(x-3)(x+4)-2(3x-2)=(x-4)^2
giup mik vs a
Những câu hỏi liên quan
a) ( 2x + 4 ) chia het ( x + 2 )
b) ( x+ 3 ) chia het ( x - 1)
c ) 3x chia het ( x+ 3 )
giup mik vs mik dang can gap
Tìm x:
a)x(2x-4)-(x-2)(2x+3)
b)x(3x+2)+(x+1)^2-(2x-5)(2x+5)=-12
c)(x-1)(x^2+x+1)-x(x-3)^2=6x^2
d)x^2-x=0
e)(x+2)(x-3)-x-2=0
f)3x^3-27x
Giup mik vs nha
câu a không có về phải=> k làm dc
Đúng 0
Bình luận (0)
b)x(3x+2)+(x+1)^2-(2x-5)(2x+5)=-12
<=> 3x^2 +2x +x^2+2x+1 - 4x^2 +25 +12=0
<=> 4x+38=0
=>4x= -38
=>x= -38/4= -19/2
Đúng 0
Bình luận (0)
d)x^2-x=0
<=>x(x-1)=0
=>x=0 hoặc x-1=0
=>x=0 hoặc x=1
Đúng 0
Bình luận (0)
Xem thêm câu trả lời
x^2-6x+9=2x(x-3)
(x+3)^2+(x+2)(x-2)
(3x-1)^3-27(x+3)(x^2-3x+9)
x^4+2x^3+x
(3x+y)^2-4(2y-3x)^2
ai giai giup minh vs minh can ngay ngay mai
giup mik voi tim x biet
1, 5-(3x+6)>-2x+1
2, -7.(x+2)-3x<6-11x
3, (x+1).(x+2)-x.(x+3)<4-x
4, 6-2x>17+(4-x)
a) (x - 3)(2x ^ 2 - 3x + 4)
b) (4x ^ 2 * y - 5x * y ^ 2 + 6xy) 2xy:
c ) x/(2x + 4) - 2/(x ^ 3 + 2x)
Ai giúp mik vs ạ🥲
a: \(\left(x-3\right)\left(2x^2-3x+4\right)\)
\(=2x^3-3x^2+4x-6x^2+9x-12\)
\(=2x^3-9x^2+13x-12\)
b: \(\left(4x^2y-5xy^2+6xy\right):2xy\)
\(=\dfrac{4x^2y-5xy^2+6xy}{2xy}\)
\(=\dfrac{2xy\cdot2x-2xy\cdot2,5y+2xy\cdot3}{2xy}\)
\(=2x-2,5y+3\)
c: \(\dfrac{x}{2x+4}-\dfrac{2}{x^3+2x}\)
\(=\dfrac{x\left(x^3+2x\right)-2\left(2x+4\right)}{x\left(x^2+2\right)\cdot2\cdot\left(x+2\right)}\)
\(=\dfrac{x^4+2x^2-4x-8}{2x\left(x^2+2\right)\left(x+2\right)}\)
Đúng 1
Bình luận (0)
a, 2x+4-5x=-11
b,Ix-(-5)=8
c,(x+2)^2=25
2(x-12)+13=x+(-14)
giup mik vs
ai dung mik tick cho:)
a, 2\(x\) + 4 - 5\(x\) = -11
-(5\(x\) - 2\(x\)) + 4 = -11
-3\(x\) + 4 = -11
3\(x\) = 11 + 4
3\(x\) = 15
\(x\) = 15 : 3
\(x\) = 5
Đúng 2
Bình luận (0)
b, \(x\) - (-5) = 8
\(x\) + 5 = 8
\(x\) = 8 - 5
\(x\) = 3
Đúng 0
Bình luận (0)
c, (\(x\) + 2)2 = 25
\(\left[{}\begin{matrix}x+2=5\\x+2=-5\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=3\\x=-7\end{matrix}\right.\)
Đúng 0
Bình luận (0)
Xem thêm câu trả lời
\(x^5=x^4+x^3+x^2+x+2\) 2 ae giup mik vs nhe
Giup trag vs ak
a) 4(x-3)\(^2\)-(2x-1)(2x+1)=10
b) (x-4)\(^2\)-(x-2)(x+2) = 6
c) 9(x+1)\(^2\)-(3x-2)(3x+2) = 10
a) 4(x - 3)2 - (2x - 1)(2x + 1) = 10
\(\Leftrightarrow\)4(x2 - 6x + 9) - (4x2 - 1) = 10
\(\Leftrightarrow\)4x2 - 24x + 36 - 4x2 + 1 - 10 = 0
\(\Leftrightarrow\)-24x + 27 = 0
\(\Leftrightarrow\)-24x = -27
\(\Leftrightarrow\)x = \(\frac{9}{8}\)
Vậy x = 9/8
b) (x - 4)2 - (x - 2)(x + 2) = 6
\(\Leftrightarrow\)x2 - 8x + 16 - x2 + 4 - 6 = 0
\(\Leftrightarrow\)-8x + 14 = 0
\(\Leftrightarrow\)-8x = -14
\(\Leftrightarrow\)x = \(\frac{7}{4}\)
Vậy x = 7/4
c) 9(x + 1)2 - (3x - 2)(3x + 2) = 10
\(\Leftrightarrow\)9(x2 + 2x + 1) - 9x2 + 4 - 10 = 0
\(\Leftrightarrow\)9x2 + 18x + 9 - 9x2 + 4 - 10 = 0
\(\Leftrightarrow\)18x + 3 = 0
\(\Leftrightarrow\)18x = - 3
\(\Leftrightarrow\)x = \(\frac{-1}{6}\)
Vậy x = -1/6
Đúng 0
Bình luận (0)
a, ->4(x^2-6x+9) - 4x^2 +1 = 10
-> 4x^2 - 24x + 36 - 4x^2 +1 = 10
-> -24x = -27
-> x = 9/8
b, -> x^2 + 8x -16 -x^2 + 4 = 6
-> 8x = 18
-> x= 9/4
c, -> 9x^2 + 18x + 9 - 9x^2 +4 =10
-> 18x = -3
-> x = -1/6
Đúng 0
Bình luận (0)
tím x a) 12 . ( x - 4 ) + 3 . ( 2x + 5 ) = 16
b) -10 . ( 2x + 4 ) - 2 . ( 6 - 15x ) = 48
ai giup mik vs mik k cho
a) => (12x-4)+(6x+15)=16
=>12x-48+6x+15=16
=>(12x+6x)-(15-48)=16
=>18x-(-33)=16
=>18x=16+(-33)
=>18x=-17
=>x=-17/18
KL
b) =>(-20x+(-40))-(12-30x)=48
=>-20x+(-40)-12+30x=48
=>(-20x+30x)+(-40-12)=48
=>10x+(-52)=48
=>10x=48-(-52)
=>10x=4
=>x=4/10
KL
Đúng 0
Bình luận (0)
a) 12( x - 4 ) + 3( 2x + 5 ) = 16
<=> 12x - 48 + 6x + 15 = 16
<=> 18x - 33 = 16
<=> 18x = 49
<=> x = 49/18
b) -10( 2x + 4 ) - 2( 6 - 15x ) = 48
<=> -20x - 40 - 12 + 30x = 48
<=> 10x - 52 = 48
<=> 10x = 100
<=> x = 10
Đúng 0
Bình luận (0)