Tinh tong
S4=3/50+3/150+3/300+...+3/9500
S5=55/11*16+55/16*21+55/21*26+...+55/36*41
Tinh: 55/11*16+55/16*21+55/21*26+55/26*31+55/31*36+55/36*41
55/11 x 16 + 55/16 x 21 + 55/21 x 26 + 55/26 x 31 + 55/31 x 36 + 55/36 x 41
= 55/11 - 55/16 + 5/16 - 5/21 + 5/21 - 55/26 + 55/26 - 55/31 + 55/31 - 55/36 + 55/36 - 55/41
= 55/11 - 55/41
= 150/41
Mình ko ghi lại đề nha !
= 55 x ( 1/11 x 16 + 1/16 x 21 + 1/21 x 26 + 1/26 x 31 + 1/31 x 36 + 1/36 x 41 )
Vì 1/11 x 16 = 1/1 - 1/11 x 16
=> 1/11 x 21 = 1/231 =1/11 x 16 - 1/16 x 21
....................................................................................
Nếu ta có thể viết :
khúc này viết lại đề bài
= 55 x ( 1/1 - 1/176 + 1/176 -1/336+1/336 - ........................cho đén hết
=55 x ( 1/1 - 1/1476 ) = 55 x 1475/1476 = kết quả tự tính
nhớ
sai rồi kết quả là 30/41 mới đúng
55/11*16 +55/16*21 +55/21*26 +55/26*31+55/31*36 +55/36*41
Lời giải:
Gọi tổng trên là $A$.
$A=11\times (\frac{5}{11\times 16}+\frac{5}{16\times 21}+\frac{5}{21\times 26}+....+\frac{5}{36\times 41})$
$=11\times (\frac{16-11}{11\times 16}+\frac{21-16}{16\times 21}+\frac{26-21}{21\times 26}+....+\frac{41-36}{36\times 41})$
$=11\times (\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+\frac{1}{21}-\frac{1}{26}+...+\frac{1}{36}-\frac{1}{41})$
$=11\times (\frac{1}{11}-\frac{1}{41})=1-\frac{11}{41}=\frac{30}{41}$
55/11*16 + 55/16*21 + 55/21*26 + 55/26*31 + 55/31*36 + 55/36*41
\(\dfrac{55}{11}\cdot6+\dfrac{55}{16}\cdot21+\dfrac{55}{21}\cdot26+\dfrac{55}{26}\cdot31+\dfrac{55}{31}\cdot36+\dfrac{55}{36}\cdot41=30+\dfrac{1155}{16}+\dfrac{1430}{21}+\dfrac{1705}{26}+\dfrac{1980}{31}+\dfrac{2255}{36}=\dfrac{12186720}{406224}+\dfrac{29324295}{406224}+\dfrac{27661920}{406224}+\dfrac{26638920}{406224}+\dfrac{25945920}{406224}+\dfrac{25445420}{406224}=\dfrac{147203195}{406224}\)
A=55/11*16+55/16*21+55/21*26+55/26*31+55/31*36+55/36*41
A=55/11.16+55/16.21+...+55/36.41
A=11x(1/11−1/16+1/16−1/21+...+1/36−1/41)
A=11x(1/11−1/41)
A=11x30/451
A=30/41
tính : A=55/11*16 + 55/16*21 + 55/21*26 + 55/26*31 + 55/31*36 + 55/36*41
A=55*[(1/11*16) * 1/5 + (1/16*21) * 1/5 + (1/21*26) * 1/5 + (1/26*31) * 1/5 + (1/31*36) * 1/5 + (1/36*41) * 1/5 ]
= 55* [ (1/11*16) + (1/16*21) + (1/21*26) + (1/26*31) + (1/31*36) + (1/36*41) ] * 1/5
= 55 * [ 1/11-1/16+1/16-1/21+1/21-1/26+1/26-1/31+1/31-1/36+1/36-1/41) * 1/5
= 55 * ( 1/11 - 1/41 ) * 1/5
= 30/41
Tính tổng sau :
S1 = 3/50 + 3/150 + 3/300 + ...... + 3/9500
S2 = 55/11*16 + 55/16*21 + 55/21*26 + ........ + 55/36*41
Các bạn giúp mik nha . Mik đang vội ( dấu " / " là phân số đó các bạn )
Mình làm rồi /hoi-dap/question/73465.html
Tính:
A=55/11*16+55/16*21+55/21*26+55/26*31+55/31*36+55/36*41
\(A=\frac{55}{11\cdot16}+\frac{55}{16\cdot21}+\frac{55}{21\cdot26}+...+\frac{55}{36\cdot41}\)
\(=\frac{55}{5}\cdot\left(\frac{16-11}{11\cdot16}+\frac{21-16}{16\cdot21}+\frac{26-21}{21\cdot26}+...+\frac{41-36}{36\cdot41}\right)\)
\(=11\cdot\left(\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+\frac{1}{26}-\frac{1}{31}+...+\frac{1}{36}-\frac{1}{41}\right)\)
\(=11\cdot\left(\frac{1}{11}-\frac{1}{41}\right)=11\cdot\frac{41-11}{11\cdot41}=\frac{30}{41}\).
Tính nhanh:
A = 55 / 11. 16
55 / 16. 21
55 / 21. 26
55/ 26.31
55 / 31.36
55 / 36. 41
dấu gạch ngang là phần
dấu chấm là nhân
Đúng ghi Đ sai ghi S
a,(55 + 35):5=55:5+35:5
=11+7
=18
b,(41+22):3=41:3+22:3
= 13 + 7
= 20
c,(55+35):5
=90:5
=18
d,(41+22):3
= 63 : 3
= 21