Tìm x, biết:

a.

75883-(31200+x)=999

31200+x =75883-999

31200+x= 74884

x = 74884-31200

x = 43684

b.

24 : ( x +1 ) = 8 

x+1=24:8

x+1=3

x=3-1

x=2

c.

1+2+3+...+x=55

Dãy trên có số số hạng là:

(x−1):1+1=x−1+1=x

Ta có:

(x+1).x:2=55

(x+1).x=55.2

(x+1).x=110

(x+1).x=11.10

⇒x=10

a, ---> 31200 + x = 75883 - 999

---> 31200 + x = 74884

---> x = 74884 - 31200 = 43684

b, ---> x + 1 = 3

---> x = 2

c, Số số hạng là : x

Tổng = ( x + 1 ) * x : 2 = 55

---> x ( x + 1 ) = 110

---> 10 ( 10 + 1 ) = 110

---> x = 10

xin tiick

a . x=43684

b.x=2

c.x=10

a) \(8x-40=56\)

\(\Leftrightarrow8x=96\)

\(\Rightarrow x=12\)

b) \(105-3x=60\)

\(\Leftrightarrow3x=45\)

\(\Rightarrow x=15\)

c) \(75883-\left(31200+x\right)=999\)

\(\Leftrightarrow31200+x=74884\)

\(\Rightarrow x=43684\)

d) \(19-9\left(x+1\right)=10\)

\(\Leftrightarrow9\left(x+1\right)=9\)

\(\Leftrightarrow x+1=1\)

\(\Rightarrow x=0\)

e) \(\left(17x-25\right)\div8+65=81\)

\(\Leftrightarrow\left(17x-25\right)\div8=16\)

\(\Leftrightarrow17x-25=128\)

\(\Leftrightarrow17x=153\)

\(\Rightarrow x=9\)

a) 8x - 40 = 56

8x        = 56 - 40

8x        = 16

x          = 2

b)  105 - 3x  =  60

      3x           =  105 - 60 

      3x           = 45

       x             =  15

c)    75883  -  ( 31200  +  x ) = 999

       75883 - 31200 - x = 999

       44683   -  x           = 999

       x                           =  44683 - 999

       x                            =  43684

d)    19  -  9 ( x + 1 ) = 10

        19 -  9x - 9 = 10

         10  - 9x  =  10

          9x         = 0

           x           = 0

e)    ( 17x  - 25 )  : 8 + 65 = 81

         ( 17x - 25 )  : 8         = 16

             17x - 25  = 128

              17x         =  128 + 25

              17x         =  153

               x              =  9

nhầm câu a

a) x - 1/2 = 3/5

x = 3/5 + 1/2

x = 11/10

b) x - 1/2 = -2/3

x = -2/3 + 1/2

x = -1/6

c) 2/5 - x = 0,25

x = 2/5 - 0,25

x = 2/5 - 1/4

x = 3/20

Lời giải:
$x-\frac{x}{3}\times \frac{3}{2}=2-\frac{1}{2}$

$x-x\times \frac{1}{2}=\frac{3}{2}$

$x\times (1-\frac{1}{2})=\frac{3}{2}$

$x\times \frac{1}{2}=\frac{3}{2}$

$x=\frac{3}{2}: \frac{1}{2}=3$

`@` `\text {Ans}`

`\downarrow`

\(\left(\dfrac{x}{3}+\dfrac{1}{2}\right)\left(75\%-1\dfrac{1}{2}x\right)=0\)

`=>`\(\left[{}\begin{matrix}\dfrac{x}{3}+\dfrac{1}{2}=0\\\dfrac{75}{100}-\dfrac{3}{2}x=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}\dfrac{x}{3}=-\dfrac{1}{2}\\\dfrac{3}{2}x=\dfrac{75}{100}\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}2x=-1\cdot3\\x=\dfrac{75}{100}\div\dfrac{3}{2}\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}2x=-3\\x=\dfrac{1}{2}\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=-\dfrac{3}{2}\\x=\dfrac{1}{2}\end{matrix}\right.\)

Vậy, `x={-3/2; 1/2}.`

ĐKXĐ: \(x\notin\left\{1;-1\right\}\)

Ta có: \(\dfrac{x-3}{x+1}=\dfrac{x^2}{x^2-1}\)

\(\Leftrightarrow\dfrac{\left(x-3\right)\left(x-1\right)}{\left(x+1\right)\left(x-1\right)}=\dfrac{x^2}{\left(x-1\right)\left(x+1\right)}\)

Suy ra: \(x^2-4x+3-x^2=0\)

\(\Leftrightarrow-4x=-3\)

hay \(x=\dfrac{3}{4}\)(thỏa ĐK)

Vậy: \(S=\left\{\dfrac{3}{4}\right\}\)

75883 - (31200+x) = 999

=> 31200+x = 74884

=> x = 74884 - 31200

=> x = 43684

`x-1/9 =8/3`

`=>x=8/3 +1/9`

`=> x= 24/9 +1/9`

`=>x= 25/9`

Vậy `x=25/9`

__

`x-2/20=-5/2-x`

`=>x+x=-5/2 +2/20`

`=> 2x= -50/20 +2/20`

`=> 2x= -48/20`

`=> x= -12/5:2`

`=>x=-12/5 xx1/2`

`=>x= -12/10`

`=>x= -6/5`

Vậy `x=-6/5`

`@` `\text {Ans}`

`\downarrow`

`a)`

Đề là \(\dfrac{x-1}{9}=\dfrac{8}{3}\) phải hongg bạn?

\(\dfrac{x-1}{9}=\dfrac{8}{3}\)

`=>` `(x-1)3 = 8*9`

`=> (x-1)3=72`

`=> x-1=72 \div 3`

`=> x-1=24`

`=> x=25`

`b)`

\(\dfrac{x-2}{20}=\dfrac{-5}{2-x}\)

`=>` `(x-2)(2-x)=20*(-5)`

`=> (x-2)(2-x)=-100`

`=> -[(x-2)(x-2)]=-100`

`=> -(x-2)^2 = -100`

`=> (x-2)^2 = 100`

`=> (x-2)^2 = (+-10)^2`

`=>`\(\left[{}\begin{matrix}x-2=10\\x-2=-10\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=12\\x=-8\end{matrix}\right.\)