1+ 1=....
98+99=
69+69=
98+69-99-88
A= 1/1×2+1/2×3+...1/98×99+1/99×100
B=4/3×7+4/7×11+4/11×15+...4/107×111
C=7/10×11+7/11×12+7/12×13+...7/69×70
Các bạn làm ơn giúp mình với
\(A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{98.99}+\frac{1}{99.100}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)
\(A=1-\frac{1}{100}\)
\(A=\frac{99}{100}\)
\(B=\frac{4}{3.7}+\frac{4}{7.11}+\frac{4}{11.15}+...+\frac{4}{107.111}\)
\(B=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{107}-\frac{1}{111}\)
\(B=\frac{1}{3}-\frac{1}{111}\)
\(B=\frac{12}{37}\)
\(C=\frac{7}{10.11}+\frac{7}{11.12}+\frac{7}{12.13}+...+\frac{7}{69.70}\)
\(C=7\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+...+\frac{1}{69}-\frac{1}{70}\right)\)
\(C=7\left(\frac{1}{10}-\frac{1}{70}\right)\)
\(C=7.\frac{3}{35}\)
\(C=\frac{3}{5}\)
Ta có:
\(A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{98.99}+\frac{1}{99.100}\)
\(A=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\)
\(A=\frac{1}{1}-\frac{1}{100}=\frac{99}{100}\)
\(B=\frac{4}{3.7}+\frac{4}{7.11}+\frac{4}{11.15}+...+\frac{4}{107.111}\)
\(B=4.\left(\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{107}-\frac{1}{111}\right)\)
\(B=4.\left(\frac{1}{3}-\frac{1}{111}\right)=4.\frac{12}{37}=\frac{48}{37}\)
\(C=\frac{7}{10.11}+\frac{7}{11.12}+\frac{7}{12.13}+...+\frac{7}{69.70}\)
\(C=7.\left(\frac{1}{10.11}+\frac{1}{11.12}+\frac{1}{12.13}+...+\frac{1}{69.70}\right)\)
\(C=7.\left(\frac{1}{10}-\frac{1}{70}\right)=7.\frac{3}{35}=\frac{3}{5}\)
\(A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{98.99}+\frac{1}{99.100}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\)
\(A=1-\frac{1}{100}=\frac{99}{100}\)
\(B=\frac{4}{3.7}+\frac{4}{7.11}+\frac{4}{11.15}+...+\frac{4}{107.111}\)
\(B=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{107}-\frac{1}{111}\)
\(B=\frac{1}{3}-\frac{1}{111}=\frac{12}{37}\)
\(C=\frac{7}{10.11}+\frac{7}{11.12}+\frac{7}{12.13}+...+\frac{7}{69.70}\)
\(C=7.\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+...+\frac{1}{69}-\frac{1}{70}\right)\)
\(C=7.\left(\frac{1}{10}-\frac{1}{70}\right)=7.\frac{3}{35}\)
\(\Rightarrow C=\frac{3}{5}\)
Rút gọn các tổng sau:
a) A = 2 - 2\(^2\) + 2\(^3\) - 2\(^4\) + ... + 2\(^{99}\) - 2\(^{100}\)
b) B = 1 + 2\(^2\) + 2\(^4\) + ... + 2\(^{98}\) + 2\(^{100}\)
c) C = 1 - 2\(^3\) + 2\(^6\) - 2\(^9\) + ... + 2\(^{60}\) - 2\(^{63}\) + 2\(^{69}\)
d) D = 1 + \(\dfrac{1}{3}\) + \(\dfrac{1}{3^2}\) + \(\dfrac{1}{3^4}\) + ... + \(\dfrac{1}{3^{100}}\)
e) E = 1 - \(\dfrac{1}{4}\) + \(\dfrac{1}{4^2}\) - \(\dfrac{1}{4^3}\) + ... + \(\dfrac{1}{4^{98}}\) - \(\dfrac{1}{4^{99}}\) + \(\dfrac{1}{4^{100}}\)
-Quy luật: Nhân mỗi vế của đẳng thức cho số thích hợp để tạo ra đẳng thức mới, khi cộng (hoặc trừ) mỗi vế của mỗi đẳng thức thì sẽ rút gọn bớt.
a) \(A=2-2^2+2^3-2^4+...+2^{99}-2^{100}\)
\(\Rightarrow2A=2^2-2^3+2^4-2^5+...+2^{100}-2^{101}\)
\(\Rightarrow2A+A=2^2-2^3+2^4-2^5+...+2^{100}-2^{101}+\left(2-2^2+2^3-2^4+...+2^{99}-2^{100}\right)\)
\(\Rightarrow A=-2^{101}+2\)
b,c) làm tương tự.
d) \(D=1+\dfrac{1}{3}+\dfrac{1}{3^2}+...+\dfrac{1}{3^{100}}\)
\(\Rightarrow3D=3+1+\dfrac{1}{3}+...+\dfrac{1}{3^{99}}\)
\(\Rightarrow3D-D=3+1+\dfrac{1}{3}+...+\dfrac{1}{3^{99}}-\left(1+\dfrac{1}{3}+\dfrac{1}{3^2}+...+\dfrac{1}{3^{100}}\right)\)
\(\Rightarrow2D=3+\dfrac{1}{3^{100}}\)
\(\Rightarrow2D=\dfrac{3^{101}+1}{3^{100}}\Rightarrow D=\dfrac{3^{101}+1}{2.3^{100}}\)
e) làm tương tự nhưng đổi thành cộng.
>; <; =?
89 156 ... 98 516 69 731 ... 69 713
79 650 ... 79 650 67 628 ... 67 728
89 156 .<.. 98 516 69 731 ..>. 69 713
79 650 .=.. 79 650 67 628 .<.. 67 728
Ta có :A =99100+1/9999+1
B=9969+1/9968+1
So sánh A và B
*Bí mật của số:
19=1×9+1+9
29=2×9+2+9
...(các số tương tự: 39, 49, 59, 69, 79, 89, 99)
*Bí mật của số:
18=1×8+1+8+1
28=2×8+2+8+2
...(các số tương tự: 38, 48, 58, 68, 78, 88, 98)
Chắc minh ko nhớ nỗi đâu nhưq hay vẫn pải khen ^^
b1:tìm x thuộc z, biết:
a. |x| + |x - 1 | = 1
b. 27 - (5 - |x| ) = 31
c. -13 - (6 - | x + 1 | = 24 )
b2:tính nhanh
a. -2001 + ( 1999 + 2001 )
b. 3784 + 23 - 3785 - 15
c. (42 - 69 + 17) - ( 42+17 )
d. 1 + (-2) +3 +(-4)+......+ (-98 ) + 99
Bài 1:
b: 27-(5-|x|)=31
=>5-|x|=-4
=>|x|=9
=>x=9 hoặc x=-9
c: -13-(6-|x+1|)=24
=>6-|x+1|=-37
=>|x+1|=43
=>x+1=43 hoặc x+1=-43
=>x=42 hoặc x=-44
a) 100 + 98 + 96 + ... + 2 - 97 - 95 - ... - 1
b) 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + 10 - 11 - 12 + ... + 299 - 300 + 301 + 302
c) 2 . 31 . 12 + 4 .6 . 42 + 8 . 27 . 3
d) 36 . 28 + 36 . 82 + 64 . 69 + 64 . 41
e) 99 - 97 + 95 - 93 + 91 - 89 + ...+ 7 - 5 + 3 - 1
a, 100 + 98 + 96 + ... + 2 - 9 7 - 95 - .. -1
= 100 + (98 - 97) + (96-95) + ... + + ... + (2 - 1)
= 100 + 1 + 1 + 1 +.. +1
= 100 + 1 x49
= 100 + 49
= 149
b , 1 + 2 - 3 - 4 + 5 + 6 - .... -299 - 330 +301 + 302
=( 1 + 2 - 3) + ( -4 + 5 + 6 -7 ) +... +(298 - 299 -300 +301 ) + 302
= 0 + 0 + .. + 0 + 302
= 302
c) 2 . 31 . 12 + 4 . 6 . 42 + 8 . 27 . 3
=24.31+24.42+24.27
=24.(31+42+27)
=24.100
=2400
d)
=36x(28+82)+64x(69+41)
=36x110+64x110
=110x(26+64)
=110x100
=11000
d) dãy tính trên có số số tự nhiên là: (99-1):2+1=50(số)
99-97+95-93+91-89+...+7-5+3-1(50:2=25 cặp)
(99-97)+(95-93)+(91-89)+...+(7-5)+(3-1) (25 cặp)
2+2+2+2+2+...+2+2(25 số 2)
2x25=50
Tính
1. (-34)+24+(-7)+27
2. 99+(-100)+101
3. (-75)+69+(-25)+131
1. (-34)+24+(-7)+27=-10+20=10
2.99+(-100)+101=(99+101)+(-100)=200-100=100
3.(-75)+69+(-25)+131=(69+131)-(75+25)=200-100=100
1) \(\left(-34\right)+24+\left(-7\right)+27\)
\(=-34+24-7+27\)
\(=-\left(34-24\right)-7+27\)
\(=-10-7+27\)
\(=-\left(10+7\right)+27\)
\(=-17+27\)
\(=27-17\)
\(=10\)
2) \(99+\left(-100\right)+101\)
\(=99-100+101\)
\(=-100+99+101\)
\(=-\left(100-99\right)+101\)
\(=-1+101\)
\(=101-1\)
\(=100\)
3) \(\left(-75\right)+69+\left(-25\right)+131\)
\(=-75+69-25+131\)
\(=-\left(75-69\right)-25+131\)
\(=-6-25+131\)
\(=-\left(6+25\right)+131\)
\(=-31+131\)
\(=131-31\)
\(=100\)
1. (-34) + 24 + (-7) + 27
= (-10) + 20
=10
2. 99 + (-100) +101
= (-1) + 101
=100
3. (-75) + 69 + (-25) + 131
= (-6) + (-25) +131
= (-31) + 131
= 100
=