Phan tich da thuc thanh nhan tu
M=\(a\left(b^2-c^2\right)+b\left(c^2-a^2\right)+c\left(a^2-b^2\right)\)
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Phan tich da thuc thanh nhan tu
M=\(a\left(b^2-c^2\right)+b\left(c^2-a^2\right)+c\left(a^2-b^2\right)\)
Phan tich da thuc thanh nhan tu
\(\left(a+b+c\right)^2+\left(a+b-c\right)^2-4c^2\)
\(\left(a+b+c\right)^2+\left(a+b-c\right)^2-4c^2\)
\(=\left[\left(a+b+c\right)^2-\left(2c\right)^2\right]+\left(a+b-c\right)^2\)
\(=\left(a+b+3c\right)\left(a+b-c\right)+\left(a+b-c\right)^2\)
\(=\left(a+b-c\right)\left(a+b+3c+a+b-c\right)\)
\(=\left(a+b-c\right)\left(2a+2b+2c\right)\)
\(=2\left(a+b-c\right)\left(a+b+c\right)\)
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Phan tich da thuc thanh nhan tu
A=\(\left(a+b+c\right)^2+\left(a+b-c\right)^2-4c^2\)
\(=\left(a+b\right)^2+2\left(a+b\right)c+c^2+\left(a+b\right)^2-2\left(a+b\right)c+c^2-4c^2\)
\(=2\left(a+b\right)^2-2c^2=2\left[\left(a+b\right)^2-c^2\right]=2\left(a+b+c\right)\left(a+b-c\right)\)
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Phan tich da thuc thanh nhan tu :
A=\(\left(a+b+c\right)^2+\left(a+b-c\right)^2-4c^2\)
Mình đã làm bài này rồi.
Link: https://hoc24.vn/hoi-dap/question/824554.html
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Phan tich da thuc sau thanh nhan tu:
a) \(a\left(b+c\right)^2+b\left(c+a\right)^2+c\left(a+b\right)^2\)
b)\(a^4+b^4+c^4-2a^2b^2-2a^2c^2-2c^2b^2\)
Phan tich da thuc thanh nhan tu
\(\left(a-b\right)^3+\left(b-c\right)^3+\left(c-a\right)^3\)
(a−b)3+(b−c)3+(c−a)3=3(a−b)(b−c)(c−a)
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Xem thêm câu trả lời
phan tich da thuc thanh nhan tu :
a,(x-5)^2+(x-5)(x+5)-(5-x)(2x+1)
b,\(\left(3x-2\right)\left(4x-3\right)-\left(2-3x\right)\left(x-1\right)-2\left(3x-2\right)\left(x+1\right)\)
Câu a :
\(\left(x-5\right)^2+\left(x-5\right)\left(x+5\right)-\left(5-x\right)\left(2x+1\right)\)
\(=x^2-10x+25+x^2-25-10x-5+2x^2+x\)
\(=4x^2-19x-5\)
Câu b :
\(\left(3x-2\right)\left(4x-3\right)-\left(2-3x\right)\left(x-1\right)-2\left(3x-2\right)\left(x+1\right)\)
\(=12x^2-9x-8x+6-2x+2+3x^2-3x-6x^2-6x+4x+4\)
\(=9x^2-24x+2\)
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phan tich da thuc thanh nhan tu
ab(a-b)+bc(b-c) +ca(c-a)
\(x^4-3x^3y+3x^2y^2-z^3-xy^3\)
\(\left(a-b\right)^3+\left(b-c\right)^3+\left(c-a\right)^3\)
phan tích da thuc thanh nhan tu
\(\text{a}b\left(\text{a}-b\right)+bc\left(b-c\right)+c\text{a}\left(c-\text{a}\right)\)
\(ab\left(a-b\right)+bc\left(b-c\right)+ca\left(c-a\right)\)
\(=ab\left(a-b\right)+bc\left[\left(b-a\right)-\left(c-a\right)\right]+ca\left(c-a\right)\)
\(=ab\left(a-b\right)-bc\left(a-b\right)-bc\left(c-a\right)+ca\left(c-a\right)\)
\(=\left(a-b\right)\left(ab-bc\right)-\left(c-a\right)\left(bc-ca\right)\)
\(=b\left(a-b\right)\left(a-c\right)-c\left(c-a\right)\left(b-a\right)\)
\(=b\left(a-b\right)\left(a-c\right)-c\left(a-c\right)\left(a-b\right)\)
\(=\left(a-c\right)\left(a-b\right)\left(b-c\right)\)
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