X-{57-[42+(-23-x)]}=13-{47+[25-(32-x)]}
Những câu hỏi liên quan
X-{57-[42+(-23-x)]}=13-{47+[25-(32-x)]}
\(x-\left\{57-\left[42+\left(-23-x\right)\right]\right\}=13-\left\{47+\left[25-\left(32-x\right)\right]\right\}\)
=>\(x-\left\{57-42+23+x\right\}=13-47-25+32-x\)
=>\(x-\left(x+38\right)=-27-x\)
=>\(-27-x=-38\)
=>x+27=38
=>\(x=38-27=11\)
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x- { 57-[42 + (-23 - x ) ]} =13-{47+[25-(32-x)]}
\(x-\left\{57-\left[42+\left(-23-x\right)\right]\right\}=13-\left\{47+\left[25-\left(32-x\right)\right]\right\}\)
\(\Leftrightarrow x-57+42-23-x=13-47-25+32-x\)
\(\Leftrightarrow x-x-57+42-23=-27-x\)
\(\Leftrightarrow-57+42-23=-27-x\)
\(\Leftrightarrow-38=-27-x\)
\(\Leftrightarrow x=\left(-27\right)-\left(-38\right)\)
\(\Leftrightarrow x=11\)
Vậy \(x=11\) là giá trị cần tìm
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\(x-\left(57-\left(42+\left(-23-x\right)\right)\right)=13-\left(47+\left(25-\left(32-x\right)\right)\right)\)
\(\Leftrightarrow\) \(x-\left(57-\left(42-23-x\right)\right)=13-\left(47+\left(25-32+x\right)\right)\)
\(\Leftrightarrow\) \(x-\left(57-42+23+x\right)=13-\left(47+25-32+x\right)\)
\(\Leftrightarrow\) \(x-57+42-23-x=13-47-25+32-x\)
\(\Leftrightarrow\) \(-38=-27-x\) \(\Leftrightarrow\) \(-x=-38+27=-11\Leftrightarrow x=11\)
vậy \(x=11\)
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x - { 57 - [ 42 + ( -23 - x ) ]} = 13 - { 47 + [25 - ( 32 - x ) ] }. Tìm x
=>x-57+42-23-x=13-47-25+32-x
=>x-x-57+42-23=-27-x
=>-57+42-23=-27-x
=>-38=-27-x
=>x=-27-(-38)
=>x=11
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x-57+42-23-x=13-47-25+32-x
x=13-47-25+32+23-42+57
x=11
tick nha bạn
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X-(57-(42+(-23-x)=13-47+25-23-x
x-(57-(42+(-23-x)=13-47+25-23-x
x-57-42-23-x=13-47+25-23-x
x-122-x=-32-x
x-x-122=-32-x
-32-x=-122
x=-32-(-122)
x=90
Vậy x=90
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\(x-(57-(42+(-23-x)=13-47+25-13-x\)
\(\Rightarrow x-57-42+\left(-23\right)-x=13-47+25-23-x\)
\(\Rightarrow x-x+x=13-47+25-23+23+42+57\)
\(\Rightarrow x=90\)
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Tìm số nguyên x biết:
a/ 43+(9-21)=317-(x+317)
b/(15-x)+(x-12)=7(-5+x)
c/x-{57-[42+(-23-x)]}=13-{47+25-(32-x)]}
a 43+(9-21)=317-(x-317)
43+(-10)=317-x-317
31=(317-317)-x
31=-x
x=-31
h minh nha
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[(10-x).2+51]:3-2=3 (X-12)-15=20-(17+x) 720-[41-(2x-5)]=2( mũ 3). 5 | (2x là 2 nhân x,chấm là dấu nhân X-{57-[42+(-23-x)]}=13-{47+[25-(32-x)]}
a: \(\left[\left(10-x\right)\cdot2+51\right]:3-2=3\)
=>\(\left[2\left(10-x\right)+51\right]:3=5\)
=>\(\left[2\left(10-x\right)+51\right]=15\)
=>\(2\left(10-x\right)=15-51=-36\)
=>10-x=-36/2=-18
=>\(x=10-\left(-18\right)=10+18=28\)
b: \(\left(x-12\right)-15=20-\left(17+x\right)\)
=>\(x-12-15=20-17-x\)
=>\(x-27=3-x\)
=>\(2x=30\)
=>\(x=\dfrac{30}{2}=15\)
c: \(720-\left[41-\left(2x-5\right)\right]=2^3\cdot5\)
=>\(720-\left[41-2x+5\right]=8\cdot5=40\)
=>\(\left[41-2x+5\right]=720-40=680\)
=>-2x+46=680
=>-2x=680-46=634
=>\(x=\dfrac{634}{-2}=-317\)
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Các bn giúp mk giải bài này nha ,ai đúng mk tick cho nha
Tìm x thuộc Z biết
a) ( 15 - x ) + ( x + 12 ) = 7 - (x + 5 )
b) x - { 57 - [42 + ( -23 -x ) ]} = 13 - { 47 + [ 25 - ( 32 - x)]}
a , 43 + ( 9 - 21 ) = 317 - ( x + 317 )
b , ( 15 - x ) + ( x - 12 ) = 7 - ( -5 + x )
c , x - { 57 - [ 42 + ( -23 - x )]} = 13 - { 47 + [ 25 - ( 32 - x )]}
d , -7 + | x - 4 | = -3
e , 13 - | x + 5 | = 13
g , | x - 10 | - ( -12 ) = 4
h , | x + 2 | < 5
a, 43 + ( 9 - 21 ) = 317 - ( x + 317 )
43 + ( -12 ) = 317 - x - 317
43 - 12 = 317 - 317 - x
-x = 31
x = -31
b, (15-x) + (x-12) = 7- (-5 + x)
15-x+x-12 = 7+5-x
15-12 = 12-x
3 = 12-x
x = 12-3
x = 9
c, x - { 57- [42+ (-23 - x)]} = 13- {47+ [25- (32-x)]}
x - [57- (42-23-x)] = 13- [47+ (25-32+x)]
x - [57- (19-x)] = 13- [47+ (x-7)]
x - (57-19+x) = 13- (47+x-7)
x - (38+x) = 13- (40+x)
x-38-x = 13-40-x
x = 13-40+38
x = 11
a , 43 + ( 9 - 21 ) = 317 - ( x + 317 )
b , ( 15 - x ) + ( x - 12 ) = 7 - ( -5 + x )
c , x - { 57 - [ 42 + ( -23 - x )]} = 13 - { 47 + [ 25 - ( 32 - x )]}
d , -7 + | x - 4 | = -3
a , 43 + ( 9 - 21 ) = 317 - ( x + 317 )
b , ( 15 - x ) + ( x - 12 ) = 7 - ( -5 + x )
c , x - { 57 - [ 42 + ( -23 - x )]} = 13 - { 47 + [ 25 - ( 32 - x )]}
d , -7 + | x - 4 | = -3
e , 13 - | x + 5 | = 13
g , | x - 10 | - ( -12 ) = 4
h , | x + 2 | < 5
a) \(43+\left(9-21\right)=317-\left(x+317\right)\\ 43+9-21=317-x-317\\ 52-21=\left(317-317\right)-x\\ 31=-x\\ x=-31\)Vậy x = -31
b) \(\left(15-x\right)+\left(x-12\right)=7-\left(-5+x\right)\\ 15-x+x-12=7+5-x\\ \left(x-x\right)+\left(15-12\right)=12-x\\ 3=12-x\\ x=9\)Vậy x = 9
c) \(x-\left\{57-\left[42+\left(-23-x\right)\right]\right\}=13-\left\{47+\left[25-\left(32-x\right)\right]\right\}\\ x-\left\{57-\left[42+\left(-23\right)-x\right]\right\}=13-\left\{47+\left[25-32+x\right]\right\}\\ x-\left\{57-42+23+x\right\}=13-\left\{47+25-32+x\right\}\\ x-57+42-23-x=13-47-25+32-x\\ -57+42-23=-34-25+32-x\\ -15-23=-59+32-x\\ -38=-27-x\\ x=11\)Vậy x = 11
d) \(-7+\left|x-4\right|=-3\\ \left|x-4\right|=4\\ \Rightarrow\left[{}\begin{matrix}x-4=4\\x-4=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=8\\x=0\end{matrix}\right.\)Vậy \(x\in\left\{8;0\right\}\)
e) \(13-\left|x+5\right|=13\\ \left|x+5\right|=0\\ \Rightarrow x+5=0\\ \Rightarrow x=-5\)Vậy x = -5
g) \(\left|x-10\right|-\left(-12\right)=4\\ \left|x-10\right|=-8\\ \Rightarrow x\in\varnothing\left(\text{vì }\left|x-10\right|\ge0\text{với mọi }x\right)\)Vậy \(x\in\varnothing\)
h) \(\left|x+2\right|< 5\\ 0\le\left|x+2\right|< 5\\ \Rightarrow\left|x+2\right|\in\left\{1;2;3;4\right\}\\ \Rightarrow x+2\in\left\{1;-1;2;-2;3;-3;4;-4\right\}\\ \Rightarrow x\in\left\{-1;-3;0;-4;1;-5;2;-6\right\}\)Vậy \(x\in\left\{-1;-3;0;-4;1;-5;2;-6\right\}\)
a) 43+(9−21)=317−(x+317)43+9−21=317−x−31752−21=(317−317)−x31=−xx=−3143+(9−21)=317−(x+317)43+9−21=317−x−31752−21=(317−317)−x31=−xx=−31Vậy x = -31
b) (15−x)+(x−12)=7−(−5+x)15−x+x−12=7+5−x(x−x)+(15−12)=12−x3=12−xx=9(15−x)+(x−12)=7−(−5+x)15−x+x−12=7+5−x(x−x)+(15−12)=12−x3=12−xx=9Vậy x = 9
c) x−{57−[42+(−23−x)]}=13−{47+[25−(32−x)]}x−{57−[42+(−23)−x]}=13−{47+[25−32+x]}x−{57−42+23+x}=13−{47+25−32+x}x−57+42−23−x=13−47−25+32−x−57+42−23=−34−25+32−x−15−23=−59+32−x−38=−27−xx=11x−{57−[42+(−23−x)]}=13−{47+[25−(32−x)]}x−{57−[42+(−23)−x]}=13−{47+[25−32+x]}x−{57−42+23+x}=13−{47+25−32+x}x−57+42−23−x=13−47−25+32−x−57+42−23=−34−25+32−x−15−23=−59+32−x−38=−27−xx=11Vậy x = 11
d) −7+|x−4|=−3|x−4|=4⇒[x−4=4x−4=−4⇒[x=8x=0−7+|x−4|=−3|x−4|=4⇒[x−4=4x−4=−4⇒[x=8x=0Vậy x∈{8;0}x∈{8;0}
e) 13−|x+5|=13|x+5|=0⇒x+5=0⇒x=−513−|x+5|=13|x+5|=0⇒x+5=0⇒x=−5Vậy x = -5
g) |x−10|−(−12)=4|x−10|=−8⇒x∈∅(vì |x−10|≥0với mọi x)|x−10|−(−12)=4|x−10|=−8⇒x∈∅(vì |x−10|≥0với mọi x)Vậy x∈∅x∈∅
h) |x+2|<50≤|x+2|<5⇒|x+2|∈{1;2;3;4}⇒x+2∈{1;−1;2;−2;3;−3;4;−4}⇒x∈{−1;−3;0;−4;1;−5;2;−6}|x+2|<50≤|x+2|<5⇒|x+2|∈{1;2;3;4}⇒x+2∈{1;−1;2;−2;3;−3;4;−4}⇒x∈{−1;−3;0;−4;1;−5;2;−6}Vậy x∈{−1;−3;0;−4;1;−5;2;−6}