B=8^20+4^20/4^25+64^5
\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}\)
\(=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=2^{10}=1024\)
8^20+4^20/4^25+64^5
\(=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}\)
8^20+4^20\4^25+64^5
8^20 + 4^20 / 4^25 + 64^5
= 2^60 + 2^40 / 2^50 + 2^30
= 2^40 x (2^20 +1) / 2^30 x (2^20 +1)
= 2^10
= 1024
chúc bạn làm zui zẻ + tốt nhé
Tính :
\(M=\frac{8^{20}+4^{20}}{4^{25}+64^5}\)\(M=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\frac{2^{60}+2^{40}}{2^{50}+2^{30}}=\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}\)
\(M=\frac{8^{20}+4^{20}}{4^{25}+64^5}\)
= \(\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\frac{2^{60}+2^{40}}{2^{50}+2^{30}}=\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}\)
Bài 1 : Tính :
a) 8^20 +4^20
____________ (Đấy là phân số nha)
4^25 +64^5
b) 45^10 .5^20
_____________
75^15.
a: \(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}\)
b: \(\dfrac{45^{10}\cdot5^{20}}{75^{15}}=\dfrac{5^{30}\cdot3^{20}}{3^{15}\cdot5^{30}}=3^5\)
a)\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}=1024\)
b)\(\dfrac{45^{10}\cdot5^{20}}{75^{15}}=\dfrac{9^{10}\cdot5^{30}}{3^{15}\cdot5^{30}}=\dfrac{3^{20}}{3^{15}}=3^5=243\)
8^20+4^20 phần 4^25+64^5 = ?
Tính M=8^20+4^20/4^25+64^5
\(M=\frac{8^{20}+4^{20}}{4^{25}+64^5}\)
\(=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}\)
\(=\frac{2^{60}+2^{40}}{2^{50}+2^{30}}\)
\(=\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}\)
\(=2^{10}=1024\)
#)Giải :
\(M=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\frac{2^{40}.2^{20}+2^{40}.1}{2^{30}.2^{20}+2^{30}.1}=\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=\frac{2^{40}}{2^{30}}=2^{10}=1024\)
Ta có 1 cách đơn giản và easy hơn
\(\frac{4^{20}\left(2^{20}+1\right)}{4^{15}+4^{10}+1}=1024\)
8^20 trừ 4^20 phần 4^25 trừ 64^5 bằng mấy?
\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}\)
ta có : \(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}\)
\(=\dfrac{2^{40}}{2^{30}}=2^{10}=1024\)