(7x-11)^3=2^5*5^2+200
(7x-11)^3 = 5^2 * 2^5 + 200
`(7x-11)^3 =5^2 *2^5 +200`
`=>(7x-11)^3 =25*32+200`
`=>(7x-11)^3 =800+200`
`=>(7x-11)^3 =1000`
`=>(7x-11)^3 =10^3`
`=>7x-11=10`
`=>7x=10+11`
`=>7x=21`
`=>x=21:7`
`=>x=3`
Đề yêu cầu làm gì em?
(5+x)^2-36=0
(7x-11)^3=2^5+5^2+200
1) \(\left(5+x\right)^2-36=0\)
\(\Rightarrow\left(5+x-6\right)\left(5+x+6\right)=0\Rightarrow\left(x-1\right)\left(x+11\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=1\\x=-11\end{matrix}\right.\)
2) \(\Rightarrow\left(7x-11\right)^3=1000=10^3\)
\(\Rightarrow7x-11=10\Rightarrow7x=21\Rightarrow x=3\)
(7x-11)^3=2^5*5^2+200
Ta có:(7x-11)3=25 * 52 + 200
=> (7x-11)3=32 * 25 + 200
=> (7x-11)3=800 + 200
=> (7x-11)3=1000 = 103
=> 7x-11 = 10
=> 7x = 21
=> x = 3
(7x -11)^3 =2^5 +5^2+200
(7x - 11) mũ 3 = 2 mũ 5 x 5 mũ 5 + 200
\(\Rightarrow\left(7x-11\right)^3=\left(2\cdot5\right)^5+200=10^5+200\\ \Rightarrow\left(7x-11\right)^3=10000+200=10200\\ \Rightarrow7x-11=\sqrt[3]{10200}\\ \Rightarrow x=\dfrac{\sqrt[3]{10200}+11}{7}\)
Tìm x biết : ( 7x - 11 )^3 = 2^5 . 5^2 + 200
( 7x - 11 )3 = 32 . 25 + 200
( 7x - 11 )3 = 800 + 200
( 7x - 11 )3 = 1000
( 7x - 11 )3 = 103
=> 7x - 11 = 10
7x = 10 + 11
7x = 21
x = 21 : 7
x = 3
=>(7x-11)^3=800+200=1000=10^3
=>7x-11=10
=>7x=21=>x=3
Vậy x=3
( 7x - 11 )3 = 25 × 52 + 200
\(\left(7x-11\right)^3=2^5\times5^2+200\)
\(\left(7x-11\right)^3=32\times25+200\)
\(\left(7x-11\right)^3=800+200\)
\(\left(7x-11\right)^3=1000\)
\(\left(7x-11\right)^3=10^3\)
\(\Rightarrow7x-11=10\)
\(7x=10+11\)
\(7x=21\)
\(x=21\div7\)
\(x=3\)
(7x-11)^3=2^5x5^2+200
(7x-11)^3=32x25+200
(7x-11)^3=800+200
(7x-11)^3=1000
(7x-11)^3=10^3
=>7x-11=10
7x=10+11
7x=21
x=21:7
x=3
Bài này nhiều người hỏi rồi nha
(7x-11)3=25.52+200
(7x-11)3=25.52+200
=>(7x-11)3=32.25+200
=>(7x-11)3=800+200
=>(7x-11)3=1000
=>(7x-11)3=103
=>7x-11=10
=>7x=10+11
=>7x=21
=>x=21:7
=>x=3
vậy x=3
(7x-11)3=25.52+200
(7x-11)3=32.25+200
(7x-11)3=1000
(7x-11)3=103
7x-11=10
7x=10+11
7x=21
x=21:7
x=3
vậy x = 3
k mình nha