\(\Leftrightarrow2011.\left|x-2011\right|+\left(x-2011\right)^2=2013.\left|x-2011\right|\)
\(\Leftrightarrow\left(x-2011\right)^2=2.\left|x-2011\right|\Rightarrow\orbr{\begin{cases}x-2011=0\\2=\left|x-2011\right|\end{cases}}\Rightarrow\orbr{\begin{cases}x=2013\\x=2009\end{cases}}\text{hoặc }x=2011\)
Vậy ....
Tìm số hữu tỉ x biết:
a) \(\frac{x+4}{2009}+\frac{x+3}{2010}=\frac{x+2}{2011}+\frac{x+1}{2012}\)
b) \(\frac{x-2011}{2010}+\frac{x-2011}{2011}+\frac{x-2011}{2012}=\frac{x-2011}{2013}+\frac{x-2011}{2014}\)
Tìm x
2012.| x-2011| +\(\left(x-2011\right)^2\)=2013.|2011-x|
Tìm x:
2012×|x-2011|+ (x-2011)^2=2013×|2011-x|
\(2012\cdot|x-2011|+\left(x-2011\right)^2=2013\cdot|2011-x|\)
Tìm x
tìm x,y biết /x-2011/ + /x-2012/ + /x-y/ + /x-2013/ = 2
Tìm x biết (x+4) /2010 + (x+3) / 2011 = (x+2) /2012 + (x+1) /2013
tìm x biết: x-1/2013 + x-2/2012 - x-3/2011= x-4/2010
Tìm x biết
\(\left(x-2011\right)^{x+1}-\left(x-2011\right)^{x+2011}=0\)
(x+4)/2011+(x+3)/2012=(x+2)/2013+(x+1)/2014.tìm x
