Ai biết giúp mình nha T-T

Mình ko biết nữa,ai biết thì giúp mình nha.

Hình như đề sai.

( x + 2 ) ( x² - 2x ) - 3x - 6

= ( x + 2 ) ( x² - 2x ) - ( 3x + 6 )

= ( x + 2 ) ( x² - 2x ) - 3 ( x + 2 )

= ( x + 2 ) ( x² - 2x - 3 )

= ( x + 2 ) [ ( x² + x ) - ( 3x + 3 ) ]

= ( x + 2 ) [ x ( x + 1 ) - 3 ( x + 1 ) ]

= ( x + 2 ) ( x - 3 ) ( x + 1 ) 

( x + 2 )( x² - 2x ) - 3x - 6

= ( x + 2 )( x² - 2x ) - 3( x + 2 )

= ( x + 2 )( x² - 2x - 3 )

= ( x + 2 )[ ( x² - 2x + 1 ) - 4 ]

= ( x + 2 )[ ( x - 1 )² - 2² ]

= ( x + 2 )( x - 1 - 2 )( x - 1 + 2 )

= ( x + 2 )( x - 3 )( x + 1 )

\(x^6-x^4+2x^3+2x\)

\(=x\left(x^5-x^3+2x^2+2\right)\)

p/s: chúc bạn học tốt

\(x^6-x^4+2x^3+2x\)

\(=x^5x-x^3x+2x^2x+2x\)

\(=x\left(x^5-x^3+2x^2+2\right)\)

\(x^3-2x^2=x^2\left(x-2\right)\)

\(y^2+2y+1-x^2=\left(y+1\right)^2-x^2=\left(y+1-x\right)\left(y+1+x\right)\)

\(x^2-x-6=x^2+2x-3x-6=x\left(x+2\right)-3\left(x+2\right)=\left(x-3\right)\left(x+2\right)\)

\(x^6+2x^5+x^4-2x^3-2x^2+1=\left(x^3+x^2-1\right)^2\)

dễ ẹc!!!!!!!!

\(2x^2+x-6\)

\(=2x^2+4x-3x-6\)

\(=2x\left(x+2\right)-3\left(x+2\right)\)

\(=\left(2x-3\right)\left(x+2\right)\)

Đề lỗi hay sao í bạn. Bạn xem lại đề!

a) x³-2x²-x+2

=x(x²-1)+2(-x²+1)

=x(x²-1)-2(x²-1)

=(x²-1)(x-2)

b)

x²+6x-y²+9

=x²+6x+9-y²

=(x+3)²-y²

^{=(x+3-y)(x+3+y)}