Question

tìm giá trị x thả mãn \(\frac{6\frac{1}{4}}{x}=\frac{x}{1,96}\)

 

Answer 1

\(\frac{6\frac{1}{4}}{x}=\frac{x}{1,96}\)

=> \(x^2=6\frac{1}{4}.1,96\)

=> \(x^2=12,25\)

=> \(x^2=\left(\pm3,5\right)^2\)

=> \(x=\pm3,5\)

Vậy \(x\in\left\{3,5;-3,5\right\}\)

Answer 2

\(\frac{6\frac{1}{4}}{x}=\frac{x}{1,96}\)

\(\frac{6,25}{x}=\frac{x}{1,96}\)

\(\Rightarrow6,25.1,96=x^2\)

\(\Rightarrow12.25=x^2\)

\(\Rightarrow\sqrt{12,25}=x=3,5\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=3,5\\x=-3,5\end{array}\right.\)

Answer 3

2

Answer 4

+_3,5