S = 1/5.6 + 1/10.9+....+ 1/3350.2013

=1/5 . 1/3 .( 1/2+ 1/2.3 + 1/3.4 +... + 1/670.671)

=1/15. ( 1-1/2 + 1/2 - 1/3+...+ 1/670-1/671)

= 1/15 .( 1 - 1/671 )

= 1/15 .670/671

=134/2013

S = \(\frac{1}{5.6}+\frac{1}{10.9}+\frac{1}{15.12}+...+\frac{1}{3350.2013}=\frac{1}{5.3}\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{670.671}\right)\)

\(=\frac{1}{15}\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{670}-\frac{1}{671}\right)=\frac{1}{15}\left(1-\frac{1}{671}\right)=\frac{1}{15}.\frac{670}{671}\)

\(=\frac{134}{2013}\)

S = 1/5.6 + 1/10.9+....+ 1/3350.2013

=1/5 . 1/3 .( 1/2+ 1/2.3 + 1/3.4 +... + 1/670.671)

=1/15. ( 1-1/2 + 1/2 - 1/3+...+ 1/670-1/671)

= 1/15 .( 1 - 1/671 )

= 1/15 .670/671

=134/2013

S = 1/5.6 + 1/10.9+....+ 1/3350.2013

=1/5 . 1/3 .( 1/2+ 1/2.3 + 1/3.4 +... + 1/670.671)

=1/15. ( 1-1/2 + 1/2 - 1/3+...+ 1/670-1/671)

= 1/15 .( 1 - 1/671 )

= 1/15 .670/671

=134/2013

S = 1/5.6 + 1/10.9+....+ 1/3350.2013

=1/5 . 1/3 .( 1/2+ 1/2.3 + 1/3.4 +... + 1/670.671)

=1/15. ( 1-1/2 + 1/2 - 1/3+...+ 1/670-1/671)

= 1/15 .( 1 - 1/671 )

= 1/15 .670/671

=134/2013

A = \(\dfrac{1}{3\times6}\) + \(\dfrac{1}{6\times9}\) + \(\dfrac{1}{9\times12}\)+...+\(\dfrac{1}{144\times147}\)

A = \(\dfrac{1}{3}\) \(\times\)( \(\dfrac{3}{3\times6}\) + \(\dfrac{3}{6\times9}\)+\(\dfrac{1}{9\times12}\)+...+\(\dfrac{3}{144\times147}\))

A = \(\dfrac{1}{3}\) \(\times\)(\(\dfrac{1}{3}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{12}+...+\dfrac{1}{144}-\dfrac{1}{147}\))

A = \(\dfrac{1}{3}\)\(\times\)(\(\dfrac{1}{3}\) - \(\dfrac{1}{147}\))

A = \(\dfrac{1}{3}\) \(\times\)\(\dfrac{16}{49}\)

A = \(\dfrac{16}{147}\)

Đang cần gấp ạ.

Ta có :

 1/2x6 + 1/4x9 + 1/6x12 +...+1/198 x 300

 = 1/6x2 + 1/6x6 + 1/6x12 + ....+1/6x9900

 = 1/6 x ( 1/2 + 1/6 + 1/ 12 +...+1/9900)

 = 1/6 x (1/1x2 + 1/2x3 + 1/3x4+...+1/99x100)

 =1/6x (1-1/2 + 1/2-1/3 + 1/3 - 1/4 + ....+1/99-1/100)

 =1/6x(1-1/100)

 =1/6 x 99/100

 = 33/200

k cho mình nha , học tốt

\(\frac{1}{2.6}+\frac{1}{4.9}+\frac{1}{6.12}+...+\frac{1}{36.57}+\frac{1}{38.60}\)

\(=\frac{1}{2.3}.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{18.19}+\frac{1}{19.20}\right)\)

\(=\frac{1}{6}.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{18}-\frac{1}{19}+\frac{1}{19}-\frac{1}{20}\right)\)

\(=\frac{1}{6}.\left(1-\frac{1}{20}\right)\)

\(=\frac{1}{6}.\frac{19}{20}=\frac{19}{120}\)

Tks bạn

\(\frac{1}{2.6}+\frac{1}{4.9}+\frac{1}{6.12}+...+\frac{1}{36.57}+\frac{1}{38.60}\)

\(=\frac{1}{2.3}.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{18.19}+\frac{1}{19.20}\right)\)

\(=\frac{1}{6}.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{18}-\frac{1}{19}+\frac{1}{19}-\frac{1}{20}\right)\)

\(=\frac{1}{6}.\left(1-\frac{1}{20}\right)\)'

\(=\frac{1}{6}.\frac{19}{20}=\frac{19}{120}\)

\(\frac{4}{3.6}+\frac{4}{6.9}+\frac{4}{9.12}+\frac{4}{12.15}\)

\(=\frac{4}{3}.\left(\frac{3}{3.6}+\frac{3}{6.9}+\frac{3}{9.12}+\frac{3}{12.15}\right)\)

\(=\frac{4}{3}.\left(\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+\frac{1}{12}-\frac{1}{15}\right)\)

\(=\frac{4}{3}.\left(\frac{1}{3}-\frac{1}{15}\right)\)

\(=\frac{4}{3}.\left(\frac{5}{15}-\frac{1}{15}\right)\)

\(=\frac{4}{3}.\frac{4}{15}=\frac{16}{45}\)

Dấu . là nhân nha

\(\frac{4}{3.6}+\frac{4}{6.9}+\frac{4}{9.12}+\frac{4}{12.15}\)

\(=\frac{4}{3}.\left(\frac{3}{3.6}+\frac{3}{6.9}+\frac{3}{9.12}+\frac{3}{12.15}\right)\)

\(=\frac{4}{3}.\left(\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+\frac{1}{12}-\frac{1}{15}\right)\)

\(=\frac{4}{3}.\left(\frac{1}{3}-\frac{1}{15}\right)\)

\(=\frac{4}{3}.\frac{4}{15}=\frac{16}{45}\)

\(A=\frac{4}{3.6}+\frac{4}{6.9}+\frac{4}{9.12}+\frac{4}{12.15}\)

\(=>\frac{3}{4}A=\frac{3}{3.6}+\frac{3}{6.9}+\frac{3}{9.12}+\frac{3}{12.15}\)

\(=>\frac{3}{4}A=\left(\frac{1}{3}-\frac{1}{6}\right)+\left(\frac{1}{6}-\frac{1}{9}\right)+\left(\frac{1}{9}-\frac{1}{12}\right)+\left(\frac{1}{12}-\frac{1}{15}\right)\)

\(=>\frac{3}{4}A=\frac{1}{3}-\frac{1}{15}\)

\(=>\frac{3}{4}A=\frac{4}{15}\)

\(=>A=\frac{4}{15}:\frac{3}{4}\)

\(=>A=\frac{4}{45}\)

nhầm = 16/45

\(\frac{4}{3.6}+\frac{4}{6.9}+\frac{4}{9.12}+\frac{4}{12.15}\)

\(=\frac{4}{3}\left(\frac{3}{3.6}+\frac{3}{6.9}+\frac{3}{9.12}+\frac{3}{12.15}\right)\)

\(=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+\frac{1}{12}-\frac{1}{15}\right)\)

\(=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{15}\right)\)

\(=\frac{4}{3}.\frac{4}{15}=\frac{16}{45}\)

giải:

\(\frac{4}{3x6}\)+\(\frac{4}{6x9}\)+\(\frac{4}{9x12}\)+ \(\frac{4}{12x15}\)

= \(\frac{4}{3}\)x(\(\frac{3}{3x6}\)+ \(\frac{3}{6x9}\)+\(\frac{3}{9x12}\)+\(\frac{3}{12x15}\))

=\(\frac{4}{3}\)x(1-\(\frac{1}{15}\))

=\(\frac{4}{3}\)x\(\frac{14}{15}\)

=\(\frac{56}{45}\)