x^4 -4*(x^2+5)-25 giải dùm ạ
Tìm x:
a, x : 2 = \(\dfrac{2}{3}+\dfrac{3}{4}\) b,X x \(\dfrac{1}{5}=1-\dfrac{3}{25}\)
hì mn giải dùm em nha
a) X : 2 = 2/3 + 3/4
X : 2 = 17/12
X = 17/12 x 2
X = 17/6
b) X x 1/5 = 1 - 3/25
X x 1/5 = 22/25
X = 22/25 : 1/5
X = 22/5
a) x:2= 17/12
x = 17/12 x 2
x= 17/6
b) X x 1/5 = 22/25
x = 22/15:1/5
x = 22/5
Các bạn giải dùm mình nhé!
(x-1)(x^2-2x+2)
(5-x)(x^2+5x+25)+(4+x)(x^2-4x+16)
(9x^2-7x-2):(x-1)
Tìm x, biết:
a) 1+3+5+7+...+x=330
b) 2+4+6+8+...+x=60
c) 1+4+7+10+...+x=25
Mọi người giải dùm mình nha! ^_^
Arigatou~))
\(a,1+3+5+7+...+x=330\)
SSH : \((x-1):1+1=x\)
Tổng : \(\frac{(1+x)\cdot x}{2}\)
Áp dụng phương pháp đó rồi làm thôi :v
Mấy bài kia cũng tương tự như thế thui
2,5- 4/5 + 7/2 giải dùm ạ
Tìm x
a) x^2 - 2x + 1 = 25
b) ( 5 - 2x )^ 2 + 1 = 25
giải nhanh dùm
Ta có : x2 - 2x + 1 = 25
=> x2 - 2.x.1 + 12 = 25
=> (x - 1)2 = 25
Mà 25 = 52 ; (-5)2
=> \(\orbr{\begin{cases}\left(x-1\right)^2=5^2\\\left(x-1\right)^2=\left(-5\right)^2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x-1=5\\x-1=-5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=6\\x=-4\end{cases}}\)
Vậy x = {-4;6}
b) (5 - 2x)2 + 1 = 25
<=> (5 - 2x)2 = 24
\(\Rightarrow\orbr{\begin{cases}5-2x=\sqrt{24}\\5-2x=-\sqrt{24}\end{cases}}\Rightarrow\orbr{\begin{cases}2x=5-2\sqrt{6}\\2x=5+2\sqrt{6}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{5-2\sqrt{6}}{2}\\x=\frac{5+2\sqrt{6}}{2}\end{cases}}\)
*hơi ngu toán nên nhờ mọi ngừi chỉ dùm ạ ;-; *
25 x 46 + 5 x 5 x 40 + 25 x 14.
25 x 46 + 5 x 5 x 40 + 25 x 14
= 25 x 46 + 25 x 40 + 25 x 14
= 25 x ( 46 + 40 + 14 )
= 25 x 100
= 2500
_HT_
25 x 46 + 5 x 5 x 40 + 25 x 14
= 25 x 46 + 25 x 40 + 25 x 14
= 25 x (46 + 40 + 14)
= 25 x 100
= 2 500
=1150 + 800 + 350
= 1950 + 350
=2300
T I C K cho mik nha
giupsmik giải đề này nhanh đc ko ạ tìm x
6-2(x-1)=4 2*(x-2)+1=7 (2*x-3)+4=9 (3*x-2)-1=3
2*(6-x)+1=5 20+(x-2)=25 (10-2:x)-1=3
3*(4+2*x)-1=8 (x+2)-5=7 (3+2*x)-1=2
\(6-2\left(x-1\right)=4\)
\(\Rightarrow2\left(x-1\right)=6-4\)
\(\Rightarrow2\left(x-1\right)=2\)
\(\Rightarrow x-1=1\)
\(\Rightarrow x=1+1=2\)
________________
\(2\cdot\left(x-2\right)+1=7\)
\(\Rightarrow2\cdot\left(x-2\right)=7-1\)
\(\Rightarrow2\cdot\left(x-2\right)=6\)
\(\Rightarrow x-2=3\)
\(\Rightarrow x=3+2=5\)
_______________
\(\left(2\cdot x-3\right)+4=9\)
\(\Rightarrow2\cdot x-3=5\)
\(\Rightarrow2\cdot x=3+5\)
\(\Rightarrow2\cdot x=8\)
\(\Rightarrow x=\dfrac{8}{2}=4\)
________________
\(\left(3\cdot x-2\right)-1=3\)
\(\Rightarrow3\cdot x-2=3+1\)
\(\Rightarrow3\cdot x-2=4\)
\(\Rightarrow3\cdot x=6\)
\(\Rightarrow x=\dfrac{6}{3}=2\)
a: =>2(x-1)=2
=>x-1=1
=>x=2
b: =>2(x-2)=6
=>x-2=3
=>x=5
c; =>2x-3=5
=>2x=8
=>x=4
d: =>3x-2=4
=>3x=6
=>x=2
e: =>2(6-x)=4
=>6-x=2
=>x=4
f: =>x-2=5
=>x=7
g: =>10-2x=4
=>2x=6
=>x=3
h: =>2x+4=3
=>2x=-1
=>x=-1/2
j: =>x+2=12
=>x=10
l: =>2x+3=3
=>2x=0
=>x=0
\(6-2\left(x-1\right)=4\\ 2\left(x-1\right)=6-4=2\\ x-1=\dfrac{2}{2}=1\\ x=1+1=2\)
\(2\left(6-x\right)+1=5\\ 2\left(6-x\right)=5-1=4\\ 6-x=\dfrac{4}{2}=2\\ x=6-2=4\)
\(\left(4+2x\right)-1=8\\ 3\left(4+2x\right)=8+1=9\\ 4+2x=\dfrac{9}{3}=3\\ 2x=3-4=-1\\ x=-\dfrac{1}{2}\)
\(2\left(x-2\right)+1=7\\ 2\left(x-2\right)=7-1=6\\ x-2=\dfrac{6}{2}=3\\ x=3+2=5\)
\(20+\left(x-2\right)=25\\ x-2=25-20=5\\ x=5+2=7\)
\(\left(x+2\right)-5=7\\ x+2=7+5=12\\ x=12-2=10\)
\(\left(2x-3\right)+4=9\\ 2x-3=9-4=5\\ 2x=5+3=8\\ x=\dfrac{8}{2}=4\)
\(\left(10-\dfrac{2}{x}\right)-1=3\\ 10-\dfrac{2}{x}=3+1=4\\ \dfrac{2}{x}=10-4=6\\ x=\dfrac{2}{6}=\dfrac{1}{3}\)
\(\left(3+2x\right)-1=3\\ 3+2x=3+1=4\\ 2x=4-3=1\\ x=\dfrac{1}{2}\)
\(\left(3x-2\right)-1=3\\ 3x-2=3+1=4\\ 3x=4+2=6\\ x=\dfrac{6}{3}=2\)
Tìm x:
x-5/25=4/x-5
Mn cho mik cách giải ạ
Cảm ơn nhiều ạ
(x-5) . (x-5)=25.4
(x-5) . (x-5)=100
10.10=100
Vậy x=15
\(\frac{x-5}{25}=\frac{4}{x-5}\)
\(\Leftrightarrow\left(x-5\right)\left(x-5\right)=25.4\)
\(\left(x-5\right)^2=100\)
\(\left(x-5\right)^2=\pm10^2\)
\(\Rightarrow\hept{\begin{cases}x-5=10\\x-5=-10\end{cases}\Rightarrow\hept{\begin{cases}x=15\\x=-5\end{cases}}}\)
(x-2)/2017+(x-5)/2014=(x-8)/2011+(x-11)/2008
giải dùm mình với ạ