Question

tinh rut gon

\(\dfrac{11\cdot3^{22}\cdot3^7-9^{15}}{2^2\cdot3^{28}}\)

Answer 1

\(\dfrac{11.3^{22}.3^7-9^{15}}{2^2.3^{28}}\)

\(=\dfrac{11.3^{28}.3-9^{15}}{2^2.3^{28}}\)

\(=\dfrac{11.3-9^{15}}{2^2}\)

\(=\dfrac{33-9^{15}}{4}\)

Answer 2

\(\dfrac{11.3^{22}.3^7-9^{15}}{2^2.3^{28}}\)

=\(\dfrac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}\)

=\(\dfrac{11.3^{29}-3^{30}}{2^2.3^{28}}\)

=\(\dfrac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)

=\(\dfrac{3^{29}.8}{2^2.3^{28}}\)

=\(\dfrac{3^{29}.2^3}{2^2.3^{28}}\)

=3.2

=6