phân tích đa thức sau thành nhân tử
1,3x^2+x-2
2, 2x^2-3xy-2y^2
3, 2x^2-3xy-2y^2
4, x^2+4xy+2x+3y^2+6
5, x^8+x+1
Tìm x,y biết
1, x^2+2x+5+y^2-4y=0
2,4x^2+y^4-20x-2y=26=0
Những câu hỏi liên quan
phân tích đa thức sau thành nhân tử1,3x 2 x 22, 2x 2 3xy 2y 23, 2x 2 3xy 2y 24, x 2 4xy 2x 3y 2 65, x 8 x 1Tìm x,y biết1, x 2 2x 5 y 2 4y 02,4x 2 y 4 20x 2y 26 0
đa thức lớp 5 hả bạm
mình ghi sao đề, các bạn ko cần làm đâu
Xem thêm câu trả lời
Biết x+y=0,tính giá trị của đa thức sau :
C=2x+2y+3xy(x+y)+5(x^3y^2)+2
D= 3xy(x+y)+2x^3y+2x^2y^2+5
Bài 1: Phân tích đa thức thành nhân tử
1. 5x-10-xy+2y
2.2x^2+2y^2-4xy-xz+yz
3.5x^2y-10xy^2
4.3x^2-6xy+3y^2-12z^2
5.x^2+4xy-16+4y^2
6.7x-6x^2-2
7.(2x+y)^2+x(2x+y)
8.x(x-y)+5x-5y
9.x^2-y^2+2x+1
10.x^3-9x
11.xy-2y+x-2
12.x^3-3x^2-4x+12
13.3x-x^2-2xy+3y-y^2
\(1,=\left(x-2\right)\left(5-y\right)\\ 2,=2\left(x-y\right)^2-z\left(x-y\right)=\left(x-y\right)\left(2x-2y-z\right)\\ 3,=5xy\left(x-2y\right)\\ 4,=3\left(x^2-2xy+y^2-4z^2\right)=3\left[\left(x-y\right)^2-4z^2\right]\\ =3\left(x-y-2z\right)\left(x-y+2z\right)\\ 5,=\left(x+2y\right)^2-16=\left(x+2y-4\right)\left(x+2y+4\right)\\ 6,=-\left(6x^2-3x-4x+2\right)=-\left(2x-1\right)\left(3x-2\right)\\ 7,=\left(2x+y\right)\left(2x+y+x\right)=\left(2x+y\right)\left(3x+y\right)\\ 8,=\left(x-y\right)\left(x+5\right)\\ 9,=\left(x+1\right)^2-y^2=\left(x-y+1\right)\left(x+y+1\right)\\ 10,=\left(x^2-9\right)x=x\left(x-3\right)\left(x+3\right)\\ 11,=\left(x-2\right)\left(y+1\right)\\ 12,=\left(x-3\right)\left(x^2-4\right)=\left(x-3\right)\left(x-2\right)\left(x+2\right)\\ 13,=3\left(x+y\right)-\left(x+y\right)^2=\left(x+y\right)\left(3-x-y\right)\)
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Phân tích mỗi đa thức sau thành nhân tử
a)x^3-2x^2y+xy^2+xy
b)x^3+4x^2y+4xy^2-9x
c)x^3-y^3+x-y
d)4x^2-4xy+2x-y+y^2
e)9x^2-3x+2y-4y^2
f)3x^2-6xy+3y^2-5x+5y
a) Xem lại đề
b) x³ - 4x²y + 4xy² - 9x
= x(x² - 4xy + 4y² - 9)
= x[(x² - 4xy + 4y² - 3²]
= x[(x - 2y)² - 3²]
= x(x - 2y - 3)(x - 2y + 3)
c) x³ - y³ + x - y
= (x³ - y³) + (x - y)
= (x - y)(x² + xy + y²) + (x - y)
= (x - y)(x² + xy + y² + 1)
d) 4x² - 4xy + 2x - y + y²
= (4x² - 4xy + y²) + (2x - y)
= (2x - y)² + (2x - y)
= (2x - y)(2x - y + 1)
e) 9x² - 3x + 2y - 4y²
= (9x² - 4y²) - (3x - 2y)
= (3x - 2y)(3x + 2y) - (3x - 2y)
= (3x - 2y)(3x + 2y - 1)
f) 3x² - 6xy + 3y² - 5x + 5y
= (3x² - 6xy + 3y²) - (5x - 5y)
= 3(x² - 2xy + y²) - 5(x - y)
= 3(x - y)² - 5(x - y)
= (x - y)[(3(x - y) - 5]
= (x - y)(3x - 3y - 5)
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1/ tìm GTNN
4x^2+y^2-4x-2y+3
X^2+y^2+2*(x-2y)y+6
2 phân tich đa thức thành nhân tử
(x+y)^2-25(x+y)+24
2x^3y-2xy-4xy-2xy
y^2 +3xy+3y^2 (y#0)
(x^2+4x+8)^2-3x(x^2+4x+8) +x^2
x^3-y^3-3x+3y
x^4+6x^2+13x^2+12x+4
phân tích thành nhân tử
`3x^2 -3xy-5x+5y`
`2x^3 y-2xy^3 -4xy^2 -2xy`
`x^2 -1+2x-y^2`
`x^2 +4x-2xy-4y+4y^2`
`x^3 -2x^2 +x`
`2x^2 +4x+2-2y^2`
a) \(3x^2-3xy-5x+5y\)
\(=\left(3x^2-3xy\right)-\left(5x-5y\right)\)
\(=3x\left(x-y\right)-5\left(x-y\right)\)
\(=\left(x-y\right)\left(3x-5\right)\)
b) \(2x^3y-2xy^3-4xy^2-2xy\)
\(=2xy\left(x^2-y^2-2y-1\right)\)
\(=2xy\left[x^2-\left(y^2+2y+1\right)\right]\)
\(=2xy\left[x^2-\left(y+1\right)^2\right]\)
\(=2xy\left(x-y-1\right)\left(x+y+1\right)\)
c) \(x^2+1+2x-y^2\)
\(=\left(x^2+2x+1\right)-y^2\)
\(=\left(x+1\right)^2-y^2\)
\(=\left(x+1+y\right)\left(x+1-y\right)\)
d) \(x^2+4x-2xy-4y+y^2\)
\(=\left(x^2-2xy+y^2\right)+\left(4x-4y\right)\)
\(=\left(x-y\right)^2+4\left(x-y\right)\)
\(=\left(x-y\right)\left(x-y+4\right)\)
e) \(x^3-2x^2+x\)
\(=x\left(x^2-2x+1\right)\)
\(=x\left(x-1\right)^2\)
f) \(2x^2+4x+2-2y^2\)
\(=2\left(x^2+2x+1-y^2\right)\)
\(=2\left[\left(x^2+2x+1\right)+y^2\right]\)
\(=2\left[\left(x+1\right)^2-y^2\right]\)
\(=2\left(x-y+1\right)\left(x+y+1\right)\)
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a: =3x(x-y)-5(x-y)
=(x-y)(3x-5)
b: \(=2xy\left(x^2-y^2-2y-1\right)\)
\(=2xy\left[x^2-\left(y^2+2y+1\right)\right]\)
\(=2xy\left(x-y-1\right)\left(x+y+1\right)\)
d:
Sửa đề: x^2+4x-2xy-4y+y^2
=x^2-2xy+y^2+4x-4y
=(x-y)^2+4(x-y)
=(x-y)(x-y+4)
e: =x(x^2-2x+1)
=x(x-1)^2
f: =2(x^2+2x+1-y^2)
=2[(x+1)^2-y^2]
=2(x+1+y)(x+1-y)
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1.Tính \(\dfrac{x}{x+2}-\dfrac{x}{x-2}\)
2.Phân tích đa thức thành nhân tử
1)\(\left(x^2y^2-8\right)-1\)
2)\(x^3y-2x^2y+xy-xy^3\)
3)\(x^3-2x^2y+xy^2\)
4)\(x^2+2x-y^2+1\)
5)\(x^2+2x-4y^2+1\)
6)\(x^2-6x-y^2+9\)
bài 1: ĐKXĐ: \(x\notin\left\{2;-2\right\}\)
\(\dfrac{x}{x+2}-\dfrac{x}{x-2}\)
\(=\dfrac{x\left(x-2\right)-x\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}\)
\(=\dfrac{x^2-2x-x^2-2x}{\left(x-2\right)\left(x+2\right)}=-\dfrac{4x}{x^2-4}\)
Bài 2:
1: \(x^2y^2-8-1\)
\(=x^2y^2-9\)
\(=\left(xy-3\right)\left(xy+3\right)\)
2: \(x^3y-2x^2y+xy-xy^3\)
\(=xy\cdot x^2-xy\cdot2x+xy\cdot1-xy\cdot y^2\)
\(=xy\left(x^2-2x+1-y^2\right)\)
\(=xy\left[\left(x-1\right)^2-y^2\right]\)
\(=xy\left(x-1-y\right)\left(x-1+y\right)\)
3: \(x^3-2x^2y+xy^2\)
\(=x\cdot x^2-x\cdot2xy+x\cdot y^2\)
\(=x\left(x^2-2xy+y^2\right)=x\left(x-y\right)^2\)
4: \(x^2+2x-y^2+1\)
\(=\left(x^2+2x+1\right)-y^2\)
\(=\left(x+1\right)^2-y^2\)
\(=\left(x+1+y\right)\left(x+1-y\right)\)
5: \(x^2+2x-4y^2+1\)
\(=\left(x^2+2x+1\right)-4y^2\)
\(=\left(x+1\right)^2-4y^2\)
\(=\left(x+1-2y\right)\left(x+1+2y\right)\)
6: \(x^2-6x-y^2+9\)
\(=\left(x^2-6x+9\right)-y^2\)
\(=\left(x-3\right)^2-y^2=\left(x-3-y\right)\left(x-3+y\right)\)
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giải phương trình :
a) x^2+2y^2-2xy+4x-3y-26=0
b)x^2+3y^2+2xy-2x-4y-3=0
c)2x^2+y^2+3xy+3x+2y+2=0
d)3x^2-y^2-2xy-2x-2y+8=0
Xem chi tiết
a) x^2+2y^2-2xy+4x-3y-26=0
b)x^2+3y^2+2xy-2x-4y-3=0
c)2x^2+y^2+3xy+3x+2y+2=0
d)3x^2-y^2-2xy-2x-2y+8=0
giải phương trình :
a) x^2+2y^2-2xy+4x-3y-26=0
b)x^2+3y^2+2xy-2x-4y-3=0
c)2x^2+y^2+3xy+3x+2y+2
d)3x^2-y^2-2xy-2x-2y+8=0
Xem chi tiết
a) x^2+2y^2-2xy+4x-3y-26=0
b)x^2+3y^2+2xy-2x-4y-3=0
c)2x^2+y^2+3xy+3x+2y+2
d)3x^2-y^2-2xy-2x-2y+8=0