3/ 4x=1 <=>x=1/4

4/7x=9/8-0,125 <=>7x=1<=>x=1/7

3/4x=1

<=>x=4/3

4/7x=9/8-0,125

<=>4/7x=9/8-1/8=8/8=1

<=>x=7/4

\(\frac{3}{4}x=1\)

\(\Leftrightarrow x=\frac{4}{3}\)

\(\frac{4}{7}x=\frac{9}{8}-0,125\)

\(\Leftrightarrow\frac{4}{7}x=\frac{9}{8}-\frac{1}{8}\)

\(\Leftrightarrow\frac{4}{7}x=1\)

\(\Leftrightarrow x=\frac{7}{4}\)

a/

   3/4 . x = 1

  => x= 1: 3/4 = 4/3

b/

       4/7 .x = 9/8 -0,125 = 9/8 -1/8 = 1

   => x= 1 : 4/7 = 7/4

a/ 3/4x=1

x=1:3/4

x=4/3

b/ 4/7x=9/8-0,125

4/7x=1

x=1:4/7

x=7/4

Lời giải:
a)

\(\frac{3}{4}x=1\)

\(x=1:\frac{3}{4}=1.\frac{4}{3}=\frac{4}{3}\)

b)

\(\frac{4}{7}x=\frac{9}{8}-0,125\)

\(\frac{4}{7}x=1\)

\(x=1:\frac{4}{7}\)

\(x=\frac{7}{4}\)

a) 3/4x = 1

         x = 1 : 3/4

         x = 4/3

b) 4/7x = 9/8 - 0,125

    4/7x = 1

        x = 1 : 4/7

        x = 7/4

a)\(\frac{3}{4}\). x =1

             x=1:\(\frac{3}{4}\)

             x=      \(\frac{4}{3}\)

b)\(\frac{4}{7}\).x=\(\frac{9}{8}\)-0,125

\(\frac{4}{7}\).x=1,125-0,125

\(\frac{4}{7}\).x=1

         x=1:\(\frac{4}{7}\)

         x=\(\frac{7}{4}\)

CHÚC BẠN HỌC GIỎI

K MÌNH NHÉ

x = 7/4

Nho tk cho minh nhe

*4/7x=9/8.0,125 

4/7x=9/8.1/8

4/7x=9/64

x    =9/64:4/7

x    =9/64.7/4

x    =63/256

*x-25%=1/2

x-1/4.x  =1/2

x(1-1/4) =1/2

3/4.x     =1/2

x           =1/2:3/4

x           =1/2.4/3

x           =2/3

a,\(\frac{1}{7}\)b,\(\frac{7}{4}\)c,\(\frac{-10}{3}\)d,ko rõ  e,=10

4/9x=9/8-0,125

4/9x=1

x=1:4/9

x=2,25

\(\dfrac{4}{7}x=\dfrac{9}{8}-\dfrac{1}{8}\left(\dfrac{1}{8}=0,125\right)\)

\(\dfrac{4}{7}x=1\)

->x=1:\(\dfrac{4}{7}\)

-> x= \(\dfrac{7}{4}\)

Ta có: \(\dfrac{4}{7}x=\dfrac{9}{8}-0.125\)

\(\Leftrightarrow\dfrac{4}{7}x=\dfrac{9}{8}-\dfrac{1}{8}=1\)

hay \(x=\dfrac{7}{4}\)

Vậy: \(x=\dfrac{7}{4}\)