1.

b) \(3^x+3^{x+2}=2430\)

\(\Rightarrow3^x.1+3^x.3^2=2430\)

\(\Rightarrow3^x.\left(1+3^2\right)=2430\)

\(\Rightarrow3^x.10=2430\)

\(\Rightarrow3^x=2430:10\)

\(\Rightarrow3^x=243\)

\(\Rightarrow3^x=3^5\)

\(\Rightarrow x=5\)

Vậy \(x=5.\)

c) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)

\(\Rightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)

\(\Rightarrow\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\)

\(\Rightarrow\left[{}\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15\right)^2=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=15\\2x-15=\pm1\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=15:2\\2x-15=1\\2x-15=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{15}{2}\\2x=16\\2x=14\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{15}{2}\\x=8\\x=7\end{matrix}\right.\)

Vậy \(x\in\left\{\frac{15}{2};8;7\right\}.\)

Chúc bạn học tốt!

3) \(-12+2x-9+x=0\\ -21+3x=0\\ 3x=21\\ x=7\)

4)
\(11+\left(15-x\right)=1\)
\(15-x=1-11\)
\(15-x=-10\)
\(x=15-\left(-10\right)\)
\(x=25\)

5) 
\(4-\left(27-3\right)=x-\left(13-4\right)\)
\(4-24=x-9\)
\(x-9=-20\)
\(x=-20+9\)
\(x=-11\)
 

\(3.-12+\left(2x-9\right)+x=0.\)

\(\Leftrightarrow-12+2x-9+x=0.\Leftrightarrow3x=21.\Leftrightarrow x=7.\)

Vậy \(x=7.\)

\(4.11+\left(15-x\right)=1.\Leftrightarrow11+15-x=1.\Leftrightarrow26-x=1.\Leftrightarrow x=25.\)

Vậy \(x=25.\)

\(5.4-\left(27-3\right)=x-\left(13-4\right).\Leftrightarrow4-24=x-9.\Leftrightarrow-20=x-9.\Leftrightarrow x=-11.\)

Vậy \(x=-11.\)

\(6.8-\left(x-10\right)=23-\left(-4+12\right).\Leftrightarrow8-x+10=23-8.\Leftrightarrow18-x=15.\Leftrightarrow x=3.\)

Vậy \(x=3.\)

\(7.105-5\left(10-5x\right)=-20.\Leftrightarrow105-50+25x=-20.\Leftrightarrow25x=-75.\Leftrightarrow x=-3.\)

Vậy \(x=-3.\)

\(8.\left(x-1\right)\left(8-2x\right)\left(3x+123\right)=0.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0.\\8-2x=0.\\3x+123=0.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1.\\x=4.\\x=-41.\end{matrix}\right.\)

Vậy \(x\in\left\{1;4;-41\right\}.\)

\(9.\left(x^2-25\right)\left(x+10\right)=0.\)

\(\Leftrightarrow\left(x-5\right)\left(x+5\right)\left(x+10\right)=0.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=0.\\x+5=0.\\x+10=0.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5.\\x=-5.\\x=-10.\end{matrix}\right.\)

Vậy \(x\in\left\{5;-5;-10\right\}.\)

\(10.x\left(x^2+5\right)=0.\Leftrightarrow x=0.\)

Bài 1 bạn tự là nhé dễ lắm :))

Bài 2 :

Ta có :

\(4x-15=-75-x\)
\(\Leftrightarrow\)\(4x+x=-75+15\)

\(\Leftrightarrow\)\(5x=-60\)

\(\Leftrightarrow\)\(x=\frac{-60}{5}\)

\(\Leftrightarrow\)\(x=-12\)

Bài 3 :

Ta có :

\(12⋮\left(x-3\right)\)\(\Rightarrow\)\(\left(x-3\right)\inƯ\left(12\right)\)

Mà \(Ư\left(12\right)=\left\{1;-1;2;-2;3;-3;4;-4;6;-6;12;-12\right\}\)

Suy ra : ( lập bảng )

Vậy \(x\in\left\{4;2;5;1;6;0;7;-1;9;-3;15;-9\right\}\)

Chúc bạn học tốt 

\(a,\left(27x+6\right):3-11=9\)

\(\Rightarrow\left(27x-6\right):3=20\)\(\Rightarrow27x-6=60\)\(\Rightarrow27x=66\)\(\Rightarrow x=\frac{22}{9}\)

\(b,\left(15-6x\right).3^5=3^6\)

\(\Rightarrow15-6x=3\)\(\Rightarrow6x=12\)\(\Rightarrow x=2\)

\(c,\left(2x-6\right).4^7=4^9\)

\(\Rightarrow2x-6=16\)\(\Rightarrow2x=22\)\(\Rightarrow x=11\)

Bài 1: Tìm x

a,(27.x+6):3-11=9

﴾ 27x + 6﴿ : 3 ‐ 11 = 9

﴾ 27x + 6﴿ : 3 = 20

27x + 6 = 60

27x = 54

    x = 54 : 27

    x = 2 

Vậy x = 2

b,( 15-6x ) . 3⁵=3⁶

( 15 - 6x ) = 3⁶ : 3⁵

15 - 6x = 3

       6x = 15 - 3

       6x = 12

         x = 12 : 6

         x = 2

Vậy x = 2

c,( 2x-6 ) . 4⁷=4⁹

2x - 6 = 4⁹ : 4⁷

2x - 6 = 16

2x      = 16 + 6

2x      = 22

  x      = 22 : 2

  x      = 11

Vậy x = 11

9-(27-2x)=-|-27|-15

9-(27-2x)=-42

27-2x = 51

2x = 27 - 51

2x = -24

x = -24 : 2

x = -12