Thực hiện phép tính:
A) (2x-3y)(4x^2+6xy+9y^2).
B) (6x^3+3x^2+4x+2):(3x^2+2)
C) (x+2)^2+(3-x)-2(x+3)(x-3)
D) x+3 phần x-2 - x-3 phần x+2 + x^2 +4x+8 phần 4-x^2
Phân tích đa thức sau thành nhân tử:
A) 6x(4-x)+x-4
B) x^2-1+x^2y-y
C) 25x^2-10x+1-16z^2
Giúp mình nhé@@
Thực hiện phép tính:
A) (2x-3y)(4x^2+6xy+9y^2).
B) (6x^3+3x^2+4x+2):(3x^2+2)
C) (x+2)^2+(3-x)-2(x+3)(x-3)
D) x+3 phần x-2 - x-3 phần x+2 + x^2 +4x+8 phần 4-x^2
Phân tích đa thức sau thành nhân tử:
A) 6x(4-x)+x-4
B) x^2-1+x^2y-y
C) 25x^2-10x+1-16z^2
mình chỉ phân tích thôi
a) 6x(4-x)+x-4
=6x(4-x)-(4-x)
=(6x-1)(4-x)
c) 25x^2-10x+1-16z^2
=(5x-1)^2-16z^2
=(5x-1-4z)(5x-1+4z)
ban xem lại đề bài câu b đi chắc là sai đó
còn các câu trên bạn tự làm nhé
Thực hiện phép tính:
a) (2x-3y)(4x2+6xy+9y2)
=8x3-27y3
b) (6x3+3x2+4x+2):(3x2+2)
=(3x2+2)(2x+1):(3x2+2)
=2x+1
c) (x+2)2+(3-x)-2(x+3)(x-3)
=x2+4x+4+3-x-2x2+18
=-x2+4x+25
Giúp mình nhé@@
Thực hiện phép tính:
A) (2x-3y)(4x^2+6xy+9y^2).
B) (6x^3+3x^2+4x+2):(3x^2+2)
C) (x+2)^2+(3-x)-2(x+3)(x-3)
D) x+3 phần x-2 - x-3 phần x+2 + x^2 +4x+8 phần 4-x^2
Phân tích đa thức sau thành nhân tử:
A) 6x(4-x)+x-4
B) x^2-1+x^2y-y
C) 25x^2-10x+1-16z^2
Phân tích các đa thức sau thành nhân tử
a) \(^{ }3xy-6xy^2\)
b) \(^{ }3x^3+6x^2+3x\)
c) \(^{ }x^3-x^2+2\)
d) \(^{ }x^2+4x+4-y^2\)
e) \(^{ }x^3+4x^2+4x\)
f) \(^{ }x^2+2x+1-9y^2\)
g) \(^{ }6x^2-12x\)
h) \(^{ }x^3+2x^2-x\)
i) \(^{ }x^2-2xy+y^2-9\)
j) \(^{ }x^2+x-6\)
k) \(^{ }2x^3+2x^2y-4xy^2\)
l) \(^{ }x^3-4x^2-12x+27\)
a) \(3xy-6xy^2=3xy\left(1-2y\right)\)
b) \(3x^3+6x^2+3x=3x\left(x^2+2x+1\right)=3x\left(x+1\right)^2\)
c) \(x^3-x^2+2\)
d) \(x^2+4x+4-y^2=\left(x^2+4x+4\right)-y^2=\left(x+2\right)^2-y^2=\left(x-y+2\right)\left(x+y+2\right)\)
e) \(x^3+4x^2+4x=x\left(x^2+4x+4\right)=x\left(x+2\right)^2\)
f) \(x^2+2x+1-9y^2=\left(x+1\right)^2-\left(3y\right)^2=\left(x-3y+1\right)\left(x+3y+1\right)\)
g) \(6x^2-12x=6x\left(x-2\right)\)
h) \(x^3-2x^2+x=x\left(x^2-2x+1\right)=x\left(x-1\right)^2\)
i) \(x^2-2xy+y^2-9=\left(x-y\right)^2-3^2=\left(x-y-3\right)\left(x-y+3\right)\)
k) \(2x^3+2x^2y-4xy^2=2x\left(x^2+xy-2y^2\right)\)
l) \(x^3-7x^2+9x+3x^2-21x+27=x\left(x^2-7x+9\right)+3\left(x^2-7x+9\right)=\left(x+3\right)\left(x^2-7x+9\right)\)
phân tích đa thức thành nhân tử
a) 4x (a-b) +6xy(b-a)
b) (6x+3) - ( 2x-5) (2x+1)
c) 4 ( x-3)^2 +2x (3-x)
d) x^4 +2x^2 -4x-4
e) 2x (x+y) -x -y
g)( 3x-1 )^2 - (x+3)^2
a) \(4x\left(a-b\right)+6xy\left(b-a\right)\)
\(=4x\left(a-b\right)-6xy\left(a-b\right)\)
\(=\left(4x-6xy\right)\left(a-b\right)\)
\(=2x\left(2-3y\right)\left(a-b\right)\)
b) \(\left(6x+3\right)-\left(2x-5\right)\left(2x+1\right)\)
\(=3\left(2x+1\right)-\left(2x-5\right)\left(2x+1\right)\)
\(=\left(3-2x+5\right)\left(2x+1\right)\)
\(=\left(8-2x\right)\left(2x+1\right)\)
\(=2\left(4-x\right)\left(2x+1\right)\)
g: \(\left(3x-1\right)^2-\left(x+3\right)^2\)
\(=\left(3x-1-x-3\right)\left(3x-1+x+3\right)\)
\(=\left(2x-4\right)\left(4x+2\right)\)
\(=4\left(x-2\right)\left(2x+1\right)\)
Phân tích các đa thức sau thành nhân tử:
a) x^3-4x^2+4x
b) x^2-2xy+y^2-9
c)2x^3-x^2-8x+4
d) x^2-y^2-5x+5y
e) 3x^2-6xy+3y^2-12z^2
f) x^3-4x^2+4x-xy^2
g) x^3-2x^2y+xy^2-25x
h) x^3-3x+2
i) 3x^2-7x-10
\(a,=x\left(x-2\right)^2\\ b,=\left(x-y\right)^2-9=\left(x-y-3\right)\left(x-y+3\right)\\ c,=x^2\left(2x-1\right)-4\left(2x-1\right)=\left(x-2\right)\left(x+2\right)\left(2x-1\right)\\ d,=\left(x-y\right)\left(x+y\right)-5\left(x-y\right)=\left(x-y\right)\left(x+y-5\right)\\ e,=3\left[\left(x-y\right)^2-4z^2\right]=3\left(x-y-2z\right)\left(x-y+2z\right)\\ f,=x\left[\left(x-2\right)^2-y^2\right]=x\left(x-y-2\right)\left(x+y-2\right)\\ g,=x\left[\left(x-y\right)^2-25\right]=x\left(x-y-5\right)\left(x-y+5\right)\\ h,=x^3-x-2x+2=x\left(x-1\right)\left(x+1\right)-2\left(x-1\right)\\ =\left(x-1\right)\left(x^2+x-2\right)=\left(x-1\right)^2\left(x+2\right)\\ i,=3x^2+3x-10x-10=\left(x+1\right)\left(3x-10\right)\)
Thực hiện phép tính:
a) \(\dfrac{x}{2x-y}-\dfrac{2x-y}{4x-2y}\)
b)\(\dfrac{3x+1}{x^2-1}-\dfrac{x}{2x-2}\)
c) \(\dfrac{x-2}{x^2-4}-\dfrac{-8-x}{3x^2+6x}\)
d) \(\dfrac{2}{2x-3}-\dfrac{x}{2x+3}-\dfrac{2x+1}{9-4x^2}\)
a: \(=\dfrac{2x-2x+y}{2\left(2x-y\right)}=\dfrac{y}{2\left(2x-y\right)}\)
b: \(=\dfrac{3x+1}{\left(x-1\right)\left(x+1\right)}-\dfrac{x}{2\left(x-1\right)}\)
\(=\dfrac{6x+2-x^2-x}{2\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{-x^2+5x+2}{2\left(x-1\right)\left(x+1\right)}\)
c: \(=\dfrac{1}{x+2}+\dfrac{x+8}{3x\left(x+2\right)}\)
\(=\dfrac{3x+x+8}{3x\left(x+2\right)}=\dfrac{4x+8}{3x\left(x+2\right)}=\dfrac{4}{3x}\)
d: \(=\dfrac{4x+6-2x^2+3x+2x+1}{\left(2x-3\right)\left(2x+3\right)}\)
\(=\dfrac{-2x^2+9x+7}{\left(2x-3\right)\left(2x+3\right)}\)
Thực hiện phép tính:
a) \(\dfrac{x^2}{x-1}+\dfrac{1-2x}{x-1}\)
b) \(\dfrac{x}{x-3}+\dfrac{-9}{x^2-3x}\)
c) \(\dfrac{3}{x-3}-\dfrac{6x}{9-x^2}+\dfrac{x}{x+3}\)
d) \(\dfrac{5x+10}{4x-8}.\dfrac{x-2}{x+2}\)
e) \(\dfrac{4x+6y}{x-1}:\dfrac{4x^2+12xy+9y^2}{1-x^2}\)
b) \(\dfrac{x}{x-3}\) + \(\dfrac{-9}{x^2-3x}\)
=\(\dfrac{x}{x-3}\)+ \(\dfrac{-9}{x\left(x-3\right)}\)
=\(\dfrac{x.x}{x\left(x-3\right)}\) + \(\dfrac{-9}{x\left(x-3\right)}\)
=\(\dfrac{x^2+3^2}{x\left(x-3\right)}\)
=\(\dfrac{\left(x+3\right)\left(x-3\right)}{x\left(x-3\right)}\)
=\(\dfrac{x+3}{x}\)
#Fiona
c) \(\dfrac{3}{x-3}-\dfrac{6x}{9-x^2}+\dfrac{x}{x+3}\)
=\(\dfrac{3}{x-3}\) - \(\dfrac{6x}{3^2-x^2}\) + \(\dfrac{x}{x+3}\)
=\(\dfrac{3}{x-3}\)+\(\dfrac{6x}{\left(x+3\right)\left(x-3\right)}\)+\(\dfrac{x}{x+3}\)
=\(\dfrac{3\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}\)+\(\dfrac{6x}{\left(x+3\right)\left(x-3\right)}\)+\(\dfrac{x\left(x-3\right)}{\left(x+3\right)\left(x-3\right)}\)
=\(\dfrac{3x+9+6x+x^2-3x}{\left(x-3\right)\left(x+3\right)}\)
=\(\dfrac{9+6x+x^2}{\left(x-3\right)\left(x+3\right)}\)
=\(\dfrac{3^2+2.3x+x^2}{\left(x-3\right)\left(x+3\right)}\)
= \(\dfrac{\left(3-x\right)^2}{\left(x-3\right)\left(x+3\right)}\)
=\(\dfrac{\left(x-3\right)^2}{\left(x-3\right)\left(x+3\right)}\)
=\(\dfrac{x-3}{x+3}\)
#Fiona
Tick đúng giúp mình nhaa<3
d)\(\dfrac{5x+10}{4x-8}\).\(\dfrac{x-2}{x+2}\)
=\(\dfrac{5\left(x+2\right)}{4\left(x-2\right)}\) . \(\dfrac{x-2}{x+2}\)
=\(\dfrac{5\left(x+2\right).\left(x-2\right)\text{}\text{}}{4\left(x-2\right).\left(x+2\right)}\)
=\(\dfrac{5}{4}\)
#Fiona
Tick đúng giúp mikk nhaa
Thực hiện phép tính:
a) 2x. ( x + 1 )
b) ( x + 1 ). ( x + 3 ) – 4
c) ( x + 2 )2 + 3x – 5
Phân tích các đa thức sau thành nhân tử:
a) 3x + 3y
b) x2 – 6x + 9
c) 2x + 2y + 5x + 5y
Tìm x biết:
3x.( x – 1 ) - 5 .( x - 1 ) = 0
\(1,\\ a,=2x^2+2x\\ b,=x^2+4x+3-4=x^2+4x-1\\ c,=x^2+4x+4+3x-5=x^2+7x-1\\ 2,\\ a,=3\left(x+y\right)\\ b,=\left(x-3\right)^2\\ c,=7\left(x+y\right)\\ 3,\\ \Leftrightarrow\left(x-1\right)\left(3x-5\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{5}{3}\end{matrix}\right.\)
phân tích đa thức thành nhân tử bằng cách phối hợp nhiều phương pháp
1) x^3 - x^2 - x + 1
2)x^4 + 6x^2y +9y^2 - 1
3)x^3 + x^2y - 4x - 4y
4)3x^2- 6xy + 3y^2 - 12z^2
\(x^3-x^2-x+1\)
\(=x^2\left(x-1\right)-\left(x-1\right)\)
\(=\left(x-1\right)\left(x^2-1\right)\)