Tìm x biết : 2011 . | x - 2011 | + ( x - 2011 )\(^2\)= 2013 . | 2011 - x |
tìm x biết (x+2014)/2011 + (x+2013)/2012 = (x+2012)/2013 + (x+2011)/2014
Tìm số hữu tỉ x biết:
a) \(\frac{x+4}{2009}+\frac{x+3}{2010}=\frac{x+2}{2011}+\frac{x+1}{2012}\)
b) \(\frac{x-2011}{2010}+\frac{x-2011}{2011}+\frac{x-2011}{2012}=\frac{x-2011}{2013}+\frac{x-2011}{2014}\)
a) \(\frac{x+4}{2009}+1+\frac{x+3}{2010}+1=\frac{x+2}{2011}+1+\frac{x+1}{2012}\)
\(\frac{x+4+2009}{2009}+\frac{x+3+2010}{2010}=\frac{x+2+2011}{2011}+\frac{x+2+2012}{2012}\)
\(\frac{x+2013}{2009}+\frac{x+2013}{2010}-\frac{x+2013}{2011}-\frac{x+2013}{2012}=0\)
\(\left(x+2013\right).\left(\frac{1}{2009}+\frac{1}{2010}-\frac{1}{2011}-\frac{1}{2012}\right)=0\) (1)
Vì \(\left(\frac{1}{2009}+\frac{1}{2010}-\frac{1}{2011}-\frac{1}{2012}\right)\ne0\)
Nên biểu thức (1) xảy ra khi \(x+2013=0\)
\(x=-2013\)
b) \(\left(x-2011\right)\left(\frac{1}{2010}+\frac{1}{2011}+\frac{1}{2012}-\frac{1}{2013}-\frac{1}{2014}\right)=0\) (2)
Vì \(\left(\frac{1}{2010}+\frac{1}{2011}+\frac{1}{2012}-\frac{1}{2013}-\frac{1}{2014}\right)\ne0\)
Nên biểu thức (2) xảy ra khi \(x-2011=0\)
\(x=2011\)
Tìm x biết
2012. | x - 2011 | + ( x - 2011 ) ^ 2 + 2013 > | 2011 - x |
=>2012|x-2011|-|x-2011|+(x-2011)^2+2013>0
=>2011|x-2011|+(x-2011)^2+2013>0(luôn đúng)
Tìm x
2012.| x-2011| +\(\left(x-2011\right)^2\)=2013.|2011-x|
2012*|x-2011|+(x-2011)^2=2013*|2011-x
Tìm x:
2012×|x-2011|+ (x-2011)^2=2013×|2011-x|
2012 . | x - 2011| + (x-2011)2 = 2013 . | 2011 - x|
|x-2011|.|x-2011| + 2012 . | x - 2011| - 2013 . | 2011- x| =0
|x - 2011|.| x - 2011| + 2012 .| x - 2011| - 2013 | x - 2011| = 0
| x- 2011| .| x -2011| - | x - 2011| = 0
| x - 2011|. { | x - 2011| - 1} = 0
\(\left[{}\begin{matrix}\left|x-2011\right|=0\\\left|x-2011\right|-1=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=2011\\x=2012\\x=2010\end{matrix}\right.\)
Kết luận x \(\in\) { 2010; 2011; 2012}
2011 x 2013 - 2012x 2011
2012 x 2011 + 2011 x 2013
\(\frac{2011.2013-2011.2012}{2012.2011+2011.2013}\)
\(=\frac{2011.\left(2013-2012\right)}{2011.\left(2012+2013\right)}\)
\(=\frac{2011.1}{2011.4025}\)
\(=\frac{1}{4025}\)
bài này là bài Tính nha mọi người giải rõ ra giúp mik nha
\(\frac{2011x2013-2012x2011}{2012x2011+2011x2013}\)
\(=\frac{2011x\left(2013-2012\right)}{2011x\left(2012+2013\right)}\)
\(=\frac{2011x1}{2011x4025}\)
\(=\frac{1}{4025}\)
Mình có bài hay lắm nè
a, tìm x biết :1/1x2+1/3x5+1/5x8+......+1/x(x+2)= 1005/2011
b, so sánh 2011/2012+2012/2013+2013/2011 và 3
giải giùm mình nha !
Câu 1 bị sai đề bài.
Câu 2:
\(\frac{2011}{2012}+\frac{2012}{2013}+\frac{2013}{2011}=\frac{2012-1}{2012}+\frac{2013-1}{2013}+\frac{2011+1+1}{2011}\)
\(=1-\frac{1}{2012}+1-\frac{1}{2013}+1+\frac{1}{2011}+\frac{1}{2011}\)
Vì:
\(\frac{1}{2011}>\frac{1}{2012};\frac{1}{2011}>\frac{1}{2013}\Rightarrow\frac{1}{2011}+\frac{1}{2011}-\frac{1}{2012}-\frac{1}{2013}>0\)
\(\Rightarrow\)\(\frac{2012-1}{2012}+\frac{2013-1}{2013}+\frac{2011+1+1}{2011}>3\)
\(\Rightarrow\frac{2011}{2012}+\frac{2012}{2013}+\frac{2013}{2011}>3\)
Tính 2 mũ76 - 2 mũ 74/ 2 mũ 78- 2 mũ 76
bài này khó lắm đó
Tìm x biết (1/2+1/3+...+1/2012+1/2013).x = 2012/1+2011/2+2010/3+...+2/2011+1/2012