Ta có :

\(\frac{6\frac{1}{4}}{x}=\frac{x}{1,96}\)

\(\Leftrightarrow\frac{\frac{25}{4}}{x}=\frac{x}{1,96}\)

\(\Rightarrow x^2=\frac{25}{4}.1,96\)

\(\Leftrightarrow x^2=\frac{49}{4}\)

\(\Leftrightarrow x=\sqrt{\frac{49}{4}}\)

\(\Rightarrow x=\frac{7}{2}\)

P/s tham khảo nha

Có 2 giá trị là: 3,5 và -3,5

\(\frac{6\frac{1}{4}}{x}=\frac{x}{1,96}\)

\(\Rightarrow x^2=6\frac{1}{4}.1,96\)

\(\Rightarrow x^2=\frac{25}{4}.\frac{49}{25}\)

\(\Rightarrow x^2=\frac{49}{4}\)

\(\Rightarrow x^2=\left(\frac{7}{2}\right)^2\)

\(\Rightarrow x=\frac{7}{2}\)

vậy \(x=\frac{7}{2}\)

Ta có : \(\frac{6\frac{1}{4}}{x}=\frac{x}{1,96}\)

\(\Rightarrow\frac{6,25}{x}=\frac{x}{1,96}\)

\(\Rightarrow\frac{6,25.1,96.x}{x.1,96}=\frac{x.x}{1,96.x}\)

\(\Rightarrow6,25.1,96.x=x.x\)

\(\Rightarrow12,25.x=x.x\)

Vì \(x=x\)nên để \(12,25.x=x.x\)thì \(12,25=x\)

Vậy \(x=12,25\)

ta có:\(\frac{6\frac{1}{4}}{x}=\frac{x}{1,96}\)

=>\(6\frac{1}{4}.1,96=x.x\)

=>6,25.1,96=2x

=>12,25=2x

=>x=12,25:2

Vậy x= 6,125

=>x.x=\(6\frac{1}{4}.1,96\)

=>x^2=12,25

=>x=3,5 hoặc x=-3,5

số giá trị là 2

\(2\)

\(\frac{6\frac{1}{4}}{x}=\frac{x}{1,96}\)

=> \(x^2=6\frac{1}{4}.1,96\)

=> \(x^2=12,25\)

=> \(x^2=\left(\pm3,5\right)^2\)

=> \(x=\pm3,5\)

Vậy \(x\in\left\{3,5;-3,5\right\}\)

\(\frac{6\frac{1}{4}}{x}=\frac{x}{1,96}\)

\(\frac{6,25}{x}=\frac{x}{1,96}\)

\(\Rightarrow6,25.1,96=x^2\)

\(\Rightarrow12.25=x^2\)

\(\Rightarrow\sqrt{12,25}=x=3,5\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=3,5\\x=-3,5\end{array}\right.\)

2

Ta có: \(\frac{6\frac{1}{4}}{x}=\frac{x}{1,96}\)

\(\left(=\right)\frac{\frac{25}{4}}{x}=\frac{x}{1,96}\)

\(\left(=\right)x^2=12,25\)

\(=>\orbr{\begin{cases}x=3,5\\x=-3,5\end{cases}}\)

học tốt

Thanks!!!!!!!!!!!!

đk \(x\ne0\)

\(\frac{6\frac{1}{4}}{x}=\frac{x}{1,96}\)

\(\Leftrightarrow x^2=12,25\)

\(\Leftrightarrow x=\pm3,5(Tm)\)

\(\frac{6+\frac{1}{4}}{x}=\frac{x}{1,96}\)

=> \(x^2=\left(6+\frac{1}{4}\right)x1,96\)

=> \(x^2=\frac{25}{4}x1,96\)

=> \(x^2=12,25\)

=> \(x=3,5\)

0,2x / 3 = 8/3 
=> 0,2x = 8 
=> x = 8 : 0,2 
=> x = 40