{-3x + 2.[45-x-3(3x+7)-2x]+4 x}=55-103-57:[-2.(2x-1)2-(-9)^0]=-106
{-3+2.[45-x-3(3x+7)-2x]+4x}=55-103-57:[-2(2X-1)^2-(-9)^0]=-106
{-3x+2. [45-x-3 (3x+7)-2x]+4x}=55-103-57:[-2. (2x-1)^2(-9)^0]=-106
Làm nhanh giúp mình nhé!
Bài 1: Tìm số nguyên x:
{-3x+2.[45-x-3(3x+7)-2x]+4x}=55-103
-57:[-2.(2x+1)^2-(-9)^0=-106
\(\left\{-3x+2\left[45-x-3\left(3x+7\right)-2x\right]+4x\right\}=55-103\)
\(\left\{-3x+2\left[45-x-9x-21-2x\right]+4x\right\}=-48\)
\(-3x+90-2x-18x-42-4x+4x=-48\)
\(-3x-2x-18x-4x+4x=-48-90+42\)
\(-23x=-96\Leftrightarrow x=\frac{96}{23}\)
đag rảnh nên ... lm nốt
\(-57:\left[-2\left(2x+1\right)^2-\left(-9\right)^0\right]=-106\)
\(-2\left(2x+1\right)^2+1=57\)
\(-2\left(2x+1\right)^2=56\)
\(\left(2x+1\right)^2=-28\)
\(\Rightarrow\orbr{\begin{cases}2x+1=-2\sqrt{7}\\2x+1=2\sqrt{7}\end{cases}\Rightarrow\orbr{\begin{cases}2x=-1-2\sqrt{7}\\2x=-1+2\sqrt{7}\end{cases}}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{-1-2\sqrt{7}}{2}\\x=\frac{-1+2\sqrt{7}}{2}\end{cases}}\)
{-3x+2*[45-x-3(3x+7)-2x]+4x}=55-103-57:[-2*(2x-1)^2-(-9)^0=-106
các bạn giúp mình với. Cảm ơn nhiều!
Tìm số nguyên x biết:
a,{-3x+2.[45-x-3.(3x+7)-2x]+4x}=55
b,103-57:[-2.(2x-1)2-(-9)0)=-106
Tìm số nguyên x
{-3x + 2[45 - x - 3(3x + 7) - 2x] + 4x } = 55 - 103 - 57 : [-2\(\left(2x-1\right)^2\) - \(\left(-9\right)^0\) = -106
B) 17X - ( -16X - 37 ) + 2x + 43
C) -2x -3.( x-17) = 34 -2 (-2x +25)
D) 17x+ 3. ( -16x -37) = 2x +43 -4x
E) {- 3x +2. [45 - x-3 (3x + 7) - 2x] + 4x} =55
F) -103 - 57 : [ -2 ( 2x -1 )2 - ( -9 )0 ] - 106
G) -2x + 3. { 12-2 [ 3x - ( 20 + 2x ) - 4x ] + 1} = 45
Tìm số nguyên x :
\(\left\{-3x+2\left[45-x-3\left(3x+7\right)-2x\right]+4x\right\}=55-103-57:\left[-2\left(2x-1\right)^2-\left(-9\right)^0\right]=-106\)
-2x – (x – 17) = 34 – (-x + 25)
17x – ( -16x – 37) = 2x + 43
-2x –3. (x – 17) = 34 – 2(-x + 25)
17x + 3. ( -16x – 37) = 2x + 43 - 4x
{ -3x + 2.[ 45- x -3( 3x+ 7 -2x ] +4x } = 55
103 -57: [-2. (2x – 1 ) ^ 2 – (-9) ^ 0 ] = -106
1)-2x – (x – 17) = 34 – (-x + 25)
-2x-x-_17