2 x 2 x X = 28
Tính
\(\dfrac{x^{30}+x^{28}+...+x^4+x^2+1}{x^{28}+x^{26}+...+x^2+1}\)
x^30+x^28+x^26+.........+x^4+x^2+1/x^28+x^24+x^20+.........+x^8+x^4+1
\(\frac{x^{30}+x^{28}+x^{26}+x^{24}+...+x^4+x^2+1}{x^{28}+x^{24}+x^{20}+...+x^8+x^4+1}=\frac{\left(x^{30}+x^{26}+x^{22}+...+x^2\right)+\left(x^{28}+x^{24}+...+x^4+1\right)}{x^{28}+x^{24}+x^{20}+...+x^4+1}\)
\(=\frac{x^2\left(x^{28}+x^{24}+...+x^4+1\right)+\left(x^{28}+x^{24}+...+x^4+1\right)}{x^{28}+x^{24}+...+x^4+1}\)
\(=\frac{\left(x^2+1\right)\left(x^{28}+x^{24}+...+x^4+1\right)}{x^{28}+x^{24}+...+x^4+1}\)
\(=x^2+1\)
7 x 2 = ..... 7 x 4 = ..... 7 x 6 = ..... 7 x 3 = .....
2 x 7 = ..... 4 x 7 = ..... 6 x 7 = ..... 3 x 7 = .....
14 : 7 = ..... 28 : 7 = ..... 42 : 7 = ..... 21 : 7 = .....
14 : 2 = ..... 28 : 4 = ..... 42 : 6 = ..... 21 : 3 = .....
7 x 2 = 14 7 x 4 = 28 7 x 6 = 42 7 x 3 = 21
2 x 7 = 14 4 x 7 = 28 6 x 7 = 42 3 x 7 = 21
14 : 7 = 2 28 : 7 = 4 42 : 7 = 6 21 : 7 = 3
14 : 2 = 7 28 : 4 = 7 42 : 6 = 7 21 : 3 = 7
1.tìm x để A nhập giá trị A=x/12
2-x^30+x^28+x^26+.....+x^4+x^2+1/b^28+x^24+x^20+....+x^1+x^4+1
Tính hợp lý nếu có thể:
a) -52 x (-2)2 + (-3)3
b) (-19 - 46) : (-13) - (-52) x (-22)
c) (135 - 35) x (-47) + 53 x (-48 - 52)
d) [(-3)13 : 95 - 73] : (-52) - |-14|
e) -105 : (-15) - 21 - 9 x (-2)3
g) (-51) x (-29) - 131 x 51 + |-102|
h) (83 - 107 - 854) - (107 - 554) + 117
k) (-5)2 x 32 x 53 x (-17) x (-1)2n, n thuộc N
n) -28 x (-19) - (-64) x 28 x 17 x |-28|
m) 73 x (28 - 56) - 28 x (73 + 56)
a: \(=-25\cdot4-27=-100-27=-127\)
b: \(=-65:\left(-13\right)-25\cdot4=5-100=-95\)
c: \(=100\cdot\left(-47\right)+53\cdot\left(-100\right)=100\cdot\left(-100\right)=-10000\)
d: \(=\left[\left(-3\right)^{13}:3^{10}-73\right]:\left(-5\right)^2-14\)
\(=\left(-100\right):25-14=-4-14=-18\)
đúng hay sai a,28:4= 28 x 2 : 4 x 2
D = (x^2 -1)(x^2-2)(x^2 - 3)....(x^2 - 2022) khi x = 28
D = (x² - 1)(x² - 2)(x² - 3)...(x² - 2022)
= (x² - 1)(x² - 2)(x² - 3)...(x² - 784)...(x² - 2022)
Thay x = 28 vào D, ta có:
D = (28² - 1)(28² - 2)(28² - 3)...(28² - 784)...(28² - 2022)
= (28² - 1)(28² - 2)(28² - 3)...(28² - 28²)...(28² - 2022)
= 0
Giải các phương trình sau: ( x + 2 ) 2 8 - 2 ( 2 x + 1 ) = 25 + ( x - 2 ) 2 8
(x+1)(x^2-x+1)-x^2(x-3)=28
\(\Leftrightarrow x^3+1-x^3+3x^2=28\)
hay \(x\in\left\{3;-3\right\}\)
Tìm x biết :
a) | 45 + x | + x = -15
b) | x + 2 | - 6x = 1
c ) | x - 3 | + | x + 3 | = 7
d) 3 | 4 x - 1 | - 2 = 19
e) x - 28 - 124 / 2011 + x -1 24 - 2014 / 28 + x - 2014 - 28 / 124 = 3