Ta có: 
               \(\frac{3}{4}+\frac{3}{28}+\frac{3}{70}+\frac{3}{130}+\frac{3}{208}\)
\(=\frac{3}{1\times4}+\frac{3}{4\times7}+\frac{3}{7\times10}+\frac{3}{10\times13}+\frac{3}{13\times16}\)
 \(=\frac{4-1}{1\times4}+\frac{7-4}{4\times7}+\frac{10-7}{7\times10}+\frac{13-10}{10\times13}+\frac{16-13}{13\times16}\)  \(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+\frac{1}{13}-\frac{1}{16}\)
 \(=1-\frac{1}{16}\)
 \(=\frac{15}{16}\)
 Chắc chắn đúng nhé !

bn hỏi vào đúng những ngày tết lk  

\(\frac{3}{4}+\frac{3}{28}+\frac{3}{70}+...+\frac{3}{10300}\)

\(=\frac{3}{1\times4}+\frac{3}{4\times7}+\frac{3}{7\times10}+...+\frac{3}{100\times103}\)

\(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{100}-\frac{1}{103}\)

\(=1-\frac{1}{103}=\frac{102}{103}\)

A=\(\frac{3}{4}+\frac{3}{28}+\frac{3}{70}+\frac{3}{130}+\frac{3}{208}+\frac{3}{304}\)

A= \(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+\frac{3}{13.16}+\frac{3}{16.19}\)

A= \(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+\frac{1}{13}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19}\)

A= 1 - \(\frac{1}{19}\)

A= \(\frac{18}{19}\)

X=3/4+3/28+...+3/304

X=3/1x4+3/4x7+....+3/13x16

X=1-1/4+1/4-1/7+....+1/13-1/16

X=1-1/16

X=15/16

k cho tớ nha Nguyễn Thu Trang 

A=3/4+3/28+3/70+3/130+3/208+3/304

  =3/1x4+3/4x7+3/7x10+3/10x13+7/13x16+7/16x19

  =3/1-3/4+3/4-3/7+3/7-3/10+3/10-3/13+3/13-3/16+3/16-3/19

  =3/1-3/19=57/19-3/19=54/19

\(\dfrac{3}{4}+\dfrac{3}{28}+\dfrac{3}{70}+\dfrac{3}{130}+\dfrac{3}{208}+\dfrac{3}{304}\\ =\dfrac{3}{1.4}+\dfrac{3}{4.7}+\dfrac{3}{7.10}+\dfrac{3}{10.13}+\dfrac{3}{13.16}+\dfrac{3}{16.19}\\ =1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{19}\\ =1-\dfrac{1}{19}=\dfrac{18}{19}\)

\(\dfrac{3}{4}+\dfrac{3}{28}+\dfrac{3}{70}+\dfrac{3}{130}+\dfrac{3}{208}+\dfrac{3}{304}\)

\(=\dfrac{3}{1\times4}+\dfrac{3}{4\times7}+\dfrac{3}{7\times10}+\dfrac{3}{10\times13}+\dfrac{3}{13\times16}+\dfrac{3}{16\times19}\)

\(=1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{19}\)

\(=1-\dfrac{1}{19}\)

=\(\dfrac{18}{19}\)

12/13

=3/1.4  + 3/4.7 + 3/7.10 + 3/13.10

=1/1 - 1/4 + 1/4 + 1/7 + 1/7 + 1/10 + 1/10 -  1/13

=8+4/13

=12/13

= \(\dfrac{3}{1.4}+\dfrac{3}{4.7}+\dfrac{3}{7.10}+\dfrac{3}{10.13}\) 

= \(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}=1-\dfrac{1}{13}=\dfrac{12}{13}\)

\(B=\frac{3}{4}+\frac{3}{28}+\frac{3}{70}+\frac{3}{130}+\frac{3}{208}+\frac{3}{304}\)

\(\Rightarrow B=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+\frac{3}{13.16}+\frac{3}{16.19}\)

\(\Rightarrow B=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+\frac{1}{13}-\frac{1}{16}+\frac{1}{16}-\frac{1}{19}\)

\(\Rightarrow B=1-\frac{1}{19}=\frac{18}{19}\)

Vậy \(B=\frac{18}{19}\)

Chúc bn học tốt

B = \(\frac{3}{4}+\frac{3}{28}+\frac{3}{70}+\frac{3}{130}+\frac{3}{208}+\frac{3}{304}\)

= \(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+\frac{3}{13.16}+\frac{3}{16.19}\)

= \(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-...+\frac{1}{13}-\frac{1}{16}\)

= \(1-\frac{1}{16}\)

= \(\frac{15}{16}\)

bài 1 tính 
`a, 45 + 128 + 55 - 28 `

`=(45 +55)+(128-28)`

`=100+ 100`

`=200`
`b, 2022.194 - 2022.94 - 2200`

`=2022.(194-94)-2200`

`=2022.100-2200`

`=202200-2200`

`=200000`

`c, 2^3 .2 -3^4 :3^2`

`=2^(3+1) - 3^(4:2)`

`=2^4 - 3^2`

`=16-9`

`=7`

`d, 560 : { 130 - [( 5 . 14 - 65 ) . 3 + 3 ]}`

`= 560 : { 130 - [(70-65) . 3 + 3 ]}`

`= 560 : [ 130 - (5 . 3 + 3 )]`

`= 560 : [ 130 - (15+3) ]`

`= 560 :(130-18)`

`=560: 112`

`=5`