Question

Giá trị x > 0 thỏa mãn: \(\frac{11}{14}+\left|\frac{2}{7}-x\right|-\frac{5}{2}=\frac{4}{3}\)

Answer 1

\(\frac{11}{14}+\left|\frac{2}{7}-x\right|-\frac{5}{2}=\frac{4}{3}\)

\(\Leftrightarrow\frac{11}{14}+\left|\frac{2}{7}-x\right|=\frac{23}{6}\)

\(\Leftrightarrow\left|\frac{2}{7}-x\right|=\frac{64}{21}\)

\(\Leftrightarrow\frac{2}{7}-x=\pm\frac{64}{21}\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}\frac{2}{7}-x=\frac{64}{21}\\\frac{2}{7}-x=-\frac{64}{21}\end{array}\right.\Leftrightarrow\left[\begin{array}{nghiempt}x=-\frac{58}{21}\\x=\frac{10}{3}\end{array}\right.\)

Mà \(x>0\)

Vậy \(x=\frac{10}{3}\)

 

Answer 2

2:7=x:14 bang gi