a)

 \(\left(2x-15\right)^5=\left(2x-15\right)^3\\ \Leftrightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\\ \Leftrightarrow\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15-1\right).\left(2d-15+1\right)=0\end{matrix}\right.\\\Leftrightarrow\left[{}\begin{matrix}2x-15=0\\2x-16=0\\2x-14=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=8\\x=7\end{matrix}\right. \)

b) \(\left(7x-11\right)^3=\left(-3\right)^2.15+208\\ \Leftrightarrow\left(7x-11\right)^3=343=7^3\\ \Leftrightarrow7x-11=7\\ \Leftrightarrow x=\dfrac{18}{7}\)

b) x^10=1x

=> x=0 ; 1

c)(2x-15)^5=(2x-15)^3

=> (2x-15)^4 = (2x-15)^2

=> (2x-15)^2 =1

=> 2x-15=1

=> x=8 

(7x-15):3 = 2

7x-15 = 2.3

7x-15 = 6

7x = 6+15

7x = 21

x = 21:7

x= 3

75:(x+30) = 5

x+30 = 75:5

x+30 = 15

x = 15-30

x = -15

(7x-15):3=2

=>7x-15=6

=>7x=21

=>x=3

75:(x+30)=5

=>x+30=17

=>x=-13

\(\left(7x-15\right):3=2\)

\(7x-15=2.3\)

\(7x-15=6\)

\(7x=6+15\)

\(7x=21\)

\(x=\frac{21}{7}\)

\(x=3\)

Vậy \(x=3\)

7x-15=6

7x=21

x=3

\(\left(7x-15\right):3=2\)

\(7x-15=6\)

\(7x=21\)

\(=>x=7\)

\(\frac{3}{7}\left(7x+\frac{2}{3}\right)-2\left(\frac{5}{14}-3x\right)=\frac{15}{5}\)

\(\Leftrightarrow3x+\frac{2}{7}-\frac{5}{7}+6x=3\)

\(\Leftrightarrow9x=\frac{24}{7}\)

\(\Leftrightarrow x=\frac{8}{21}\)

\(\frac{3}{7}.\left(7x+\frac{2}{3}\right)-2.\left(\frac{5}{14}-3x\right)=\frac{15}{5}\)

\(\Leftrightarrow3x+\frac{2}{7}.x-\frac{5}{7}+6x=3\)

\(\Leftrightarrow\frac{65}{7}.x-\frac{5}{7}=3\)

\(\Leftrightarrow\frac{65}{7}.x=3+\frac{5}{7}\)

\(\Leftrightarrow\frac{65}{7}.x=\frac{26}{7}\)

\(\Leftrightarrow x=\frac{26}{7}:\frac{65}{7}\)

\(\Leftrightarrow x=\frac{2}{5}\)

 3/7.(7x+2/3)-2.(5/14-3x)=15/5

\(\Leftrightarrow3x+\frac{2}{7}.x-\frac{5}{7}+6x=3\)

\(\Leftrightarrow\frac{65}{7}.x-\frac{5}{7}=3\)

\(\Leftrightarrow\frac{65}{7}.x=\frac{26}{7}\)\(\Leftrightarrow x=\frac{2}{5}\)

Vậy x =\(\frac{2}{5}\)

1.Tính 

a) 7.[ 6 : 2 - 15 :(-3) - l-3l ]

=  7.[ 3 + 5 - 3]

=  7.[( 3 - 3 ) + 5]

=  7.[0 + 5]

=  7.5

=  35

b) 159.(18-59) - 59 .(18-159)

= 159 . ( - 41) - 59 . ( - 141 )

= ( - 6519 ) - ( - 8319 )

= 1800

2.Tìm x thuộc Z

a) x + 15 = 20 -4x

    x+4x=20-15

    5x=5

      x=5:5

      x=1

Vậy x=1

b) 3 - lx - 1l =0

    |x-1|=3

* x-1=3            * x-1=-3

      x=3+1             x=-3+1

      x=4                 x=-2

Vậy x=4 hoặc x=-2

c) 7(x-3) - 5 (3-x) = 11x - 5

    7x-21-15+5x=11x-5

    -21-15+5=11x-7x-5x

    -31=-x

     31=x

Vậy x=31  

mình sửa lại nha, nãy mình nhìn nhầm dấu:

343x³ - 1617x² + 2541x - 1674 = 0

x = 18/7 là nghiệm duy nhất của phương trình đã cho

a)88-3(7+x)=64                                  

=>3(7+x)=88-64

=>3(7+x)=24

=>7+x=24:3

=>7+x=8

=>x=8-7=1

tick nha