a)4x(3x-1)-2(3x+1)-(x+3)
b)(2x^2-1/3xy+2y^2)(-1/2x^2y)
Làm tính chia
a, (-2x^5+3x^2-4x^3):2x^2
b, (x^3-2x^2y+3xy^2):[-1/2x]
c, (3x^2y^2+6x^2y^3-12xy):3xy
a,(3+1)(x-1)
b,5x(3x-2)
c,3x^2y+6xy^2-9xy):3xy
d,(3x^4-6x^3+4x^2):2x^y
e,(8x^4y^3-4x^3y^2+x^2y^2):2x^2y^2
làm tính chia
a, (-2x^5+3x^2-4x^3):2x^2
b, (x^3-2x^2y+3xy^2):[-1/2X]
C, (3x^2y^2+6x^2y^3-12xy):3xy
a.4x^2y-3xy^2+xy+xy-x^2y+5xy^2
b.x^2+2y^2+3xy+x^2-3y^2+4xy
c.2x^y-3xy+4xy^2-5x^2y+2xy^2
d.(2x^3+3x^2-4x+1)-(3x+4x^3-5)
Thực hiện phép chia:
a. (-2x^5+3x^2-4x^3):2x^2
b .(x^3-2x^2y+3xy^2):(-1/2x)
c. (3x^2y^2+6x^2y^3-12xy^2):3xy
d. (4x^3-3x^2y+5xy^2):0,5x
e. (18x^3y^5-9x^2y^2+6xy^2):3xy^2
f. (x^4+2x^2y^2+y^4):(x^2+y^2)
sau bạn đăng tách ra cho mn cùng giúp nhé
a, \(\left(-2x^5+3x^2-4x^3\right):2x^2=-x^3+\frac{3}{2}-2x\)
b, \(\left(x^3-2x^2y+3xy^2\right):\left(-\frac{1}{2}x\right)=-\frac{x^2}{2}+xy-\frac{3y^2}{2}\)
c, \(\left(3x^2y^2+6x^3y^3-12xy^2\right):3xy=xy+2x^2y^2-4y\)
d, \(\left(4x^3-3x^2y+5xy^2\right):\frac{1}{2}x=2x^2-\frac{3xy}{2}+\frac{5y^2}{2}\)
e, \(\left(18x^3y^5-9x^2y^2+6xy^2\right):3xy^2=6x^2y^3-3x+2\)
f, \(\left(x^4+2x^2y^2+y^4\right):\left(x^2+y^2\right)=\left(x^2+y^2\right)^2:\left(x^2+y^2\right)=x^2+y^2\)
rút gọn các biểu thức sau:
a)5x^2(3x^2-7x+2)-15x(x-3)
b)2/3xy(2x^2y-3xy+y^2)-2/3xy^3
c) (x+3)(x-3)-(x-2)(x+1)
d) (2x+1)^2+(4x-1)^2+2(2x+1)(4x-1)
e) (2x^2-3x)(5x^2-2x+1)-10x(x+3)
a) 5x2 ( 3x2 -7x+2)-15x(x-3)
=15x4-35x3+10x2-15x2+45x
=15x4-35x3-5x2+45x
c) (x+3)(x-3)(x-2)(x+1)
=(x2-9)(x2+x-2x-2)
=(x2-9)(x2-x-2)
=x4-x3-2x2-9x2+9x+18
=x4-x3-11x2+9x+18
d)(2x+1)2+(4x-1)2+2(2x+1)(4x+1)
=2x2+4x+1-16x2-8x+1
=2x2+4x+1-16x2-8x+1+16x2-4x+8x-2
=2x2+7
e) (2x2-3x)(5x2-2x+1)-10x2(x+3)
=10x4 -4x3+2x2-15x3+6x2-3 -10x2-30x
=10x4-19x3-2x2-30x-3
A = \(\dfrac{5xy^2-3z}{3xy}+\dfrac{4x^2y+3z}{3xy}\)
B = \(\dfrac{3y+5}{y-1}+\dfrac{-y^2-4y}{1-y}+\dfrac{y^2+y+7}{y-1}\)
C = \(\dfrac{6x}{x^2-9}+\dfrac{5x}{x-3}+\dfrac{x}{x+3}\)
D = \(\dfrac{1-3x}{2x}+\dfrac{3x-2}{2x-1}+\dfrac{3x-2}{2x-4x^2}\)
E = \(\dfrac{x^3+2x}{x^3+1}+\dfrac{2x}{x^2-x+1}+\dfrac{1}{x+1}\)
b: \(B=\dfrac{3y+5}{y-1}-\dfrac{-y^2-4y}{y-1}+\dfrac{y^2+y+7}{y-1}\)
\(=\dfrac{3y+5+y^2+4y+y^2+y+7}{y-1}\)
\(=\dfrac{2y^2+8y+12}{y-1}\)
1, ( x+1/3)^3
2, ( 2x+y^2)^3
3, ( 1/2x^2+1/3y)^3
4, ( 3x^2-2y)^3
5, ( 2/3x^2-1/2y)^3
6, ( 2x+1/2)^3
7, ( x-3)^3
8, ( x+1).(X^2+3x+9)
9, ( x-3).( x^2+3x+9)
10, ( x-2).( x^2+2x+4)
11, ( x+4).( x^2-4x+16)
12, ( x-3y).( x^2+3xy+9y^2)
13, ( x^2-1/3). ( x^4+1/3x^2+1/9)
14, ( 1/3x+2y).( 1/9x^2-2/3xy+4y^2)
Đưa về HĐT
2) tính a)3x(3x+6). b)-1/2xy(4x^2+6x). c)-2x^2y^3(1/2xy+4y^2). d)-6x^2(1/3xy^2-1/2y)
\(a,3x\left(3x+6\right)=9x^2+18x\)
\(b,-\dfrac{1}{2}xy\left(4x^2+6x\right)\)
\(=-2x^3y-3x^2y\)
\(c,-2x^2y^3\left(\dfrac{1}{2}xy+4y^2\right)\)
\(=-x^3y^4-8x^2y^5\)
\(d,-6x^2\left(\dfrac{1}{3}xy^2-\dfrac{1}{2}y\right)\)
\(=-2x^3y^2+3x^2y\)
#\(Urushi\)
a) 3x(3x+6) = 9x^2 + 18x b) -1/2xy(4x^2+6x) = -2x^3y - 3xy c) -2x^2y^3(1/2xy+4y^2 ) = -x^2y^2 - 8x^2y^5 d) -6x^2(1/3xy^2-1/2y) = -2xy + 3x^2y
Vậy kết quả của các biểu thức là: a) 9x^2 + 18x b) -2x^3y - 3xy c) -x^2y^2 - 8x^2y^5 d) -2xy + 3x^2y