Question

B3:Tìm x

a (x-12)+48=96

b56-(17+x)=24

c 5x+57=112

d 87-2x=65

e (x-46):32=2

g 120-3(x+1)=102

Answer 1

a, 60

b, 15

c, 11

d, 11

e, 110

g, 5

Answer 2

a (x-12)+48=96

x-12=96-48=48

x=12+48=60

b56-(17+x)=24

17+x=56-24

17+x=32

x=31-17=15

c 5x+57=112

5x=112-57=55

x=11

d 87-2x=65

2x=87-65=22

x=11

e (x-46):32=2

x-46=64

x=110

g 120-3(x+1)=102

3(x+1)=120-102=18

x+1=6

x=5

 

Answer 3

a: Ta có: \(\left(x-12\right)+48=96\)

\(\Leftrightarrow x-12=48\)

hay x=60

b: ta có: \(56-\left(x+17\right)=24\)

\(\Leftrightarrow x+17=32\)

hay x=15

c: Ta có: \(5x+57=112\)

\(\Leftrightarrow5x=55\)

hay x=11

d: Ta có: 87-2x=65

\(\Leftrightarrow2x=22\)

hay x=11