Given and . Evaluate .
Answer:
Evaluate , given and .
Answer:
giúp mk vs
Evaluate (a+b)2 , given a-b=8 and ab=10 .
Answer:
giải
Ta có : \(\left(a+b\right)^2=\left(a-b\right)^2+4ab\)
Với \(a-b=8\)và \(ab=10\)
\(\Rightarrow\left(a+b\right)^2=8^2+4\times10\)
\(=104\)
Given the quadrilateral ABCD with two diagonals perpendicular and AB = 8cm, BC = 7cm, AD = 4cm. Evaluate CD.
Answer: CD = cm.
Given a trapezoid ABCD with base AB=4cm , CD=6cm , and góc C + góc D = 90 độ . Let M, N be respectively the midpoints of the segments AB and CD . Evaluate MN.
Answer: MN= ? cm
chỗ tiếng việt chỗ tiếng anh là sao
1.Given the quadrilateral ABCD with two diagonals perpendicular and AB = 8cm, BC = 7cm, AD = 4cm. Evaluate CD.
2.Given three consecutive even natural numbers, which have the product of last two numbers is 80 greater than the product of first two numbers.
Find the largest number.
Answer: The largest number is
2) đặt 3 số có dạng a; a+2, a+4 rồi khai triển ra
số lớn nhất là 22
Given the isosceles triangle ABC (AB=AC) with \(A=108^o\). Draw the bisector AD and BE of angles A and B respectively. Given BE = 10cm. Evaluate AD.
given the quadrilateral ABCD with two diagonals perpendicular and AB=8cm, BC=7cm, AD=4cm. Evaluate CD
Bài 1 mình ko chắc, nhưng cứ làm thử vậy
Bạn vẽ hình ra, gọi giao điểm 2 đường chéo là I(qui ước: VD:AB2=AB^2)
T có:AI2+IB2=AB2
IB2 + IC2=CB2
AI2+DI2=AD2
DI2+IC2=DC2
=>Cộng hết 8 cái bên trái sẽ bằng với 4 cái bên phải cộng lại
(tiếp tục)=2AI2+2IB2+2IC2+2DI2=129+DC2
=>2(AI2+IB2+IC2+DI2)=129+DC2
=>2(CB2+AD2)=129+DC2
=>2.65=129+DC
=>DC=1
Given the isosceles triangle ABC (AB=AC) with . Draw the bisector AD and BE of angles A and B respectively. Given BE = 10cm. Evaluate AD.
Evaluate the expression at
Fill in the blank: ............
Fill in the blank: Fill in the blank:Evaluate the expression at
x3 + 12x + 48x + 64
= (x + 4)2
= (- 4 + 4)2
= 02
= 0
Fill in the blank: ............
x3 - a = (x - 2)(x2 + 2x + 4)
x3 - a = x3 - 8
a = 8
Fill in the blank: (x - 1)3 = x3 - 3x2 + 3x - 1 Fill in the blank: (x + 1)3 = x3 + 3x2 + 3x + 1a + b = 8
(a + b)2 = 82
a2 + b2 + 2ab = 64
a2 + b2 + 2 . 10 = 64
a2 + b2 + 20 = 64
a2 + b2 = 64 - 20
a2 + b2 = 44
(a - b)2
= a2 - 2ab + b2
= 44 - 2 . 10
= 44 - 20
= 24
Given .
Evaluate A at .
Answer: A
A = (x - 5)(x2 + 5x + 25) - x2(x + 3) + 3x2
= x3 - 125 - x3 - 3x2 + 3x2
= - 125
Given .
Evaluate A at .
Answer: A
Given a trapezoid ABCD with base , and . Let M, N be respectively the midpoints of the segments . Evaluate MN.
Answer: cm