Bài 7 : Viết các biểu thức sau dưới dạng tích1/ \(^{x^{16}-y^{16}}\)2/ \(^{x^3-125

Trịnh Thành Long K9A2 (...

9 tháng 7 2023 lúc 8:23

bài 4 : viết các biểu thức sau dưới dạng tích

a , 25 x mũ 2 -16

b , 16 a mũ 2 - 9 b mũ 2

c , 8 x mũ 3 + 1

d , 125 x mũ 3 + 27 y mũ 3

e , 8 x mũ 3 - 125

g , 27 x mũ 3 - y mũ 3

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Lớp 8 Toán Câu hỏi của OLM

Kiều Vũ Linh CTV

9 tháng 7 2023 lúc 8:32

a) 25x² - 16

= (5x)² - 4²

= (5x - 4)(5x + 4)

b) 16a² - 9b²

= (4a)² - (3b)²

= (4a - 3b)(4a + 3b)

c) 8x³ + 1

= (2x)³ + 1³

= (2x + 1)(4x² - 2x + 1)

d) 125x³ + 27y³

= (5x)³ + (3y)³

= (5x + 3y)(25x² - 15xy + 9y²)

e) 8x³ - 125

= (2x)³ - 5³

= (2x - 5)(4x² + 10x + 25)

g) 27x³ - y³

= (3x)³ - y³

= (3x - y)(9x² + 3xy + y²)

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Nguyễn Đức Trí

9 tháng 7 2023 lúc 8:33

a) \(25x^2-16=\left(5x-4\right)\left(5x+4\right)\)

b) \(16a^2-9b^2=\left(4a-3b\right)\left(4a+3b\right)\)

c) \(8x^3+1=\left(2x+1\right)\left(4x^2-2x+1\right)\)

d) \(125x^3+27y^3=\left(5x+3y\right)\left(25x^2-15xy+9y^2\right)\)

e) \(8x^3-125=\left(2x-5\right)\left(4x^2-10x+25\right)\)

g) \(27x^3-y^3=\left(3x-y\right)\left(9x^2+3xy+y^2\right)\)

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Đoàn Khôi Nguyên

9 tháng 7 2023 lúc 8:39

tao phá olm đêy nè:

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[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉η҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉-҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉φ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉φ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉ύ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉β҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉η҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉-҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉φ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉φ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉ύ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉β҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉-҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉η҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉-҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉

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Ngân Phạm

25 tháng 7 2023 lúc 16:12

Viết các biểu thức sau dưới dạng một lũy thừa:

6, 3/2 x 9/4 x 81/16

7, (1/2)^7 x 8 x 32 x 2^8

8, (-1/7)^4 x 125 x 5

9, 4 x 32 : (2^3 x 1/16)

10, (1/7)^2 x 1/7 x 49

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Lớp 6 Toán

Nguyễn Lê Phước Thịnh CTV

25 tháng 7 2023 lúc 19:59

6:=(3/2)*(3/2)^2*(3/2)^4=(3/2)^7

7: =(1/2)^7*2^3*2^5*2^8=2^9

8: =(-1/7)^4*5^4=(-5/7)^4

9: =2^2*2^5:(2^3/2^4)

=2^7/2=2^6

10: =(1/7)^3*7^2=1/7

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Ngân Phạm

25 tháng 7 2023 lúc 15:42

Viết các biểu thức sau dưới dạng một lũy thừa:

6; 3/2 x 9/4 x 81/16

7; (1/2)^7 x 8 x 32 x 2^8

8; (-1/7)^4 x 125 x 5

9; 4 x 32 : (2^3 x 1/16)

10; (1/7)^2 x 1/7 x 49

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Lớp 6 Toán Câu hỏi của OLM

Phạm Quang Lộc

25 tháng 7 2023 lúc 15:51

\(\dfrac{3}{2}\times\dfrac{9}{4}\times\dfrac{81}{16}=\dfrac{3}{2}\times\left(\dfrac{3}{2}\right)^2\times\left(\dfrac{3}{2}\right)^4=\left(\dfrac{3}{2}\right)^7\)

\(\left(\dfrac{1}{2}\right)^7\times8\times32\times2^8=\left(\dfrac{1}{2}\right)^7\times2^3\times2^5\times2^8=\left(\dfrac{1}{7}\right)^7\times2^{16}\)

\(\left(-\dfrac{1}{7}\right)^4\times125\times5=\left(-\dfrac{1}{7}\right)^4\times5^3\times5=\left(-\dfrac{1}{7}\right)^4\times5^4\)

\(4\times32:\left(2^3\times\dfrac{1}{16}\right)=2^2\times2^5:2^3:2^{-4}=2^0\)

\(\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times49=\left(\dfrac{1}{7}\right)^3\times7^3=1^3\)

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✎﹏Kim Kim✧❤‿✶🌈(*•.¸♡ţę...

25 tháng 7 2023 lúc 15:49

6, \(\dfrac{3}{2}\times\dfrac{9}{4}\times\dfrac{81}{16}=\dfrac{3}{2}\times\left(\dfrac{3}{2}\right)^2\times\left(\dfrac{3}{2}\right)^4\)

7,\(\left(\dfrac{1}{2}\right)^7\times8\times32\times2^8=\left(\dfrac{1}{2}\right)^7\times2^3\times2^5\times2^8\)

8,\(\left(-\dfrac{1}{7}\right) ^4\times125\times5=\left(\dfrac{1}{7}\right)^4\times5^3\times5\)

9,\(4\times32:\left(2^3\times\dfrac{1}{16}\right)=2^2\times2^5:\left[2^3\times\left(\dfrac{1}{2}\right)^4\right]\)

10, \(\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times49=\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times7^2\)

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Nguyễn Đức Trí

25 tháng 7 2023 lúc 15:57

6) \(...=\dfrac{3}{2}.\left(\dfrac{3}{2}\right)^2.\left(\dfrac{3}{2}\right)^4=\left(\dfrac{3}{2}\right)^7\)

7) \(...=2^{-7}.2^3.2^5.2^8=2^9\)

8) \(...=\left(\dfrac{1}{7}\right)^4.5^3.5=\left(\dfrac{1}{7}\right)^4.5^4\)

9) \(...=2^2.2^5:\left(2^3.2^{-4}\right)=2^8\)

10) \(...=\left(\dfrac{1}{7}\right)^3.\left(\dfrac{1}{7}\right)^2=\left(\dfrac{1}{7}\right)^5\)

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JUST DO IT

1 tháng 8 2018 lúc 22:04

Bài 1: Viết các biểu thức sau dưới dạng TÍCH

\(\frac{9}{16}x^{2m-2}y^2-2x^my^m+\frac{16}{9}x^2y^{2m-2}\)

CÁC BẠN GIÚP MK NHA AI NHANH MK TICK CHO THANKS ^^

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Lớp 8 Toán Câu hỏi của OLM

Nguyễn Tũn

1 tháng 8 2018 lúc 22:08

Tích mình đi

Ai tích sẽ có lợi

vì khi có lợi bạn sẽ được người khác tích lại.

THANKS

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Không Tên

1 tháng 8 2018 lúc 22:10

\(\frac{9}{16}x^{2m-2}y^2-2x^my^m+\frac{16}{9}x^2y^{2m-2}\)

\(=\left(\frac{3}{4}x^{m-1}y-\frac{4}{3}xy^{m-1}\right)^2\)

p/s: chúc bạn học tốt

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ミ╰❥♡❥꧁.Nhật❁Hạ.꧂♡彡‿〄...

1 tháng 8 2018 lúc 22:11

\(=\left(\frac{3}{4}.x^{m-1}y\right)^2-2x^my^m+\left(\frac{4}{3}x.y^{m-1}\right)^2\)

\(=\left(\frac{3}{4}x^{m-1}.y-\frac{4}{3}y^{m-1}.x\right)^2\)

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Nguyễn Ngọc Hạnh

26 tháng 9 2021 lúc 21:51

Bài 1:Viết các biểu thức sau dưới dạng lũy thừa của 1 số hữu tỉ:

a) \(2^6\) x \(3^3\) b) \(6^4\) x \(8^3\) c) 16 x 81 d) \(25^4\) x \(2^8\)

Giúp mk với

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Lớp 7 Toán

Nguyễn Lê Phước Thịnh CTV

26 tháng 9 2021 lúc 21:52

a: \(2^6\cdot3^3=\left(2^2\cdot3\right)^3=12^3\)

b: \(6^4\cdot8^3=2^4\cdot3^4\cdot2^9=2^{13}\cdot3^4\)

c: \(16\cdot81=36^2\)

d: \(25^4\cdot2^8=100^4\)

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Vy trần

15 tháng 9 2021 lúc 10:15

Bài 2: Viết các biểu thức sau dưới dạng các hằng đẳng thức đã học

a) x²-4x+4

b)9x²-12x+4

c)x²-6xy+9y²

d)x²/4+x+1

e)-8x+16+x²

f)xy²+1/4x²y⁴+1

g)x²-1

h)25x²-16

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Lớp 8 Toán

Lấp La Lấp Lánh

15 tháng 9 2021 lúc 10:18

a) \(=\left(x-2\right)^2\)

b) \(=\left(3x-2\right)^2\)

c) \(=\left(x-3y\right)^2\)

d) \(=\left(\dfrac{x}{2}+1\right)^2\)

e) \(=\left(x-4\right)^2\)

f) \(=\left(\dfrac{1}{2}xy^2+1\right)^2\)

g) \(=\left(x-1\right)\left(x+1\right)\)

h) \(=\left(5x-4\right)\left(5x+4\right)\)

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Emmaly

15 tháng 9 2021 lúc 10:22

a) x²-4x+4=\(\left(X-2\right)^2\)

b)9x²-12x+4=\(\left(3x-2\right)^2\)

c)x²-6xy+9y^{2=\(\left(x-3y\right)^2\)}

d)x²/4+x+1=\(\left(\dfrac{x}{2}+1\right)^2\)

e)-8x+16+x²=\(X^2-8x+16=\left(x-4\right)^2\)

f)xy²+1/4x²y⁴+1 => sai đề

g)x²-1=\(\left(X-1\right)\left(x+1\right)\)

h)25x²-16=\(\left(5x-4\right)\left(5x+4\right)\)

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Bùi Tiến Chung

4 tháng 7 2018 lúc 21:30

Viết các biểu thức sau dưới dạng tích

a. x^4+4,x^2+4;9a^4+35a^2b^2+16b^4

b. 4a^2b^2-c^2d^2;a^3+27;x^16-y^16

c. x^3-125;-64+\(\dfrac{1}{8}\) x^3

d. 8x^3+60x^2y+150xy^2+125y^3

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Lớp 8 Toán Bài 3: Những hằng đẳng thức đáng nhớ

Nguyễn Lê Phước Thịnh CTV

16 tháng 7 2022 lúc 21:16

a: \(x^4+4=x^4+4x^2+4-4x^2=\left(x^2+2-2x\right)\left(x^2+2+2x\right)\)

c: \(x^3-125=\left(x-5\right)\left(x^2+5x+25\right)\)

\(\dfrac{1}{8}x^3-64=\left(\dfrac{1}{2}x-4\right)\left(\dfrac{1}{4}x^2+2x+16\right)\)

d: \(=\left(2x+5y\right)^3\)

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Thaodethuong

11 tháng 7 2018 lúc 17:10

1/ Viết các biểu thức sau dưới dạng tổng:

a. (x+y+z).(x-y-z)

b. (x-y+z).(x+y+z)

c. -16+(x-3)\(^2\)

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Lớp 8 Toán Câu hỏi của OLM

Lê Tuấn Kiệt

11 tháng 7 2018 lúc 17:19

a) Ta có:

(x+y+z)(x-y-z) = x^2 -xy -xz +yx- y^2 -yz+zx -zy -z^2

=x^2 - y^2 - 2yz - z^2.

b) Ta có: (x-y+z)(x+y+z) = x^2 +xy+xz -yx-y^2 -yz +zx+zy +z^2

=x^2 +2xz- y^2 +z^2.

c) Ta có: -16 + (x-3)^2 = -16 + ( x^2-6x+9)

= -16 + x^2 - 6x + 9

= x^2 - 6x - 7.

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Aikawa Maiya

11 tháng 7 2018 lúc 17:31

\(a,\left(x+y+z\right)\left(x-y-z\right)\)

\(=x\left(x-y-z\right)+y\left(x-y-z\right)+z\left(x-y-z\right)\)

\(=x^2-xy-xz+xy-y^2-yz+xz-yz-z^2\)

\(=x^2-y^2-2yz-z^2\)

\(b,\left(x-y+z\right)\left(x+y+z\right)\)

\(=x\left(x+y+z\right)-y\left(x+y+z\right)+z\left(x+y+z\right)\)

\(=x^2+xy+xz-xy-y^2-yz+xz+yz+z^2\)

\(=x^2+2xz-y^2+z^2\)

\(c,-16+\left(x-3\right)^2\)

\(=-16+x^2-6x+9\)

\(=x^2-6x-7\)

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Phạm Duy Lộc

14 tháng 10 2023 lúc 21:54

1.Viết các tích sau dưới dạng lũy thừaa) 4^8 . 2^20 ; 9^12 . 27^5 . 81^4 ; 64^3 . 4^5 . 16^2b) 25^20 . 125^4 ; x^7 . x^4 . x^3 ; 3^6 . 4^6c) 8^4 . 2^3 . 16^2 ; 2^3 . 2^2 . 8^3 ; y . y^72.Tính giá trị lũy thừa saua) 2^2 ; 2^3 ; 2^4 ; 2^5 ; 2^6 ; 2^7 ; 2^8 ; 2^9 ; 2^10b) 3^2 ; 3^3 ; 3^4 ; 3^5c) 4^2 ; 4^3 ; 4^4d) 5^2 ; 5^3 ; 5^43.Viết các thương sau dưới dạng lũy thừaa) 4^9 : 4^4 ; 17^8 : 17^5 ; 2^10 : 8^2 ; 18^10 : 3^10 ; 27^5 : 81^3b)10^6 : 100 ; 5^9 : 25^3 ; 4^10 : 64^3 ; 2^25 : 32^4 ; 18^4 : 9^...

Đọc tiếp

1.Viết các tích sau dưới dạng lũy thừa

a) 4^8 . 2^20 ; 9^12 . 27^5 . 81^4 ; 64^3 . 4^5 . 16^2

b) 25^20 . 125^4 ; x^7 . x^4 . x^3 ; 3^6 . 4^6

c) 8^4 . 2^3 . 16^2 ; 2^3 . 2^2 . 8^3 ; y . y^7

2.Tính giá trị lũy thừa sau

a) 2^2 ; 2^3 ; 2^4 ; 2^5 ; 2^6 ; 2^7 ; 2^8 ; 2^9 ; 2^10

b) 3^2 ; 3^3 ; 3^4 ; 3^5

c) 4^2 ; 4^3 ; 4^4

d) 5^2 ; 5^3 ; 5^4

3.Viết các thương sau dưới dạng lũy thừa

a) 4^9 : 4^4 ; 17^8 : 17^5 ; 2^10 : 8^2 ; 18^10 : 3^10 ; 27^5 : 81^3

b)10^6 : 100 ; 5^9 : 25^3 ; 4^10 : 64^3 ; 2^25 : 32^4 ; 18^4 : 9^4

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Lớp 6 Toán

Kiều Vũ Linh CTV

14 tháng 10 2023 lúc 22:01

1) a) 4⁸.2²⁰ = (2²)⁸.2²⁰

= 2¹⁶.2²⁰ = 2³⁶

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9¹².27⁵.81³ = (3²)¹².(3³)⁵.(3⁴)⁴

= 3²⁴.3¹⁵.3¹⁶ = 3⁵⁵

--------

64³.4⁵.16² = (4³)³.4⁵.(4²)²

= 4⁹.4⁵.4⁴ = 4¹⁸

b) 25²⁰.125⁴ = (5²)²⁰.(5³)⁴

= 5⁴⁰.5¹² = 5⁵²

--------

x⁷.x³.x⁴ = x¹⁴

--------

3⁶.4⁶ = (3.4)⁶ = 12⁶

Đúng 4

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Kiều Vũ Linh CTV

14 tháng 10 2023 lúc 22:03

2) a) 2² = 4

2³ = 8

2⁴ = 16

2⁵ = 32

2⁶ = 64

2⁷ = 128

2⁸ = 256

2⁹ = 512

2¹⁰ = 1024

b) 3² = 9

3³ = 27

3⁴ = 81

3⁵ = 243

c) 4² = 16

4³ = 64

4⁴ = 256

d) 5² = 25

5³ = 125

5⁴ = 625

Đúng 2

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Kiều Vũ Linh CTV

14 tháng 10 2023 lúc 22:06

3)

a) 4⁹ : 4⁴ = 4⁵

17⁸ : 17⁵ = 17³

2¹⁰ : 8² = 2¹⁰ : (2³)² = 2¹⁰ : 2⁶ = 2⁴

18¹⁰ : 3¹⁰ = (18 : 3)¹⁰ = 6¹⁰

27⁵ : 81³ = (3³)⁵ : (3⁴)³ = 3¹⁵ : 3¹² = 3³

b) 10⁶ : 100 = 10⁶ : 10² = 10⁴

5⁹ : 25³ = 5⁹ : (5²)³ = 5⁹ : 5⁶ = 5³

4¹⁰ : 64³ = 4¹⁰ : (4³)³ = 4¹⁰ : 4⁹ = 4

2²⁵ : 32⁴ = 2²⁵ : (2⁵)⁴ = 2²⁵ : 2²⁰ = 2⁵

18⁴ : 9⁴ = (18 : 9)⁴ = 2⁴

Đúng 2

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