​​\(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}\)

=\(\frac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}\)

=\(\frac{11\cdot3^{29}-3^{29}\cdot3}{2^2\cdot3^{28}}\)

=\(\frac{3^{29}\cdot\left(11-3\right)}{2^2\cdot3^{28}}\)

=\(\frac{3^{29}\cdot2^3}{2^2\cdot3^{28}}\)

=\(\frac{3\cdot2}{1}\)

=6

\(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}\)

\(A=\frac{11.3^{29}-3^{30}}{4.3^{28}}\)

\(A=\frac{3^{29}.\left(11-3\right)}{4.3^{28}}\)

\(A=\frac{3^{29}.8}{4.3^{28}}=3.2=6\)

\(\Rightarrow A=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}\)

\(\Rightarrow A=\frac{11.3^{29}-3^{29}.3}{2^2.3^{28}}\)

\(\Rightarrow A=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)

\(\Rightarrow A=\frac{3^{29}.2^3}{2^2.3^{28}}\)

\(\Rightarrow A=3.2\)

=> A=6

A = 11 . 3²⁹ - ( 3²)¹⁵ /2² .3²⁸

A=  3²⁹. ( 11 - 3 )/ 2² . 3²⁸

A = 3²⁹ . 2³ / 2² . 3²⁸

A = 3 .2

A = 6

Mong cac ban ung ho minh nha

tách mẫu ra: (2.3¹⁴)² = 2².(3¹⁴)² nha

duyệt đi

A=(11.3^22.3^7-9^15)/ ( 2.3^14)
=(11.3^29-3^30) /(2.3^14)
=[3^29(11-3) / (2.3^14]
=(3^29.8) / (2.3^14)
=(3^29:3^14) /(8:2)
=3^15/4

\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)

\(=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}\)

\(=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)

\(=\frac{3^{29}.2^3}{2^2.3^{28}}\)

\(=3.2=6\)

\(A=\frac{3^7\cdot17-3^9}{2^3\cdot3^5}=\frac{3^7\left(17-3^2\right)}{2^3\cdot3^5}=\frac{3^7\cdot2^3}{2^3\cdot3^5}=9\)

\(B=\frac{3^2\cdot4^2\cdot2^{32}}{11\cdot2^{13}\cdot4^{11}-16^9}=\frac{3^2\cdot2^{36}}{2^{35}\cdot11-2^{36}}=\frac{3^2\cdot2^{36}}{2^{35}\left(11-2\right)}=\frac{3^2\cdot2^{36}}{2^{35}\cdot3^2}=2\)

\(\frac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}=\frac{3^{29}\left(11-3\right)}{2^2\cdot3^{28}}=\frac{3^{29}\cdot8}{2^2\cdot3^{28}}=6\)

\(C=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-3^{30}}{4.3^{28}}=\frac{3^{29}\left(11-3\right)}{4.3^{28}}=\frac{3.8}{4}=6\)

\(\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)

\(=\dfrac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}\)

\(=\dfrac{11.3^{29}-3^{30}}{2^2.3^{28}}\)

\(=\dfrac{3^{29}\left(11-3\right)}{2^2.3^{28}}\)

\(=\dfrac{3^{29}.2^3}{2^2.3^{28}}\)

\(=\dfrac{3.2}{1.1}=6\)

\(\dfrac{4^6\cdot9^5+6^9\cdot120}{-8^4\cdot3^{12}-6^{11}}\)

\(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)

\(=\dfrac{2^{12}\cdot3^{10}\cdot\left(1+5\right)}{2^{11}\cdot3^{11}\left(2\cdot3-1\right)}\)

\(=\dfrac{2\cdot6}{3\cdot5}=\dfrac{4}{5}\)

                                                    Bài giải

a, \(\frac{7}{12}+\frac{5}{6}+\frac{1}{4}-\frac{3}{7}-\frac{5}{12}\)

\(=\left(\frac{7}{12}-\frac{5}{12}+\frac{5}{6}+\frac{1}{4}\right)-\frac{3}{7}=\left(\frac{7}{12}-\frac{5}{12}+\frac{10}{12}+\frac{3}{12}\right)-\frac{3}{7}=\frac{5}{4}-\frac{3}{7}=\frac{23}{28}\)

b, \(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=\frac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}=\frac{3^{29}\left(11-3\right)}{3^{28}\cdot4}=\frac{3\cdot8}{4}=6\)