Tìm x
a. \(2x+12-18=x+4-18\) ( quy tắc chuyển vế)
b. \(-5x+10-102=-6x-102\)
Tìm x bằng quy tắc chuyển vế :
a)-18-( x-6)=0
b)29-(10+29)= x-(27-9)
a) -(x-6)=18
-x+6=18
-x=12
a) -18-(x-6)=0
x-6=(-18)-0
x-6=-18
x = (-18)+6
x = -12
b) 29-(10+29)=x-(27-9)
29-39 = x-18
-10 =x-18
x-18=-10
x = (-10)+18
x = 8
Học tốt
Trl:
a) \(-18-\left(x-6\right)=0\)
\(\Rightarrow\left(x-6\right)=-18-0\)
\(\Rightarrow\left(x-6\right)=-18\)
\(\Rightarrow x=-18+6\)
\(\Rightarrow x=-12\)
b) \(29-\left(10+29\right)=x-\left(27-9\right)\)
\(\Rightarrow29-39=x-18\)
\(\Rightarrow-10=x-18\)
\(\Rightarrow x=18+\left(-10\right)\)
\(\Rightarrow x=28\)
Quy tắc chuyển vế ( Tìm x)
a, 2 - x = 17 - ( -5 )
b, x -12 = - 9 - 15
c , 11 - ( 15 + 11 ) = x - ( 25 - 9 )
d, 5x - ( x + 2 ) = - 6x + 10
a/ => 2 - x = 22 => x = -20
b/ => x - 12 = -24 => x = -12
c/ => 11 - 26 = x - 16
=> -15 = x - 16
=> x = 1
d/ => 5x - x - 2 + 6x - 10 = 0
=> 10x - 12 = 0
=> 10x = 12
=> x = 1,2
a) 2 - x = 17 - ( - 5)
2 - x = 22
x = 2-22
x=-20
Vận dụng các quy tắc: quy tắc chuyển vế, quy tắc dấu ngoặc, nhân phá ngoặc làm bài sau.
a) 3x - 10 = 2x + 13
b) x + 12 = - 5 - x
c) x + 5 - 10 - x
d) 6x + 2^3 = 2x - 12
e) 12 - x = x + 1
f) 14 - 4x = 3x + 20
g) 2 . ( x - 1 ) + 3 ( x - 2 ) = x - 4
h) 3 . ( 4 - x ) - 2 . ( x - 1 ) = x + 20
n) 135 - | 9 - x | = 35
o) | 2x + 3 | = 5
i) 4 . ( 2x + 7 ) - 3 . ( 3x - 2 ) = 24
k) 3 ( x - 2 ) + 2x = 10
GIÚP MÌNH VỚI MỌI NGƯỜI!
Dạng 3: vận dụng các quy tắc: qt chuyển vế,qtdấu ngoặc, nhân phá ngoặc
a)3x –10 = 2x + 13
b) x + 12 = -5 –x
c) x + 5 = 10 –x
d)6x + 23= 2x –12
e) 12 –x = x + 1
f) 14 + 4x = 3x + 20
g) 2.(x-1) + 3(x-2) = x -4
h) 3.(4 –x) –2.( x-1) = x + 20
i) 4.( 2x + 7) –3.(3x –2) = 24
k) 3(x –2) + 2x = 10
a) \(3x-10=2x+13\Leftrightarrow x=13+10=23\)
b) \(x+12=-5-x\Leftrightarrow2x=-17\Leftrightarrow x=-\frac{17}{2}\)
c) \(x+5=10-x\Leftrightarrow2x=5\Leftrightarrow x=\frac{5}{2}\)
d) \(6x+23=2x-12\Leftrightarrow4x=-35\Leftrightarrow x=-\frac{35}{4}\)
e) \(12-x=x+1\Leftrightarrow2x=11\Leftrightarrow x=\frac{11}{2}\)
f) \(14+4x=3x+20\Leftrightarrow x=20-14=6\)
g) \(2\left(x-1\right)+3\left(x-2\right)=x-4\Leftrightarrow2x-2+3x-6=x-4\)
\(\Leftrightarrow5x-8=x-4\Leftrightarrow4x=4\Leftrightarrow x=1\)
h ) \(3\left(4-x\right)-2\left(x-1\right)=x+20\Leftrightarrow12-3x-2x+2=x+20\)
\(\Leftrightarrow14-5x=x+20\Leftrightarrow6x=-6\Leftrightarrow x=-1\)
i ) \(4\left(2x+7\right)-3\left(3x-2\right)=24\Leftrightarrow8x+28-9x+6=24\)
\(\Leftrightarrow34-x=24\Leftrightarrow x=34-24=10\)
k) \(3\left(x-2\right)+2x=10\Leftrightarrow3x-6+2x=5x-6=10\)
\(\Leftrightarrow5x=10+6=16\Leftrightarrow x=\frac{16}{5}\)
Tự KL cho các phần
tìm x(=quy tắc chuyển vế)
a) 2x-(40-52)=x+12
b) 40-x=-12+3x
giúp mik với,tks
tìm x
a) 4(18-5x)-12(3x-7)=15(2x-16)-6(x+14)
b) 5(3x+5)-4(2x-3)=5x+3(2x+12)+1
c) 2(5x-8)-3(4x-5)=4(3x-4)+11
a) \(\Rightarrow72-20x-36x+84=30x-240-6x-84\)
\(\Rightarrow80x=480\Rightarrow x=6\)
b) \(\Rightarrow15x+25-8x+12=5x+6x+36+1\)
\(\Rightarrow4x=0\Rightarrow x=0\)
c) \(\Rightarrow10x-16-12x+15=12x-16+11\)
\(\Rightarrow14x=4\Rightarrow x=\dfrac{2}{7}\)
dùng quy tắc chuyển vế
a) -84-(-18-6)=x+(-20)
a) -84 - (-18 - 6) = x + (-20)
-84 + 18 + 6 = x - 20
-84 + 18 + 6 + 20 = x
=> x = -40
\(-84-\left(-18-6\right)=x+\left(-20\right)\)
\(\Leftrightarrow x=\left(-20\right)+84+\left(-18-6\right)\)
\(\Leftrightarrow x=40\)
P/s tham khảo nha
dùng quy tắc chuyển vế
a) -14-7+x=-12 b) x+(-15)-(-6)=11
c)x-[18+(-7)]=15 d) 4-x=-3-(-6)
A)
\(-14-7+x=-12\)
\(\Leftrightarrow x=-12+7+14\)
\(\Leftrightarrow x=9\)
P/s tham khảo nha
B)
\(x+\left(-15\right)-\left(-6\right)=11\)
\(\Leftrightarrow x=11+\left(-6\right)-\left(-15\right)\)
\(\Leftrightarrow x=20\)
P/s tham khảo nha
B3:Tìm x
a (x-12)+48=96
b56-(17+x)=24
c 5x+57=112
d 87-2x=65
e (x-46):32=2
g 120-3(x+1)=102
a (x-12)+48=96
x-12=96-48=48
x=12+48=60
b56-(17+x)=24
17+x=56-24
17+x=32
x=31-17=15
c 5x+57=112
5x=112-57=55
x=11
d 87-2x=65
2x=87-65=22
x=11
e (x-46):32=2
x-46=64
x=110
g 120-3(x+1)=102
3(x+1)=120-102=18
x+1=6
x=5
a: Ta có: \(\left(x-12\right)+48=96\)
\(\Leftrightarrow x-12=48\)
hay x=60
b: ta có: \(56-\left(x+17\right)=24\)
\(\Leftrightarrow x+17=32\)
hay x=15
c: Ta có: \(5x+57=112\)
\(\Leftrightarrow5x=55\)
hay x=11
d: Ta có: 87-2x=65
\(\Leftrightarrow2x=22\)
hay x=11