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Phan An
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Nguyễn Lê Phước Thịnh
23 tháng 9 2021 lúc 21:02

\(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\dfrac{\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(=\dfrac{\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(=\dfrac{\left(5^{16}-1\right)\left(5^{16}+1\right)}{2}\)

\(=\dfrac{5^{32}-1}{2}\)

Minh Hiếu
23 tháng 9 2021 lúc 21:04

\(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{32}+1\right)\)

\(2P\)\(=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)

\(2P=\)\(\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)

\(2P=\left(5^{16}-1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)

\(2P=5^{32}-1\)

\(P=\dfrac{5^{32}-1}{2}\)

 

Cỏ Bốn Lá
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Võ Đông Anh Tuấn
15 tháng 6 2016 lúc 20:14

2p=24(5^2+1)(5^4+1)(5^8+1)(5^16+1)
=(5^2-1)(5^2+1)(5^4+1)(5^8+1)(5^16+1)
=(5^4-1)(5^4+1)(5^8+1)(5^16+1)
=(5^8-1)(5^8+1)(5^16+1)
=(5^16-1)(5^16+1)
=5^32-1
~> p=5^32-1/2

Nguyễn Hoàng Tiến
15 tháng 6 2016 lúc 20:15

\(2P=24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^{16}-1\right)\left(5^{16}+1\right)\)

\(2P=5^{32}-1\)

\(p=\frac{5^{32}-1}{2}\)

Trần Cao Anh Triết
16 tháng 6 2016 lúc 17:48

\(2P=24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^{16}-1\right)\left(5^{16}+1\right)\)

\(2P=5^{32}-1\)

\(p=\frac{5^{32}-1}{2}\)

Trần Vy
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Nguyễn tiến hải
9 tháng 12 2016 lúc 23:04

2p=24(52+1)(54+1)(58+1)(516+1)2p=24(52+1)(54+1)(58+1)(516+1)
=(52−1)(52+1)(54+1)(58+1)(516+1)=(52−1)(52+1)(54+1)(58+1)(516+1)
=(54−1)(54+1)(58+1)(516+1)=(54−1)(54+1)(58+1)(516+1)
=(58−1)(58+1)(516+1)=(58−1)(58+1)(516+1)
=(516−1)(516+1)=(516−1)(516+1)
=532−1 >p=5322

Hoang thi dieu linh
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binh bui
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Trần Phượng
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Vũ Minh Tuấn
19 tháng 8 2020 lúc 18:52

Đặt \(A=12.\left(5^2+1\right).\left(5^4+1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)

\(\Rightarrow2A=24.\left(5^2+1\right).\left(5^4+1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)

     \(2A=\left(5^2-1\right).\left(5^2+1\right).\left(5^4+1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)

     \(2A=\left(5^4-1\right).\left(5^4+1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)

     \(2A=\left(5^8-1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)

     \(2A=\left(5^{16}-1\right).\left(5^{16}+1\right)\)

     \(2A=\left(5^{16}\right)^2-1^2\)

     \(2A=5^{32}-1\)

\(\Rightarrow A=\frac{5^{32}-1}{2}.\)

Khách vãng lai đã xóa
minh anh
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super xity
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Trần Đức Thắng
27 tháng 9 2015 lúc 15:01

2P = 24.(5^2 + 1 )( 5^4 + 1 ) (5^8 +  1 )(5^16 + 1 )

2P = ( 5^2 - 1 )((5^2  + 1 )( 5^4 + 1 ) (5^ 8 + 1 )( 5^ 16 + 1)

2P = ( 5 ^ 4 - 1 )( 5 ^ 4 + 1 ) (5^8 + 1 )(5^16 + 1 )

2P = ( 5 ^8 - 1 )( 5^8 + 1 )( 5^16 + 1)

2P = ( 5 ^16 - 1 )( 5^16 + 1 )

2P = 5^32 - 1 

=> P = \(\frac{5^{32}-1}{2}\)

Trà My
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Đỗ Kiều My
13 tháng 9 2017 lúc 21:01

Nhân cả 2 vế với 2 ta có:

2P=24(52+1)(54+1)(58+1)(516+1)

2P=(52_1)(52+1)(54+1)(58+1)(516+1)

2P=(54_1)(54+1)(58+1)(516+1)

2P=(58_1)(58+1)(516+1)

2P=(516_1)(516+1)

2P=532_1

P=\(\frac{5^{32}-1}{2}\)