a; \(\dfrac{3}{5}\) - \(\dfrac{-7}{10}\) - \(\dfrac{13}{-20}\)

= \(\dfrac{12}{20}\) +  \(\dfrac{14}{20}\) + \(\dfrac{13}{20}\)

= \(\dfrac{39}{20}\)

b; \(\dfrac{1}{2}\) + \(\dfrac{1}{-3}\) + \(\dfrac{1}{4}\) - \(\dfrac{-1}{6}\)

= \(\dfrac{6}{12}\) - \(\dfrac{4}{12}\) + \(\dfrac{3}{12}\) + \(\dfrac{2}{12}\)

= \(\dfrac{7}{12}\)

\(\frac{1}{3}\cdot y+2=\frac{1}{5}\cdot y+\frac{7}{2}\)

\(=>\frac{1}{3}\cdot y-\frac{1}{5}\cdot y=\frac{7}{2}-2\)

\(=>y\cdot\left(\frac{1}{3}-\frac{1}{5}\right)=\frac{3}{2}\)

\(=>y\cdot\frac{2}{15}=\frac{3}{2}\)

\(=>y=\frac{3}{2}:\frac{2}{15}=\frac{45}{4}\)

Hai phần chín cộng ích bằng một

theo de bai ta co 1/3.y+2=1/5.y+7/2

=>y/3+2=y/5+7/2

=>y+6/3=2y+35/10

=>6y+105=10y+60

=>16y=165

=>y=165/16

Có: 7-3.\(\frac{-1}{4}^2\)

= 7-3. \(\frac{1}{16}\)

= 7- \(\frac{3}{16}\)

= \(\frac{112}{16}\)-\(\frac{3}{16}\)

= \(\frac{109}{16}\)

\(\frac{1}{2}+-\frac{1}{5}+-\frac{5}{7}+\frac{1}{6}-\frac{3}{35}+\frac{1}{3}+\frac{1}{41}=\frac{1}{41}\)

1/41 giai ra dai nam cu rut gon roi quy dong

\(\frac{1}{2}+\left(-\frac{1}{5}\right)+\left(-\frac{5}{7}\right)+\frac{1}{6}+\left(-\frac{3}{35}\right)+\frac{1}{3}+\frac{1}{41}\)

\(=\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{3}\right)+\left[\left(\frac{-1}{5}\right)+\left(-\frac{5}{7}\right)+\left(-\frac{3}{35}\right)\right]+\frac{1}{41}\)

\(=1+\left(-1\right)+\frac{1}{41}\)

=0+1/41=1/41

a 15/7"3/4

\(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{99\cdot100}\)

\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}\)

\(=1-\dfrac{1}{100}\)

\(=\dfrac{99}{100}\)

dễ, nhưng phai giai dc câu nay  60% nhan x cong 2 phan 3 = 1 phan 3 nhan 6va 1 phan 3

dễ mà