\(4x^2-y^2-6x+3y\)

\(=\left(2x\right)^2-y^2-3\left(2x-y\right)\)

\(=\left(2x-y\right)\left(2x+y\right)-3\left(2x-y\right)\)

\(=\left(2x-y\right)\left(2x+y-3\right)\)

Phân tích đa thức thành nhân tử :

\(4x^2-y^2-6x+3y\)

\(=\left(2x-y\right)\left(2x+y\right)-3\left(2x-y\right)\)

\(=\left(2x-y\right)\left(2x+y+3\right)\)

mk xl nhé, mk ghi sai dấu 

Sửa lại phần cuối :

\(\left(2x-y\right)\left(2x+y-3\right)\)

1. 5x² - 4x

= x(5x - 4)

2. 8x²(x - 3y) - 12x(x - 3y)

= (8x² - 12x)(x - 3y)

= 4x(2x - 3)(x - 3y)

3. 3(x - y) - 5x(y - x)

= 3(x - y) + 5x(x - y)

= (3 + 5x)(x - y)

a: \(x^2+4xy+y^2\)

\(=x^2+4xy+4y^2-3y^2\)

\(=\left(x+2y-y\sqrt{3}\right)\left(x+2y+y\sqrt{3}\right)\)

1. \(4x^2-2x-3y-9y^2\)

\(=\left(2x\right)^2-\left(3y\right)^2-\left(2x+3y\right)\)

\(=\left(2x-3y\right)\left(2x+3y\right)-\left(2x+3y\right)\)

\(=\left(2x+3y\right)\left(2x-3y-1\right)\)

2. \(x^2-25=6x-9\)

\(\Rightarrow x^2-6x+9=25\)

\(\Rightarrow\left(x-3\right)^2=25\)

\(\Rightarrow\orbr{\begin{cases}x-3=5\\x-3=-5\end{cases}}\Rightarrow\orbr{\begin{cases}x=8\\x=-2\end{cases}}\)

\(4x^4y-4x^2y^3+12x^3y+12x^2y^2\)

\(=4x^2y\left(x^2-y^2+3x+3y\right)\)

\(=4x^2y\left(x-y-3\right)\left(x+y\right)\)

3(x²-2x+1-y²⁾ 

=3((x-1)²-y²)

3.(x-1-y)(x-1+y)

tik nha 3:)

a) 3x^2 -6x + 3 - 3y^2

=3.(x²-2x+1-y²)

=3.[(x-1)²-y²]

=3.(x-1+y)(x-1-y)

\(x^4+x^3y-4x-4y\) (sửa \(x^3\rightarrow x^4\))

\(=x^3\left(x+y\right)-4\left(x+y\right)\)

\(=\left(x+y\right)\left(x^3-4\right)\)

\(=\left(x+y\right)\left(x^2-xy+y^2\right)-4\left(x+y\right)=\)

\(=\left(x+y\right)\left(x^2-xy+y^2-4\right)\)