a) \(\frac{22}{33}\)và \(\frac{60}{71}\)

Ta có :

\(1-\frac{22}{33}=\frac{11}{33}\)

\(1-\frac{60}{71}=\frac{11}{71}\)

Vì \(\frac{11}{33}>\frac{11}{71}\)nên \(\frac{22}{33}< \frac{60}{71}\)

b)\(\frac{141}{893}\)và \(\frac{149}{901}\)

Ta có :

 \(1-\frac{141}{893}=\frac{752}{893}\)

\(1-\frac{149}{901}=\frac{752}{901}\)

Vì \(\frac{753}{893}>\frac{753}{901}\)nên \(\frac{141}{893}< \frac{149}{901}\)

a, 22/33 va 60/71

22/33=2/3=2x71/3x71=142/213

                                                      => 142/213<180/213 Vay 22/33<60/71

60/71=60x3/71x3=180/213

b, 141/893 va 149/901

ta có : 

1-141/893=752/893

1-149/901=752/901

Vi 752/893>752/901 => 141/893>149/901

3^22=3^21.3
2^33=2^31.4=2^31.(3+1)=2^31.3+2^31
Ta có 3^22=(3^2)^11=9^11
2^33=(2^3)^11=8^11
→2^31.3+2^31<3^21.3→2^31.3<3^21.3→2^31<3^21

Ta co : 22³³ va 33²²

=> 22³³=22^3.11=(22³)¹¹=10648¹¹

=> 33²²=33^2.11=(33²)¹¹=1089¹¹

Ma 1089¹¹<10648¹¹

Vay suy ra 22³³<33²²

^{nho lik e} 

Mất công chép lại:

3^22=3^21.3
2^33=2^31.4=2^31.(3+1)=2^31.3+2^31
Ta có 3^22=(3^2)^11=9^11
2^33=(2^3)^11=8^11
→2^31.3+2^31<3^21.3→2^31.3<3^21.3→2^31<3^21

71/60>37/35

> thì phải

Ta có \(3^{22}=\left(3^2\right)^{11}=9^{11}\)

\(2^{33}=\left(2^3\right)^{11}=8^{11}\)

Ta có \(8< 9\Rightarrow8^{11}< 9^{11}\)

hay \(3^{22}>2^{33}\)

Ta có 3^22= (3^2)^11=9^11(1)

2^33= (2^3)^11=8^11(2)

Từ (1) và (2) suy ra 3^22>2^33

Học tốt !

mình nghĩ là 2^33 < 3^22

nấu sai thì bạn thông cảm nhé :)

Ta có:2^33=(2^3)^11=6^11

      3^22=(3^2)^11=6^11

:) 2^33=3^22

ta có: 2\(^{33}\)= (2\(^3\))\(^{11}\)=8\(^{11}\)

3\(^{22}\)=(3\(^2\))\(^{11}\)= 9\(^{11}\)

Do 9>8 ⇒ 9\(^{11}\)> 8\(^{11}\) hay 3\(^{22}\)>2\(^{33}\)

22^3^2 : 33^2^3 = 22/33

22/33 = 2/3

vậy 22^3^2 = 2/3 x 33^2^3

suy ra 22^3^2 < 33^2^3

Ta có: \(\frac{22}{33}=\frac{2}{3}=\frac{12}{18}>\frac{12}{19}\)

Vậy \(\frac{12}{19}< \frac{22}{33}\)

12/19 < 22/33

tại sao

\(\dfrac{22}{33}=\dfrac{22:11}{33:11}=\dfrac{2}{3}\)
Ta có: 
Mẫu số chung 2 phân số: 57
\(\dfrac{12}{19}=\dfrac{12*3}{19*3}=\dfrac{36}{57}\)
\(\dfrac{2}{3}=\dfrac{2*19}{3*19}=\dfrac{38}{57}\)
Vì \(36< 38\) nên\(\dfrac{36}{57}< \dfrac{38}{57}\)
Vậy \(\dfrac{12}{19}< \dfrac{22}{33}\)

\(\dfrac{22}{33}\)=\(\dfrac{22:11}{33:11}\)=\(\dfrac{2}{3}\)=\(\dfrac{2\times6}{3\times6}\)=\(\dfrac{12}{18}\)>\(\dfrac{12}{19}\)