\(\dfrac{-2}{3}.\dfrac{4}{3}+\dfrac{9}{2}:\dfrac{1}{2}=\dfrac{-8}{3}+9=\dfrac{19}{3}\)
\(=\dfrac{2}{3}.\dfrac{4}{3}+\dfrac{9}{2}.2=\dfrac{8}{9}+9=\dfrac{8}{9}+\dfrac{81}{9}=\dfrac{89}{9}\)
\(\dfrac{-2}{3}\cdot\dfrac{4}{3}+\dfrac{9}{2}:\dfrac{1}{2}\)
\(=\dfrac{-8}{9}+9\)
\(=\dfrac{73}{9}\)