ai giải được mk k cho nhoa mọi người@@@

Ta có: \(A=2015\cdot10001\cdot2016\cdot100010001=2015\cdot2016\cdot10001\cdot100010001\)

          \(B=2016\cdot10001\cdot2015\cdot100010001=2015\cdot2016\cdot10001\cdot100010001\)

\(\Rightarrow A=B\)(Dấu . là nhân)

= nhau nha

Ta có:

\(A=2016.20172017=2016.2017.10001\)

\(B=2017.20162016=2017.2016.10001\)

\(\Rightarrow2016.2017.10001=2017.2016.10001\)

\(\Leftrightarrow A=B\)

Thank you Phúc Trần Tấn

\(\frac{20152015}{20162016}+\frac{20162016}{20162016}\)

\(=\frac{2015\times10001}{2016\times10001}+\frac{2016\times10001}{2016\times10001}\)

\(=\frac{2015}{2016}+\frac{2016}{2016}\)

\(=\frac{4031}{2016}\)

kết quả :4013 / 2016

( 20152015/20162016 + 20172017/20162016 ) . x - 1 = 2016

2.x-1=2016

2x=2017

x=2017:2

x=1008,5

=>2.x-1=2016

=>2x =2017

=>x=1008,5

a/ \(3^{150}=\left(3^2\right)^{75}=9^{75}\)

\(2^{225}=\left(2^3\right)^{75}=8^{75}\)

\(9^{75}>8^{75}\Rightarrow3^{150}>2^{225}\)

b/

\(20162016^{10}=\left(2016.10001\right)^{10}=2016^{10}10001^{10}\)

\(2016^{20}=2016^{10}.2016^{10}\)

\(10001^{10}>2016^{10}\Rightarrow2016^{10}.10001^{10}>2016^{10}.2016^{10}\Rightarrow20162016^{10}>2016^{20}\)

c/ \(\frac{222^{333}}{333^{222}}=\frac{\left(222^3\right)^{111}}{\left(333^2\right)^{111}}=\frac{\left(2^3.111^3\right)^{111}}{\left(3^2.111^2\right)^{111}}=\left(\frac{8.111}{9}\right)^{111}\)

\(\frac{888}{9}>1\Rightarrow\left(\frac{888}{9}\right)^{111}>1\Rightarrow222^{333}>333^{222}\)

a) Ta có: 3^150 = 3^2.75 = (3^2)^75 = 9^75

2^225 = 2^3.75 = (2^3)^75 = 8^75

Vì 9 > 8 nên 9^75 > 8^75

Vậy 3^150 > 2^225

b) Ta có: 2016^20 = 2016^10+10 = 2016^10 . 2016^10

20162016^10 = (10001 . 2016)^10 = 10001^10 . 2016^10

Vì 2016^10 < 10001^10 nên 2016^10 . 2016^10 < 10001^10 . 2016^10

Vậy 2016^20 < 20162016^10

c) (222^3)^111 và (333^2)^111

(2 . 111)^3 và (3 . 111)^2

8 . 111^3 và 9 . 111^2

888 . 111^2 và 9 . 111^2

Vậy 222^333 > 333^222

b = 20162014 . 20162018 = (20162016 - 2) (20162016 + 2)

= 20162016² - 4

mà a = 20162016²

=> a > b

Ta thấy:

A = \(\frac{20162017}{20162016}\) và     B =  \(\frac{20152016}{20152015}\)

A  =  \(\frac{20162016}{20162016}\)+  \(\frac{1}{20162016}\)  =   \(1\) +   \(\frac{1}{20162016}\)

B  =   \(\frac{20152015}{20152015}\) +   \(\frac{1}{20152015}\)=   \(1\)  +    \(\frac{1}{20152015}\)

Vì:     \(\frac{1}{20162016}\)   \(< \)       \(\frac{1}{20152015}\)

Nên:    \(A\)    \(< \)    \(B\)

~ HokT~

A>b mình  nghĩ vậy 

a = 2015 x 20162016 

A = 2015 x 10001 x 2016

B = 2016 x 20152015

B = 2016 x 10001 x 2015

=> A = B