

= 164.100

= 16400

a) 204 - 84 : 12

= 204 - 7 = 197

b) 15.23 + 4.32 - 5.7

= 15.8 + 4.9 - 35

= 120 + 36 - 35

= 156 - 35

= 121

c) 56 : 53 + 23.22

= 56 - 3 + 23 + 2

= 53 + 25

= 125 + 32

= 157

d) 164.53 + 47.164

= 164.( 53 + 47 )

= 164.100

= 16400

a. 50-17+2-50+15

= (50-50)+(15+2-17)

= 0+0 = 0

a.0

b.79
c.16400
d.10

2:

=>27:3^x=2*25-16-31=50-47=3

=>3^x=27/3=9

=>3^x=3^2

=>x=2

1:

b: \(=16\cdot55+16\cdot45-1\)

=16(55+45)-1

=1600-1

=1599

c: \(=\dfrac{1800}{49-\left[2\cdot\left(36-34\right)^3-5\right]}\)

\(=\dfrac{1800}{49-2\cdot2^3+5}=\dfrac{1800}{49-16+5}=\dfrac{1800}{38}\)=900/19

d: \(=\dfrac{5\cdot3^{11}\cdot2^{11}-3^{11}\cdot2^{11}}{2^{10}\cdot3^{10}\cdot2^2\cdot3+7\cdot2^{12}\cdot3^{12}}\)

\(=\dfrac{3^{11}\cdot2^{11}\left(5-1\right)}{2^{12}\cdot3^{11}\left(1+7\cdot3\right)}=\dfrac{1}{2}\cdot\dfrac{4}{1+21}=\dfrac{4}{22\cdot2}=\dfrac{1}{11}\)

204-84:2=204-42=162

15.2³+4.3²-5.7=15.8+4.9-35=120+36-35=121

5⁶:5³+2³.2²=15625:125+8.4=125+32=157

164.53+47.164=164.(53+47)=164.100=16400

HỌC TỐT.

mình sai ở đâu vậy mà bạn k sai

Bài 2: 

a: =>x-1=1 hoặc x-1=-1

=>x=2 hoặc x=0

b: =>x+1=-1

hay x=-2

c: =>(135-7x):9=8

=>135-7x=72

=>7x=63

hay x=9

d: =>(x+7)(x-3)<0

=>-7<x<3

e: \(\Leftrightarrow3^{x-3}=18+9=27\)

=>x-3=3

hay x=6

f: =>4-2x=0

hay x=2

a: Ta có: \(3\sqrt{2}\cdot5\sqrt{6}\cdot4\sqrt{12}\)

\(=\sqrt{18\cdot25\cdot6\cdot16\cdot12}\)

\(=\sqrt{518400}\)

=720

b: Ta có: \(\left(\sqrt{7}-\sqrt{2}\right)^2+2\sqrt{14}\)

\(=9-2\sqrt{14}+2\sqrt{14}\)

=9

c: Ta có: \(\left(1+\sqrt{5}+\sqrt{6}\right)\left(1+\sqrt{5}-\sqrt{6}\right)\)

\(=6+2\sqrt{5}-6\)

\(=2\sqrt{5}\)

a) \(204-84:12=204-7=197\)

b) \(15.2^3+4.3^2-5.7=15.8+4.9+5.7=120+36+35=156+35=191\)

c) \(5^6:5^3+2^3.2^2=5^3+2^5=125+32=157\)

d) \(164.53+47.164=164.\left(53+47\right)=164.100=16400\)

_Chúc bạn học tốt_

208 - 84: 12= 208- 7= 201

5^6 : 5^3 + 2^3.2^2= 5^3 + 2^5= 125 + 32= 1577

15 . 2^3 + 4 . 3^2 - 5.7= 15 . 8 + 4. 9 - 5.7= 120 + 36 - 35=156 - 35=121

164 . 53 + 47 . 164= 164.(53 + 47)=164. 100=16400

a)204-84:12=204-7=197

b)5⁶:5³+2³.2²=(5:5)⁹+2⁵=9+32=41       

c)15.2³+4.3²-5.7=15.8+4.9-35=120+36-35=121

d)164.53+47.164=(53+47).164=100.164=16400

2:

a: =>2(x+1)=26

=>x+1=13

=>x=12

b: =>(6x)^3=125

=>6x=5

=>x=5/6(loại)

c: =>\(7\cdot3^x\cdot\dfrac{1}{3}+11\cdot3^x\cdot3=318\)

=>3^x=9

=>x=2

d: -2x+13 chia hết cho x+1

=>-2x-2+15 chia hết cho x+1

=>15 chia hết cho x+1

=>x+1 thuộc {1;3;5;15}

=>x thuộc {0;2;4;14}

e: 4x+11 chia hết cho 3x+2

=>12x+33 chia hết cho 3x+2

=>12x+8+25 chia hết cho 3x+2

=>25 chia hết cho 3x+2

=>3x+2 thuộc {1;-1;5;-5;25;-25}

mà x là số tự nhiên

nên x=1

1: 

a: Đặt A=2^2024-2^2023-...-2^2-2-1

Đặt B=2^2023+2^2022+...+2^2+2+1

=>2B=2^2024+2^2023+...+2^3+2^2+2

=>B=2^2024-1

=>A=2^2024-2^2024+1=1

c: \(=\dfrac{3^{12}\cdot2^{11}+2^{10}\cdot3^{12}\cdot5}{2^2\cdot3\cdot3^{11}\cdot2^{11}}=\dfrac{2^{10}\cdot3^{12}\left(2+5\right)}{2^{13}\cdot3^{12}}\)

\(=\dfrac{7}{2^3}=\dfrac{7}{8}\)