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Nước đến chân thì éc ô éc hả? (;

Hàm số bậc hai luôn dương khi a > 0 và b² - 4ac < 0

`#3107.101107`

\(A=1+3+3^2+3^3+...+3^{101}\)

$A = (1 + 3 + 3^2) + (3^3 + 3^4 + 3^5) + ... + (3^{99} + 3^{100} + 3^{101}$

$A = (1 + 3 + 3^2) + 3^3 (1 + 3 + 3^2)  + ... + 3^{99}(1 + 3 + 3^2)$

$A = (1 + 3 + 3^2)(1 + 3^3 + ... + 3^{99})$

$A = 13(1 + 3^3 + ... + 3^{99})$

Vì `13(1 + 3^3 + ... + 3^{99}) \vdots 13`

`\Rightarrow A \vdots 13`

Vậy, `A \vdots 13.`

\(A=1+3+3^2+3^3+3^4+3^5+...+3^{101}\\=(1+3+3^2)+(3^3+3^4+3^5)+(3^6+3^7+3^8)+...+(3^{99}+3^{100}+3^{101})\\=13+3^3\cdot(1+3+3^2)+3^6\cdot(1+3+3^2)+...+3^{99}\cdot(1+3+3^2)\\=13+3^3\cdot13+3^6\cdot13+...+3^{99}\cdot13\\=13\cdot(1+3^3+3^6+...+3^{99})\)

Vì \(13\cdot(1+3^3+3^6...+3^{99}\vdots13\)

nên \(A\vdots13\)

\(\text{#}Toru\)

b) Tia tới hợp vs tia phản xạ một góc 90* và tia phản xạ hợp vs mặt gương một góc 8* bằng vs số đo vs tia tới hợp vs mặt gương

a)

b) Nhận xét:

-Tia tới và tia phản xạ có góc tới và góc phản xạ bằng nhau

-Tia tới hợp với gương G1 bằng tia phản xạ hợp với gương G2

?????????????????

J v bạn

Bn có thể ns lại đề bài 1 cáh cụ thể ko

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Ngô Sĩ Liên sinh : thế kỉ XV, mất : 20 tháng tám âm lịch. ( Không rõ )

Ngô Sĩ Liên sinh vào thế kỉ XV và mất vào ngày 20 tháng 8 âm lịch( và năm mất không rõ)

TL :

  + Chảy máu ở tĩnh mạch: chảy chậm, ít. Có thể sơ cứu tại chỗ bằng băng dán hay gạc (nếu vết thương sâu thì nên đến bệnh viện).

    + Chảy máu ở động mạch: chảy mạnh do vẫn tốc máu trong mạch lớn, chảy thành tia gây nguy hiểm, cần sơ cứu tạm thời và đưa ngay đến bệnh viện.

HT