[(x-2)3-11]3=46
3(1/11) x 27(27/46) x 1(6/17) x 2(4/7)=....
282 là đúng mình làm trên Violympic rồi
3(1/11) x 27(27/46) x 1(6/17) x 2(4/9)=
3\(\dfrac{1}{11}\) x \(\dfrac{27}{46}\) x 1\(\dfrac{6}{17}\) x 2 \(\dfrac{4}{9}\)
(11/5+3/5×x) =3/4
(3/15-x) ×1/3=2/5
X÷46/15=25/12
3/4+2×|2x-2/3|=2
X÷3/4+1/4=2/3
1) (x-2).(x+4)=0
2) (x-2).(x+15)=0
3) (7-x).(x+19)=0
4) -5<x<1
5) (x-3)(x-5)<0
6) 2x2-3=29
7) -6x-(-7)=25
8) 46-(x-11) = -48
1) \(\left(x-2\right)\left(x+4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)
2) \(\left(x-2\right)\left(x+15\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-2=0\\x+15=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-15\end{matrix}\right.\)
3) \(\left(7-x\right)\left(x+19\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}7-x=0\\x+19=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=7\\x=-19\end{matrix}\right.\)
4) \(-5< x< 1\)
\(\Rightarrow x\in\left\{-1;-3;-2;-1;0\right\}\)
5) \(\left(x-3\right)\left(x-5\right)< 0\)
\(\Rightarrow\left[{}\begin{matrix}x-3>0\\x-5< 0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x>3\\x< 5\end{matrix}\right.\)
\(\Rightarrow3< x< 5\)
6) \(2x^2-3=29\)
\(\Rightarrow2x^2=29+3\)
\(\Rightarrow2x^2=32\)
\(\Rightarrow x^2=\dfrac{32}{2}\)
\(\Rightarrow x^2=16\)
\(\Rightarrow x^2=4^2\)
\(\Rightarrow\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
7) \(-6x-\left(-7\right)=25\)
\(\Rightarrow-6x+7=25\)
\(\Rightarrow-6x=25-7\)
\(\Rightarrow-6x=18\)
\(\Rightarrow x=\dfrac{18}{-6}\)
\(\Rightarrow x=-3\)
8) \(46-\left(x-11\right)=-48\)
\(\Rightarrow x-11=48+46\)
\(\Rightarrow x-11=94\)
\(\Rightarrow x=94+11\)
\(\Rightarrow x=105\)
1: (x-2)(x+4)=0
=>x-2=0 hoặc x+4=0
=>x=2 hoặc x=-4
2: (x-2)(x+15)=0
=>x-2=0 hoặc x+15=0
=>x=2 hoặc x=-15
3: (7-x)(x+19)=0
=>7-x=0 hoặc x+19=0
=>x=7 hoặc x=-19
4: -5<x<1
=>\(x\in\left\{-4;-3;-2;-1;0\right\}\)
5: (x-3)(x-5)<0
=>x-3>0 và x-5<0
=>3<x<5
6: 2x^2-3=29
=>2x^2=32
=>x^2=16
=>x=4 hoặc x=-4
7: -6x-(-7)=25
=>-6x=25-7=18
=>x=-3
8: 46-(x-11)=-48
=>x-11=46+48=94
=>x=94+11=105
Bài 2:Phân tích đa thức sau thành nhân tử:
6,(x+2).(x+3).(x+4)
7,x^2-2xy+y^2+3x-3y
8,x^4+4
9,4x.(x+1)^2-5x^2.(x+1)-4.(x+1)
10,(1+2x).(1-2x)-(x+2).(x-2)
11,a^2-2a-46^2-46
7,x2-2xy+y2+3x-3y=(x-y)2+3(x-y)=(x-y)(x-y+3)
8,x4+4=(x4+4x2+4)-4x2=(x2+2)2-(2x)2=(x2-2x+2)(x2+2x+2)
9,4x(x+1)2-5x2(x+1)-4.(x+1)=(x+1)\(\left[4x\left(x+1\right)-5x^2-4\right]\)=(x+1)(4x2+4x-5x2-4)=(x+1)(-x2+4x-4)=-(x+1)(x-2)2
7: \(x^2-2xy+y^2+3x-3y\)
\(=\left(x-y\right)^2+3\cdot\left(x-y\right)\)
\(=\left(x-y\right)\left(x-y+3\right)\)
8: \(x^4+4\)
\(=x^4+4x^2+4-4x^2\)
\(=\left(x^2+2\right)^2-4x^2\)
\(=\left(x^2-2x+2\right)\left(x^2+2x+2\right)\)
9: \(4x\left(x+1\right)^2-5x^2\left(x+1\right)-4\left(x+1\right)\)
\(=\left(x+1\right)\left(4x^2+4x-5x^2-4\right)\)
\(=\left(x+1\right)\left(-x^2+4x-4\right)\)
\(=-\left(x+1\right)\left(x-2\right)^2\)
10: \(\left(1+2x\right)\left(1-2x\right)-\left(x+2\right)\left(x-2\right)\)
\(=1-4x^2-x^2+4\)
\(=-5x^2+5\)
\(=-5\left(x-1\right)\left(x+1\right)\)
3 và 1/11 x 27 và 27/46 x 1 và 6/17 x 2 và 4/7 =
Tìm x biết:
(x-2).(x+4)=0
2x2 - 3 = 29
46 - (x-11)= -48
a) (x-2).(x+4)=0
<=> hoặc x-2=0 hoặc x+4=0
<=> hoặc x=2 hoặc x=-4
Vậy x \(\in\){-4;2}
b) 2x2-3=29
=> 2x2=32
=> x2=16
<=> x=4
c) 45-(x-11)=-48
x-11 = 45-(-48)
x-11 = 45+48
x-11 = 93
x = 93+11
x = 104
1. Tính:
3 và 1/11 x 27 và 27/46 x 1 và 6/17 x 2 và 4/9
=88.57596425 nha bn.